{"id":231778,"date":"2025-06-11T11:30:10","date_gmt":"2025-06-11T11:30:10","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=231778"},"modified":"2025-06-11T11:30:12","modified_gmt":"2025-06-11T11:30:12","slug":"how-many-moles-would-be-represented-by-25-0-g-of-neon","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/11\/how-many-moles-would-be-represented-by-25-0-g-of-neon\/","title":{"rendered":"How many moles would be represented by 25.0 g of neon"},"content":{"rendered":"\n<p>How many moles would be represented by 25.0 g of neon (Ne)?<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-0-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>Let\u2019s calculate how many moles are in 25.0 g of neon (Ne).<\/p>\n\n\n\n<p>We use the formula: moles=mass&nbsp;(g)molar&nbsp;mass&nbsp;(g\/mol)\\text{moles} = \\frac{\\text{mass (g)}}{\\text{molar mass (g\/mol)}}moles=molar&nbsp;mass&nbsp;(g\/mol)mass&nbsp;(g)\u200b<\/p>\n\n\n\n<p>The molar mass of neon (Ne) is approximately <strong>20.18 g\/mol<\/strong>.<\/p>\n\n\n\n<p>Now substitute: moles=25.0&nbsp;g20.18&nbsp;g\/mol\\text{moles} = \\frac{25.0\\ \\text{g}}{20.18\\ \\text{g\/mol}}moles=20.18&nbsp;g\/mol25.0&nbsp;g\u200b moles\u22481.239&nbsp;mol\\text{moles} \\approx 1.239\\ \\text{mol}moles\u22481.239&nbsp;mol<\/p>\n\n\n\n<p><strong>Answer:<\/strong><br>25.0 g of neon represents approximately <strong>1.24 moles<\/strong> (rounded to 3 significant figures).<\/p>\n\n\n\n<p><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner4-969.jpeg\" alt=\"\" class=\"wp-image-231779\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>How many moles would be represented by 25.0 g of neon (Ne)? The Correct Answer and Explanation is: Let\u2019s calculate how many moles are in 25.0 g of neon (Ne). We use the formula: moles=mass&nbsp;(g)molar&nbsp;mass&nbsp;(g\/mol)\\text{moles} = \\frac{\\text{mass (g)}}{\\text{molar mass (g\/mol)}}moles=molar&nbsp;mass&nbsp;(g\/mol)mass&nbsp;(g)\u200b The molar mass of neon (Ne) is approximately 20.18 g\/mol. Now substitute: moles=25.0&nbsp;g20.18&nbsp;g\/mol\\text{moles} = \\frac{25.0\\ [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-231778","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/231778","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=231778"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/231778\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=231778"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=231778"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=231778"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}