{"id":232082,"date":"2025-06-11T16:58:34","date_gmt":"2025-06-11T16:58:34","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=232082"},"modified":"2025-06-11T16:58:36","modified_gmt":"2025-06-11T16:58:36","slug":"referring-to-the-most-stable-lewis-dot-structure-of-i-1-3","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/11\/referring-to-the-most-stable-lewis-dot-structure-of-i-1-3\/","title":{"rendered":"Referring to the most stable Lewis dot structure of I 1\/3"},"content":{"rendered":"\n

Referring to the most stable Lewis dot structure of I 1\/3
, what is the hybridization of the central atom? a. sp
b. sp
c. sp d. sp
d<\/p>\n\n\n\n

\"\"<\/figure>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

Correct Answer:<\/strong> b. sp\u00b3<\/p>\n\n\n\n

Explanation:<\/h3>\n\n\n\n

To determine the hybridization of the central atom in the triiodine cation (I\u2083\u207a), we must first draw its most stable Lewis dot structure and then apply the Valence Shell Electron Pair Repulsion (VSEPR) theory.<\/p>\n\n\n\n

Step 1: Calculate the total number of valence electrons.<\/strong>
Iodine (I) is in Group 17 of the periodic table, so each iodine atom has 7 valence electrons.<\/p>\n\n\n\n

    \n
  • Total valence electrons from 3 iodine atoms = 3 \u00d7 7 = 21<\/li>\n\n\n\n
  • The ion has a +1 charge, which means one electron has been removed.<\/li>\n\n\n\n
  • Total valence electrons for I\u2083\u207a = 21 – 1 = 20 electrons.<\/li>\n<\/ul>\n\n\n\n

    Step 2: Draw the Lewis structure.<\/strong><\/p>\n\n\n\n

      \n
    1. Arrange the atoms with one iodine atom in the center, bonded to the other two: I \u2014 I \u2014 I. This skeletal structure uses 2 bonds, which account for 4 electrons.<\/li>\n\n\n\n
    2. Distribute the remaining electrons (20 – 4 = 16) to the terminal atoms first to satisfy their octets. Each terminal iodine atom needs 6 more electrons (3 lone pairs). This uses 2 \u00d7 6 = 12 electrons.<\/li>\n\n\n\n
    3. Place the remaining electrons (16 – 12 = 4) on the central iodine atom. These 4 electrons form 2 lone pairs.<\/li>\n<\/ol>\n\n\n\n

      The resulting Lewis structure is:
      [ :\u00cf\u2014\u00cf\u2014\u00cf: ]\u207a
      Where the central iodine has two lone pairs and the terminal iodines each have three lone pairs. The formal charge on the central iodine is +1, while the terminal iodines have a formal charge of 0, correctly summing to the overall +1 charge of the ion.<\/p>\n\n\n\n

      Step 3: Determine the hybridization.<\/strong>
      The hybridization of the central atom is determined by its steric number, which is the total number of electron domains (bonding pairs + lone pairs) around it.<\/p>\n\n\n\n

        \n
      • Number of atoms bonded to the central atom (bonding domains) = 2<\/li>\n\n\n\n
      • Number of lone pairs on the central atom = 2<\/li>\n\n\n\n
      • Steric Number = 2 (bonding pairs) + 2 (lone pairs) = 4<\/li>\n<\/ul>\n\n\n\n

        A steric number of 4 indicates that the central atom uses four hybrid orbitals to accommodate its electron domains. These orbitals are formed by mixing one s<\/em> orbital and three p<\/em> orbitals, resulting in sp\u00b3 hybridization<\/strong>. The electron geometry around the central atom is tetrahedral, though the molecular geometry is bent or V-shaped due to the presence of the two lone pairs.<\/p>\n\n\n\n

        \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

        Referring to the most stable Lewis dot structure of I 1\/3, what is the hybridization of the central atom? a. spb. spc. sp d. spd The Correct Answer and Explanation is: Correct Answer: b. sp\u00b3 Explanation: To determine the hybridization of the central atom in the triiodine cation (I\u2083\u207a), we must first draw its most stable […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-232082","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/232082","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=232082"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/232082\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=232082"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=232082"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=232082"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}