{"id":231875,"date":"2025-06-11T12:48:53","date_gmt":"2025-06-11T12:48:53","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=231875"},"modified":"2025-06-11T12:48:55","modified_gmt":"2025-06-11T12:48:55","slug":"provided-here-is-an-unbalanced-chemical-equation","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/11\/provided-here-is-an-unbalanced-chemical-equation\/","title":{"rendered":"Provided here is an unbalanced chemical equation."},"content":{"rendered":"\n<p>Provided here is an unbalanced chemical equation. CuCl<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Na<br>PO<br>? Cu<br>(PO<br>)<\/li>\n\n\n\n<li>NaCl Which of the following shows the product side of the correctly balanced equation? ?4Cu<br>(PO<br>)<\/li>\n\n\n\n<li>2NaCl ?2Cu<br>(PO<br>)<\/li>\n\n\n\n<li>3NaCl ?Cu<br>(PO<br>)<\/li>\n\n\n\n<li>6NaCl ?3Cu<br>(PO<br>)<\/li>\n\n\n\n<li>NaCl<\/li>\n<\/ul>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p><strong>Given unbalanced equation:<\/strong> CuCl+Na3PO4\u2192Cu3(PO4)2+NaCl\\text{CuCl} + \\text{Na}_3\\text{PO}_4 \\rightarrow \\text{Cu}_3(\\text{PO}_4)_2 + \\text{NaCl}CuCl+Na3\u200bPO4\u200b\u2192Cu3\u200b(PO4\u200b)2\u200b+NaCl<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Balancing the equation:<\/h3>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Identify reactants and products:<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Reactants: Copper(I) chloride (CuCl), Sodium phosphate (Na\u2083PO\u2084)<\/li>\n\n\n\n<li>Products: Copper(II) phosphate (Cu\u2083(PO\u2084)\u2082), Sodium chloride (NaCl)<\/li>\n<\/ul>\n\n\n\n<ol start=\"2\" class=\"wp-block-list\">\n<li><strong>Balance copper (Cu):<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>On product side: Cu3(PO4)2\\text{Cu}_3(\\text{PO}_4)_2Cu3\u200b(PO4\u200b)2\u200b contains 3 Cu atoms.<\/li>\n\n\n\n<li>On reactant side: We need 3 CuCl to provide 3 Cu atoms.<\/li>\n<\/ul>\n\n\n\n<p>3CuCl+Na3PO4\u2192Cu3(PO4)2+NaCl3\\text{CuCl} + \\text{Na}_3\\text{PO}_4 \\rightarrow \\text{Cu}_3(\\text{PO}_4)_2 + \\text{NaCl}3CuCl+Na3\u200bPO4\u200b\u2192Cu3\u200b(PO4\u200b)2\u200b+NaCl<\/p>\n\n\n\n<ol start=\"3\" class=\"wp-block-list\">\n<li><strong>Balance sodium (Na):<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Na3PO4\\text{Na}_3\\text{PO}_4Na3\u200bPO4\u200b has 3 Na atoms.<\/li>\n\n\n\n<li>On the product side, we need 3 NaCl to balance Na.<\/li>\n<\/ul>\n\n\n\n<p>3CuCl+Na3PO4\u2192Cu3(PO4)2+3NaCl3\\text{CuCl} + \\text{Na}_3\\text{PO}_4 \\rightarrow \\text{Cu}_3(\\text{PO}_4)_2 + 3\\text{NaCl}3CuCl+Na3\u200bPO4\u200b\u2192Cu3\u200b(PO4\u200b)2\u200b+3NaCl<\/p>\n\n\n\n<ol start=\"4\" class=\"wp-block-list\">\n<li><strong>Check phosphorus (P) and chlorine (Cl):<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Phosphorus is already balanced (1 phosphate group on both sides).<\/li>\n\n\n\n<li>Chlorine: 3 Cl on both sides.<\/li>\n<\/ul>\n\n\n\n<p>The final balanced equation is: 3CuCl+Na3PO4\u2192Cu3(PO4)2+3NaCl3\\text{CuCl} + \\text{Na}_3\\text{PO}_4 \\rightarrow \\text{Cu}_3(\\text{PO}_4)_2 + 3\\text{NaCl}3CuCl+Na3\u200bPO4\u200b\u2192Cu3\u200b(PO4\u200b)2\u200b+3NaCl<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>Correct product side:<\/strong><br>Cu3(PO4)2+3NaCl\\text{Cu}_3(\\text{PO}_4)_2 + 3\\text{NaCl}Cu3\u200b(PO4\u200b)2\u200b+3NaCl<\/p>\n\n\n\n<p>From the options provided, the correct answer is:<\/p>\n\n\n\n<p><strong>3Cu(PO\u2084)\u2082 + NaCl<\/strong><\/p>\n\n\n\n<p>\u2192 This is incorrect formatting. The correct answer according to options