{"id":232346,"date":"2025-06-11T23:17:31","date_gmt":"2025-06-11T23:17:31","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=232346"},"modified":"2025-06-11T23:17:33","modified_gmt":"2025-06-11T23:17:33","slug":"fill-in-name-and-empirical-formula-of-each-ionic-compound-that-can-be-formed-from-ions-below","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/11\/fill-in-name-and-empirical-formula-of-each-ionic-compound-that-can-be-formed-from-ions-below\/","title":{"rendered":"Fill in name and empirical formula of each ionic compound that can be formed from ions below"},"content":{"rendered":"\n<p>Fill in name and empirical formula of each ionic compound that can be formed from ions below: 1) Cation: Na+, Anion: IO2^- 2) Cation: Na+, Anion: IO4^- 3) Cation: Na+, Anion: IO3^- 4) Cation: Na+, Anion: IO-<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-0-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Ionic Compounds Formed from Na\u207a and Iodine Oxyanions<\/strong><\/h3>\n\n\n\n<figure class=\"wp-block-table\"><table class=\"has-fixed-layout\"><thead><tr><th>No.<\/th><th>Cation<\/th><th>Anion<\/th><th>Name of Compound<\/th><th>Empirical Formula<\/th><\/tr><\/thead><tbody><tr><td>1<\/td><td>Na\u207a<\/td><td>IO\u2082\u207b<\/td><td>Sodium iodite<\/td><td>NaIO\u2082<\/td><\/tr><tr><td>2<\/td><td>Na\u207a<\/td><td>IO\u2084\u207b<\/td><td>Sodium periodate<\/td><td>NaIO\u2084<\/td><\/tr><tr><td>3<\/td><td>Na\u207a<\/td><td>IO\u2083\u207b<\/td><td>Sodium iodate<\/td><td>NaIO\u2083<\/td><\/tr><tr><td>4<\/td><td>Na\u207a<\/td><td>IO\u207b<\/td><td>Sodium hypoiodite<\/td><td>NaIO<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation:<\/strong><\/h3>\n\n\n\n<p>When forming ionic compounds, cations and anions combine in ratios that result in overall electrical neutrality. In this case, sodium ion (Na\u207a) is a monovalent cation, meaning it carries a single positive charge. It can combine with any monovalent anion, such as the oxyanions of iodine, which also carry a single negative charge (\u207b1). Because the charges are equal and opposite, these ions combine in a 1:1 ratio, resulting in empirical formulas of the form <strong>NaIO\u2093<\/strong>, where x depends on the number of oxygen atoms in the polyatomic ion.<\/p>\n\n\n\n<p>The iodine oxyanions are named systematically based on the number of oxygen atoms bonded to the iodine atom:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>IO\u207b<\/strong> is called <em>hypoiodite<\/em>. The prefix \u201chypo-\u201d and suffix \u201c-ite\u201d indicate fewer oxygen atoms than the \u201c-ite\u201d form.<\/li>\n\n\n\n<li><strong>IO\u2082\u207b<\/strong> is <em>iodite<\/em>, the \u201c-ite\u201d form with fewer oxygens than \u201c-ate\u201d.<\/li>\n\n\n\n<li><strong>IO\u2083\u207b<\/strong> is <em>iodate<\/em>, the common \u201c-ate\u201d form.<\/li>\n\n\n\n<li><strong>IO\u2084\u207b<\/strong> is <em>periodate<\/em>, using the prefix \u201cper-\u201d and suffix \u201c-ate\u201d to denote the most oxygen-rich form.<\/li>\n<\/ul>\n\n\n\n<p>When these anions combine with Na\u207a, their names are prefixed by \u201csodium\u201d (the cation name), and the empirical formula reflects the 1:1 stoichiometry. These naming conventions are standard for ionic compounds involving polyatomic ions and help ensure consistent communication in chemistry.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner9-263.jpeg\" alt=\"\" class=\"wp-image-232347\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Fill in name and empirical formula of each ionic compound that can be formed from ions below: 1) Cation: Na+, Anion: IO2^- 2) Cation: Na+, Anion: IO4^- 3) Cation: Na+, Anion: IO3^- 4) Cation: Na+, Anion: IO- The Correct Answer and Explanation is: Ionic Compounds Formed from Na\u207a and Iodine Oxyanions No. Cation Anion Name [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-232346","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/232346","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=232346"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/232346\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=232346"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=232346"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=232346"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}