{"id":229700,"date":"2025-06-08T11:28:10","date_gmt":"2025-06-08T11:28:10","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=229700"},"modified":"2025-06-08T11:28:12","modified_gmt":"2025-06-08T11:28:12","slug":"question-1-of-10-2-points-what-is-the-approximate-area-of-the-circle-shown-below-a-616-cm","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/08\/question-1-of-10-2-points-what-is-the-approximate-area-of-the-circle-shown-below-a-616-cm\/","title":{"rendered":"Question 1 of 10 2 Points What is the approximate area of the circle shown below? A. 616 cm"},"content":{"rendered":"\n<p>Question 1 of 10 2 Points What is the approximate area of the circle shown below? A. 616 cm<br>B. 154 cm<br>C. 22 cm<br>D. 44 cm<br>14 cm C<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/image-292.png\" alt=\"\" class=\"wp-image-229701\"\/><\/figure>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>To find the <strong>area of the circle<\/strong>, we use the formula:A=\u03c0r2A = \\pi r^2A=\u03c0r2<\/p>\n\n\n\n<p>From the image, the <strong>diameter<\/strong> of the circle is given as <strong>14 cm<\/strong>, which means the <strong>radius (r)<\/strong> is half of the diameter:r=142=7&nbsp;cmr = \\frac{14}{2} = 7 \\text{ cm}r=214\u200b=7&nbsp;cm<\/p>\n\n\n\n<p>Now plug the radius into the area formula:A=\u03c0\u00d772=\u03c0\u00d749\u22483.14\u00d749A = \\pi \\times 7^2 = \\pi \\times 49 \\approx 3.14 \\times 49A=\u03c0\u00d772=\u03c0\u00d749\u22483.14\u00d749A\u2248153.86&nbsp;cm2A \\approx 153.86 \\text{ cm}^2A\u2248153.86&nbsp;cm2<\/p>\n\n\n\n<p>Rounded to the nearest whole number:A\u2248154&nbsp;cm2A \\approx 154 \\text{ cm}^2A\u2248154&nbsp;cm2<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">\u2705 Correct Answer: <strong>B. 154 cm\u00b2<\/strong><\/h3>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation<\/h3>\n\n\n\n<p>The problem asks for the approximate area of a circle with a diameter of 14 cm. To find the area, we must first understand that the area of a circle depends on its <strong>radius<\/strong>, not the diameter. The radius is half the diameter, so in this case, the radius is:Radius=142=7&nbsp;cm\\text{Radius} = \\frac{14}{2} = 7 \\text{ cm}Radius=214\u200b=7&nbsp;cm<\/p>\n\n\n\n<p>Next, we apply the standard formula for the area of a circle:A=\u03c0r2A = \\pi r^2A=\u03c0r2<\/p>\n\n\n\n<p>Substituting the radius into the formula gives:A=\u03c0\u00d772=\u03c0\u00d749A = \\pi \\times 7^2 = \\pi \\times 49A=\u03c0\u00d772=\u03c0\u00d749<\/p>\n\n\n\n<p>Since the problem asks for an approximate area, we use the approximation \u03c0\u22483.14\\pi \\approx 3.14\u03c0\u22483.14:A\u22483.14\u00d749=153.86&nbsp;cm2A \\approx 3.14 \\times 49 = 153.86 \\text{ cm}^2A\u22483.14\u00d749=153.86&nbsp;cm2<\/p>\n\n\n\n<p>This value is approximately <strong>154 cm\u00b2<\/strong>, which matches option <strong>B<\/strong>. The other options are either too small or too large to be correct based on the formula.<\/p>\n\n\n\n<p>Understanding the relationship between the diameter, radius, and area of a circle is crucial in solving such problems. A common mistake is using the diameter directly in the area formula, which would result in an incorrect answer. Always remember that the <strong>radius is the key<\/strong> quantity for calculating the area of a circle.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner7-338.jpeg\" alt=\"\" class=\"wp-image-229702\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Question 1 of 10 2 Points What is the approximate area of the circle shown below? A. 616 cmB. 154 cmC. 22 cmD. 44 cm14 cm C The Correct Answer and Explanation is: To find the area of the circle, we use the formula:A=\u03c0r2A = \\pi r^2A=\u03c0r2 From the image, the diameter of the circle [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-229700","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/229700","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=229700"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/229700\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=229700"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=229700"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=229700"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}