{"id":231957,"date":"2025-06-11T15:05:54","date_gmt":"2025-06-11T15:05:54","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=231957"},"modified":"2025-06-11T15:05:56","modified_gmt":"2025-06-11T15:05:56","slug":"which-is-a-correct-lewis-structure-for-cs2","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/11\/which-is-a-correct-lewis-structure-for-cs2\/","title":{"rendered":"Which is a correct Lewis Structure for CS2"},"content":{"rendered":"\n<p> Which is a correct Lewis Structure for CS2? A. S=C=S B. C-S=S C. C=S=S D. C\u00e2\u2030\u00a1C E. S=C=S<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The correct Lewis structure for <strong>carbon disulfide (CS\u2082)<\/strong> is:<\/p>\n\n\n\n<p><strong>A. S=C=S<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>Carbon disulfide (CS\u2082) is a linear molecule composed of one carbon atom and two sulfur atoms. To determine the correct Lewis structure, we follow a systematic approach:<\/p>\n\n\n\n<h4 class=\"wp-block-heading\">1. <strong>Count Total Valence Electrons:<\/strong><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Carbon (C) has 4 valence electrons.<\/li>\n\n\n\n<li>Each sulfur (S) has 6 valence electrons.<\/li>\n\n\n\n<li>Total: 4 + 6\u00d72 = <strong>16 valence electrons<\/strong><\/li>\n<\/ul>\n\n\n\n<h4 class=\"wp-block-heading\">2. <strong>Determine the Central Atom:<\/strong><\/h4>\n\n\n\n<p>Carbon is less electronegative than sulfur, so carbon becomes the central atom, flanked by the two sulfur atoms.<\/p>\n\n\n\n<h4 class=\"wp-block-heading\">3. <strong>Form Initial Bonds:<\/strong><\/h4>\n\n\n\n<p>Draw single bonds between the carbon and each sulfur:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>S\u2013C\u2013S<\/li>\n<\/ul>\n\n\n\n<p>This uses 2 bonds = 4 electrons, leaving 12 electrons to distribute.<\/p>\n\n\n\n<h4 class=\"wp-block-heading\">4. <strong>Complete Octets:<\/strong><\/h4>\n\n\n\n<p>Place 6 electrons (three lone pairs) on each sulfur atom:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>This uses up all 12 remaining electrons.<\/li>\n<\/ul>\n\n\n\n<p>However, this structure gives carbon only 4 electrons, which is not enough to complete its octet. To fix this, create double bonds between carbon and each sulfur:<\/p>\n\n\n\n<p><strong>S=C=S<\/strong><\/p>\n\n\n\n<p>This structure:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Has 4 electrons (two bonds) between C and each S<\/li>\n\n\n\n<li>Gives carbon 8 electrons (full octet)<\/li>\n\n\n\n<li>Gives each sulfur 8 electrons (2 bonding + 2 lone pairs)<\/li>\n<\/ul>\n\n\n\n<h4 class=\"wp-block-heading\">5. <strong>Check Formal Charges:<\/strong><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Carbon: 4 valence \u2212 0 lone pairs \u2212 4 bonds = 0<\/li>\n\n\n\n<li>Sulfur: 6 valence \u2212 4 lone electrons \u2212 2 bonds = 0<\/li>\n<\/ul>\n\n\n\n<p>All atoms have formal charges of zero, indicating a stable structure.<\/p>\n\n\n\n<h4 class=\"wp-block-heading\">6. <strong>Geometry:<\/strong><\/h4>\n\n\n\n<p>The molecule is <strong>linear<\/strong>, with bond angles of 180\u00b0, due to the arrangement of electron domains around the central carbon.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Final Answer:<\/h3>\n\n\n\n<p><strong>A. S=C=S<\/strong> is the correct Lewis structure for CS\u2082.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner9-236.jpeg\" alt=\"\" class=\"wp-image-231958\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Which is a correct Lewis Structure for CS2? A. S=C=S B. C-S=S C. C=S=S D. C\u00e2\u2030\u00a1C E. S=C=S The Correct Answer and Explanation is: The correct Lewis structure for carbon disulfide (CS\u2082) is: A. S=C=S Explanation: Carbon disulfide (CS\u2082) is a linear molecule composed of one carbon atom and two sulfur atoms. To determine the [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-231957","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/231957","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=231957"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/231957\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=231957"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=231957"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=231957"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}