{"id":232158,"date":"2025-06-11T18:42:14","date_gmt":"2025-06-11T18:42:14","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=232158"},"modified":"2025-06-11T18:42:27","modified_gmt":"2025-06-11T18:42:27","slug":"write-the-name-of-the-k2co3","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/11\/write-the-name-of-the-k2co3\/","title":{"rendered":"Write the name of the K2CO3"},"content":{"rendered":"\n<p>Solve 1. Write the name of the K2<br>CO3<br>compound and deduce its molecular mass. C(12), O(16)<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p><strong>Answer:<\/strong><\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Name of the compound: Potassium Carbonate<\/strong><br><strong>Chemical Formula: K\u2082CO\u2083<\/strong><\/li>\n<\/ol>\n\n\n\n<p><strong>Molecular Mass Calculation:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Potassium (K): 39 \u00d7 2 = 78<\/li>\n\n\n\n<li>Carbon (C): 12 \u00d7 1 = 12<\/li>\n\n\n\n<li>Oxygen (O): 16 \u00d7 3 = 48<br><strong>Total Molecular Mass = 78 + 12 + 48 = 138 g\/mol<\/strong><\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation<\/strong><\/h3>\n\n\n\n<p>Potassium carbonate is an inorganic compound with the chemical formula <strong>K\u2082CO\u2083<\/strong>. It is composed of two potassium ions (K\u207a) and one carbonate ion (CO\u2083\u00b2\u207b). The carbonate ion is a polyatomic ion consisting of one carbon atom covalently bonded to three oxygen atoms. One of the oxygen atoms forms a double bond with the carbon, while the other two carry a negative charge each and are bonded via single bonds, forming a resonance-stabilized ion. This negative charge is balanced by the two positively charged potassium ions, resulting in a neutral compound overall.<\/p>\n\n\n\n<p>The nomenclature of potassium carbonate follows the standard IUPAC naming system. &#8220;Potassium&#8221; refers to the cation K\u207a, while &#8220;carbonate&#8221; refers to the anion CO\u2083\u00b2\u207b. Since potassium is a Group 1 alkali metal and has a fixed +1 oxidation state, and carbonate is a common polyatomic anion with a \u22122 charge, the chemical formula must contain <strong>two<\/strong> potassium ions for every <strong>one<\/strong> carbonate ion to maintain charge neutrality, leading to the formula <strong>K\u2082CO\u2083<\/strong>.<\/p>\n\n\n\n<p>To determine the molecular mass (also known as molar mass or formula weight) of potassium carbonate, we add the atomic masses of all the atoms in the formula:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Potassium (K)<\/strong> has an atomic mass of <strong>39 g\/mol<\/strong>. Since there are two potassium atoms, their combined mass is <strong>78 g\/mol<\/strong>.<\/li>\n\n\n\n<li><strong>Carbon (C)<\/strong> has an atomic mass of <strong>12 g\/mol<\/strong>.<\/li>\n\n\n\n<li><strong>Oxygen (O)<\/strong> has an atomic mass of <strong>16 g\/mol<\/strong>, and since there are three oxygen atoms, the total oxygen mass is <strong>48 g\/mol<\/strong>.<\/li>\n<\/ul>\n\n\n\n<p>Adding these together gives the molecular mass:<br><strong>78 (K) + 12 (C) + 48 (O) = 138 g\/mol<\/strong><\/p>\n\n\n\n<p>Potassium carbonate is a white salt, highly soluble in water, and commonly used in soaps, glass manufacturing, and as a buffering agent.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner5-298.jpeg\" alt=\"\" class=\"wp-image-232159\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Solve 1. Write the name of the K2CO3compound and deduce its molecular mass. C(12), O(16) The Correct Answer and Explanation is: Answer: Molecular Mass Calculation: Explanation Potassium carbonate is an inorganic compound with the chemical formula K\u2082CO\u2083. It is composed of two potassium ions (K\u207a) and one carbonate ion (CO\u2083\u00b2\u207b). The carbonate ion is a [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-232158","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/232158","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=232158"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/232158\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=232158"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=232158"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=232158"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}