{"id":230693,"date":"2025-06-09T20:24:14","date_gmt":"2025-06-09T20:24:14","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=230693"},"modified":"2025-06-09T20:24:15","modified_gmt":"2025-06-09T20:24:15","slug":"for-zero-order-reaction-a-%e2%86%92-a-graph-of-rate-vs-time-has-slope-equal-to-where-k-rate-of-reaction","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/09\/for-zero-order-reaction-a-%e2%86%92-a-graph-of-rate-vs-time-has-slope-equal-to-where-k-rate-of-reaction\/","title":{"rendered":"For zero order reaction, A \u2192 ,a graph of rate vs time has slope equal to:( where k = rate of reaction)"},"content":{"rendered":"\n

For zero order reaction, A \u2192 ,a graph of rate vs time has slope equal to:( where k = rate of reaction) A. k B. – k C. zero D. – 2.303 k<\/p>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

ChatGPT said:<\/h6>\n\n\n\n

Correct Answer: C. Zero<\/strong><\/h3>\n\n\n\n

Explanation<\/h3>\n\n\n\n

In a zero-order reaction<\/strong>, the rate of reaction is independent of the concentration<\/strong> of the reactant. This means the rate remains constant throughout the reaction as long as some reactant is still present.<\/p>\n\n\n\n

The general form of a zero-order reaction is:A\u2192Products\\text{A} \\rightarrow \\text{Products}A\u2192Products<\/p>\n\n\n\n

For a zero-order reaction, the rate law<\/strong> is:Rate=\u2212d[A]dt=k\\text{Rate} = -\\frac{d[\\text{A}]}{dt} = kRate=\u2212dtd[A]\u200b=k<\/p>\n\n\n\n

Here, kkk is the rate constant<\/strong>, and the negative sign indicates the concentration of A is decreasing.<\/p>\n\n\n\n

Now, if we graph rate vs. time<\/strong> for a zero-order reaction:<\/p>\n\n\n\n

    \n
  • The rate =k= k=k, which is a constant<\/strong>.<\/li>\n\n\n\n
  • This means no matter how much time passes, the rate doesn’t change as long as A is present.<\/li>\n<\/ul>\n\n\n\n

    So, plotting rate on the y-axis<\/strong> and time on the x-axis<\/strong> results in a horizontal line<\/strong>. A horizontal line has a slope of zero<\/strong>.<\/p>\n\n\n\n

    Therefore, the slope of the rate vs. time graph is zero<\/strong>, which corresponds to:C. Zero\\boxed{\\text{C. Zero}}C. Zero\u200b<\/p>\n\n\n\n

    \n\n\n\n

    Additional Context:<\/h3>\n\n\n\n
      \n
    • For zero-order reactions, the integrated rate law is: [A]=[A]0\u2212kt[A] = [A]_0 – kt[A]=[A]0\u200b\u2212kt This tells us how the concentration of A decreases linearly with time.<\/li>\n\n\n\n
    • However, the rate itself does not change<\/strong>, because it’s not dependent on [A].<\/li>\n\n\n\n
    • This behavior is typical in reactions where a catalyst surface becomes saturated or in enzyme kinetics under conditions of maximum saturation.<\/li>\n\n\n\n
    • In contrast:\n
        \n
      • First-order reactions<\/strong> have rates that decrease exponentially over time.<\/li>\n\n\n\n
      • Second-order reactions<\/strong> show even faster decreases in rate with time.<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n

        But in zero-order<\/strong>, the unchanging rate gives a flat line in a rate vs. time plot \u2014 hence a slope of zero<\/strong>.<\/p>\n\n\n\n

        \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

        For zero order reaction, A \u2192 ,a graph of rate vs time has slope equal to:( where k = rate of reaction) A. k B. – k C. zero D. – 2.303 k The Correct Answer and Explanation is: ChatGPT said: Correct Answer: C. Zero Explanation In a zero-order reaction, the rate of reaction is […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-230693","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/230693","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=230693"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/230693\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=230693"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=230693"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=230693"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}