should be:<\/p>\n\n\n\n<p><strong>Cu\u2083(PO\u2084)\u2082 + 3NaCl<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Textbook-style explanation<\/h3>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>Balancing Chemical Reactions: An Example with Copper(I) Chloride and Sodium Phosphate<\/strong><\/p>\n\n\n\n<p>In chemical reactions, the law of conservation of mass states that matter cannot be created or destroyed. Therefore, the number of atoms for each element must be the same on both the reactant and product sides of a chemical equation. Let us apply this principle to balance the given reaction:<\/p>\n\n\n\n<p>Unbalanced equation: CuCl+Na3PO4\u2192Cu3(PO4)2+NaCl\\text{CuCl} + \\text{Na}_3\\text{PO}_4 \\rightarrow \\text{Cu}_3(\\text{PO}_4)_2 + \\text{NaCl}CuCl+Na3\u200bPO4\u200b\u2192Cu3\u200b(PO4\u200b)2\u200b+NaCl<\/p>\n\n\n\n<p>First, examine the copper atoms. The product Cu3(PO4)2\\text{Cu}_3(\\text{PO}_4)_2Cu3\u200b(PO4\u200b)2\u200b contains 3 copper atoms. To balance this, place the coefficient 3 before CuCl: 3CuCl+Na3PO4\u2192Cu3(PO4)2+NaCl3\\text{CuCl} + \\text{Na}_3\\text{PO}_4 \\rightarrow \\text{Cu}_3(\\text{PO}_4)_2 + \\text{NaCl}3CuCl+Na3\u200bPO4\u200b\u2192Cu3\u200b(PO4\u200b)2\u200b+NaCl<\/p>\n\n\n\n<p>Next, balance the sodium atoms. Sodium phosphate (Na3PO4\\text{Na}_3\\text{PO}_4Na3\u200bPO4\u200b) contains 3 sodium atoms. Therefore, place a coefficient of 3 before NaCl to ensure the sodium atoms are balanced: 3CuCl+Na3PO4\u2192Cu3(PO4)2+3NaCl3\\text{CuCl} + \\text{Na}_3\\text{PO}_4 \\rightarrow \\text{Cu}_3(\\text{PO}_4)_2 + 3\\text{NaCl}3CuCl+Na3\u200bPO4\u200b\u2192Cu3\u200b(PO4\u200b)2\u200b+3NaCl<\/p>\n\n\n\n<p>Upon verification, phosphorus and chlorine atoms are also balanced. Each side contains 1 phosphate group and 3 chlorine atoms.<\/p>\n\n\n\n<p>Thus, the correctly balanced equation is: 3CuCl+Na3PO4\u2192Cu3(PO4)2+3NaCl3\\text{CuCl} + \\text{Na}_3\\text{PO}_4 \\rightarrow \\text{Cu}_3(\\text{PO}_4)_2 + 3\\text{NaCl}3CuCl+Na3\u200bPO4\u200b\u2192Cu3\u200b(PO4\u200b)2\u200b+3NaCl<\/p>\n\n\n\n<p>The correctly balanced product side is: Cu3(PO4)2+3NaCl\\text{Cu}_3(\\text{PO}_4)_2 + 3\\text{NaCl}Cu3\u200b(PO4\u200b)2\u200b+3NaCl<\/p>\n\n\n\n<p>This ensures the conservation of mass and confirms the reaction is properly balanced.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner4-994.jpeg\" alt=\"\" class=\"wp-image-231876\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Provided here is an unbalanced chemical equation. CuCl The Correct Answer and Explanation is: Given unbalanced equation: CuCl+Na3PO4\u2192Cu3(PO4)2+NaCl\\text{CuCl} + \\text{Na}_3\\text{PO}_4 \\rightarrow \\text{Cu}_3(\\text{PO}_4)_2 + \\text{NaCl}CuCl+Na3\u200bPO4\u200b\u2192Cu3\u200b(PO4\u200b)2\u200b+NaCl Balancing the equation: 3CuCl+Na3PO4\u2192Cu3(PO4)2+NaCl3\\text{CuCl} + \\text{Na}_3\\text{PO}_4 \\rightarrow \\text{Cu}_3(\\text{PO}_4)_2 + \\text{NaCl}3CuCl+Na3\u200bPO4\u200b\u2192Cu3\u200b(PO4\u200b)2\u200b+NaCl 3CuCl+Na3PO4\u2192Cu3(PO4)2+3NaCl3\\text{CuCl} + \\text{Na}_3\\text{PO}_4 \\rightarrow \\text{Cu}_3(\\text{PO}_4)_2 + 3\\text{NaCl}3CuCl+Na3\u200bPO4\u200b\u2192Cu3\u200b(PO4\u200b)2\u200b+3NaCl The final balanced equation is: 3CuCl+Na3PO4\u2192Cu3(PO4)2+3NaCl3\\text{CuCl} + \\text{Na}_3\\text{PO}_4 \\rightarrow \\text{Cu}_3(\\text{PO}_4)_2 + 3\\text{NaCl}3CuCl+Na3\u200bPO4\u200b\u2192Cu3\u200b(PO4\u200b)2\u200b+3NaCl Correct product [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center 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