{"id":230891,"date":"2025-06-10T07:43:25","date_gmt":"2025-06-10T07:43:25","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=230891"},"modified":"2025-06-10T07:43:27","modified_gmt":"2025-06-10T07:43:27","slug":"write-down-the-electronic-configuration-of-al3-how-many-electrons-are-present-in-its-outer-most-shell","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/10\/write-down-the-electronic-configuration-of-al3-how-many-electrons-are-present-in-its-outer-most-shell\/","title":{"rendered":"Write down the electronic configuration of al3+ how many electrons are present in its outer most shell"},"content":{"rendered":"\n<p>Write down the electronic configuration of al3+ how many electrons are present in its outer most shell<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Electronic Configuration of Al\u00b3\u207a<\/strong><\/h3>\n\n\n\n<p>The element <strong>Aluminium (Al)<\/strong> has an atomic number of <strong>13<\/strong>, which means a neutral aluminium atom has <strong>13 electrons<\/strong>.<br>The electronic configuration of a neutral Al atom is:<\/p>\n\n\n\n<p><strong>Al (Z = 13): 1s\u00b2 2s\u00b2 2p\u2076 3s\u00b2 3p\u00b9<\/strong><\/p>\n\n\n\n<p>When Aluminium loses <strong>three electrons<\/strong> to form an <strong>Al\u00b3\u207a ion<\/strong>, the electrons are removed from the <strong>outermost shell<\/strong> (the 3rd shell).<\/p>\n\n\n\n<p>So, we remove:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>First: 3p\u00b9<\/li>\n\n\n\n<li>Second: 3s\u00b2<\/li>\n<\/ul>\n\n\n\n<p>After removing three electrons, the configuration becomes:<\/p>\n\n\n\n<p><strong>Al\u00b3\u207a: 1s\u00b2 2s\u00b2 2p\u2076<\/strong><\/p>\n\n\n\n<p>This is the same configuration as the <strong>noble gas Neon (Ne)<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>How many electrons are present in the outermost shell of Al\u00b3\u207a?<\/strong><\/h3>\n\n\n\n<p>The outermost shell in <strong>Al\u00b3\u207a<\/strong> is the <strong>second shell<\/strong> (n = 2), which consists of:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>2s\u00b2<\/li>\n\n\n\n<li>2p\u2076<\/li>\n<\/ul>\n\n\n\n<p>Total electrons in the outermost shell = <strong>2 + 6 = 8 electrons<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation <\/strong><\/h3>\n\n\n\n<p>Aluminium (Al) is a group 13 element with an atomic number of 13. This means it has 13 protons and, in a neutral state, 13 electrons. The arrangement of these electrons in shells and subshells is known as the electronic configuration. For a neutral Al atom, the electrons fill the orbitals in the order of increasing energy: 1s, 2s, 2p, 3s, and 3p. Thus, its configuration is <strong>1s\u00b2 2s\u00b2 2p\u2076 3s\u00b2 3p\u00b9<\/strong>.<\/p>\n\n\n\n<p>When aluminium becomes an ion, it typically forms a <strong>+3 charge (Al\u00b3\u207a)<\/strong> by <strong>losing three electrons<\/strong>. This happens because aluminium has three valence electrons (3s\u00b2 3p\u00b9), which are relatively easy to remove to achieve a stable electronic structure. Losing these three electrons gives it the configuration of <strong>1s\u00b2 2s\u00b2 2p\u2076<\/strong>, which is the same as the noble gas <strong>Neon<\/strong>, making it stable.<\/p>\n\n\n\n<p>In the case of Al\u00b3\u207a, all electrons from the third shell are lost, so its outermost shell becomes the second shell. The second shell now contains <strong>eight electrons<\/strong> (2s\u00b2 2p\u2076), which is a full shell and very stable \u2014 this is known as an <strong>octet<\/strong>.<\/p>\n\n\n\n<p>Therefore, in Al\u00b3\u207a:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Total electrons<\/strong> = 10<\/li>\n\n\n\n<li><strong>Outermost shell (n=2)<\/strong> electrons = <strong>8<\/strong><\/li>\n<\/ul>\n\n\n\n<p>This loss of electrons and resulting stability explains why aluminium commonly forms the +3 ion. The noble gas configuration in Al\u00b3\u207a is highly stable and helps to minimize energy, which is why this ionic form is so prevalent in chemical compounds.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner4-814.jpeg\" alt=\"\" class=\"wp-image-230892\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Write down the electronic configuration of al3+ how many electrons are present in its outer most shell The Correct Answer and Explanation is: Electronic Configuration of Al\u00b3\u207a The element Aluminium (Al) has an atomic number of 13, which means a neutral aluminium atom has 13 electrons.The electronic configuration of a neutral Al atom is: Al [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-230891","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/230891","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=230891"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/230891\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=230891"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=230891"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=230891"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}