{"id":231017,"date":"2025-06-10T11:14:19","date_gmt":"2025-06-10T11:14:19","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=231017"},"modified":"2025-06-10T11:14:22","modified_gmt":"2025-06-10T11:14:22","slug":"hydrogen-sulfide-gas-is-bubbled-through-an-excess-of-potassium-hydroxide-solution-2","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/10\/hydrogen-sulfide-gas-is-bubbled-through-an-excess-of-potassium-hydroxide-solution-2\/","title":{"rendered":"Hydrogen sulfide gas is bubbled through an excess of potassium hydroxide solution."},"content":{"rendered":"\n<p>Hydrogen sulfide gas is bubbled through an excess of potassium hydroxide solution. H2S + 2OH- \u00e2\u2020\u2019 S2- + 2H2O Write the balanced chemical equation excluding spectator ions. How do you get there from H2S + KOH -> K2S + H2O?<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The correct balanced chemical equation, excluding spectator ions, for the reaction of hydrogen sulfide (H\u2082S) with an excess of potassium hydroxide (KOH) is:<\/p>\n\n\n\n<p><strong>H\u2082S + 2OH\u207b \u2192 S\u00b2\u207b + 2H\u2082O<\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<ol start=\"1\" class=\"wp-block-list\">\n<li><strong>Understanding the Reactants:<\/strong>\n<ul class=\"wp-block-list\">\n<li>Hydrogen sulfide (H\u2082S) is a weak diprotic acid.<\/li>\n\n\n\n<li>Potassium hydroxide (KOH) is a strong base that dissociates completely in aqueous solution into potassium ions (K\u207a) and hydroxide ions (OH\u207b).<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Ionic Perspective of KOH:<\/strong>\n<ul class=\"wp-block-list\">\n<li>Since KOH is a strong electrolyte, it fully dissociates in solution:<\/li>\n<\/ul>\n<\/li>\n<\/ol>\n\n\n\n<p>KOH\u2192K++OH\u2212KOH \\rightarrow K\u207a + OH\u207b<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>When KOH is in excess, it provides a surplus of hydroxide ions.<\/li>\n<\/ul>\n\n\n\n<ol start=\"3\" class=\"wp-block-list\">\n<li><strong>Acid-Base Neutralization:<\/strong>\n<ul class=\"wp-block-list\">\n<li>H\u2082S releases hydrogen ions (H\u207a) in two steps due to its diprotic nature:<\/li>\n<\/ul>\n<\/li>\n<\/ol>\n\n\n\n<p>H2S\u21ccHS\u2212+H+H\u2082S \\rightleftharpoons HS\u207b + H\u207a<\/p>\n\n\n\n<p>HS\u2212\u21ccS2\u2212+H+HS\u207b \\rightleftharpoons S\u00b2\u207b + H\u207a<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The hydroxide ions (OH\u207b) neutralize these hydrogen ions, forming water:<\/li>\n<\/ul>\n\n\n\n<p>H++OH\u2212\u2192H2OH\u207a + OH\u207b \\rightarrow H\u2082O<\/p>\n\n\n\n<ol start=\"4\" class=\"wp-block-list\">\n<li><strong>Formation of Sulfide Ion:<\/strong>\n<ul class=\"wp-block-list\">\n<li>With an excess of OH\u207b, both H\u207a ions from H\u2082S are neutralized, leading to the formation of the sulfide ion (S\u00b2\u207b):<\/li>\n<\/ul>\n<\/li>\n<\/ol>\n\n\n\n<p>H2S+2OH\u2212\u2192S2\u2212+2H2OH\u2082S + 2OH\u207b \\rightarrow S\u00b2\u207b + 2H\u2082O<\/p>\n\n\n\n<ol start=\"5\" class=\"wp-block-list\">\n<li><strong>Comparison with K\u2082S Formation:<\/strong>\n<ul class=\"wp-block-list\">\n<li>The reaction <strong>H\u2082S + KOH \u2192 K\u2082S + H\u2082O<\/strong> suggests the formation of potassium sulfide (K\u2082S).<\/li>\n\n\n\n<li>However, when written in ionic form, <strong>K\u2082S dissociates into K\u207a and S\u00b2\u207b<\/strong>, making K\u207a a spectator ion.<\/li>\n\n\n\n<li>Removing spectator ions from the equation results in:<\/li>\n<\/ul>\n<\/li>\n<\/ol>\n\n\n\n<p>H2S+2OH\u2212\u2192S2\u2212+2H2OH\u2082S + 2OH\u207b \\rightarrow S\u00b2\u207b + 2H\u2082O<\/p>\n\n\n\n<p>Thus, the simplified balanced equation represents the core reaction, excluding irrelevant spectator ions.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner4-843.jpeg\" alt=\"\" class=\"wp-image-231019\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Hydrogen sulfide gas is bubbled through an excess of potassium hydroxide solution. H2S + 2OH- \u00e2\u2020\u2019 S2- + 2H2O Write the balanced chemical equation excluding spectator ions. How do you get there from H2S + KOH -> K2S + H2O? The correct Answer and Explanation is: The correct balanced chemical equation, excluding spectator ions, for [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-231017","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/231017","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=231017"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/231017\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=231017"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=231017"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=231017"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}