{"id":232353,"date":"2025-06-11T23:28:38","date_gmt":"2025-06-11T23:28:38","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=232353"},"modified":"2025-06-11T23:28:41","modified_gmt":"2025-06-11T23:28:41","slug":"resolver-la-ecuacion-cual-es-el-precedimiento-correcto-para-resolver-la-ecuacion","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/11\/resolver-la-ecuacion-cual-es-el-precedimiento-correcto-para-resolver-la-ecuacion\/","title":{"rendered":"Resolver la ecuaci\u00f3n: cual es el precedimiento correcto para resolver la ecuacion"},"content":{"rendered":"\n<p><em>resolver la ecuaci\u00f3n: cual es el precedimiento correcto para resolver la ecuacion 3(x-2)=-4 (-x+2)? X = 2 X =-2 (-1)(-<\/em>) = (-1)(-2) Z- = X- 3x &#8211; 4x = -8 + 6 3x &#8211; 6 = 4x &#8211; 8 3(x &#8211; 2) = -4(-x + 2) (-1)(-x) = (-1)(2) ~X = 2 3x &#8211; 4x = -8 + 6 3x &#8211; 6 = 4x &#8211; 8 D) 3(x &#8211; 2) = 4(-x + 2) X = -4 (-1)(-x) = (-1)(4) ~X = 4 3x &#8211; 4x = 2 + 2 3x &#8211; 2 = 4x + 2 3(x &#8211; 2) = 4(-x + 2) 14 X = (-1)(-x) = (-1)(-14) C) Fl- = X- 3x &#8211; 4x = -8 &#8211; 6 3x &#8211; 6 = 4x &#8211; 8 3(x &#8211; 2) = -4(-x + 2) { Cu\u00e1l es el procedimiento correcto para 7 &#8211; 3( x &#8211; 2) = 4 (-x + 2 )? resolver la ecuaci\u00f3n:<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p><strong>Respuesta correcta:<\/strong><\/p>\n\n\n\n<p>Para resolver la ecuaci\u00f3n:<br><strong>7 &#8211; 3(x &#8211; 2) = 4(-x + 2)<\/strong><br>la respuesta correcta es:<br><strong>x = 3<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Procedimiento correcto para resolver la ecuaci\u00f3n:<\/strong><\/h3>\n\n\n\n<p><strong>Paso 1: Escribir la ecuaci\u00f3n original.<\/strong> 7\u22123(x\u22122)=4(\u2212x+2)7 &#8211; 3(x &#8211; 2) = 4(-x + 2)7\u22123(x\u22122)=4(\u2212x+2)<\/p>\n\n\n\n<p><strong>Paso 2: Aplicar la propiedad distributiva en ambos lados.<\/strong><br>Distribuir el -3 a los t\u00e9rminos dentro del par\u00e9ntesis en el lado izquierdo: \u22123(x\u22122)=\u22123x+6-3(x &#8211; 2) = -3x + 6\u22123(x\u22122)=\u22123x+6<\/p>\n\n\n\n<p>Distribuir el 4 a los t\u00e9rminos dentro del par\u00e9ntesis en el lado derecho: 4(\u2212x+2)=\u22124x+84(-x + 2) = -4x + 84(\u2212x+2)=\u22124x+8<\/p>\n\n\n\n<p>Entonces la ecuaci\u00f3n se convierte en: 7\u22123x+6=\u22124x+87 &#8211; 3x + 6 = -4x + 87\u22123x+6=\u22124x+8<\/p>\n\n\n\n<p><strong>Paso 3: Simplificar ambos lados.<\/strong><br>Sumar los t\u00e9rminos constantes en el lado izquierdo: (7+6)\u22123x=\u22124x+8\u21d213\u22123x=\u22124x+8(7 + 6) &#8211; 3x = -4x + 8 \\Rightarrow 13 &#8211; 3x = -4x + 8(7+6)\u22123x=\u22124x+8\u21d213\u22123x=\u22124x+8<\/p>\n\n\n\n<p><strong>Paso 4: Mover las variables a un solo lado y las constantes al otro.<\/strong><br>Sumamos 4x a ambos lados: 13\u22123x+4x=8\u21d213+x=813 &#8211; 3x + 4x = 8 \\Rightarrow 13 + x = 813\u22123x+4x=8\u21d213+x=8<\/p>\n\n\n\n<p>Restamos 13 de ambos lados: x=8\u221213\u21d2x=\u22125x = 8 &#8211; 13 \\Rightarrow x = -5x=8\u221213\u21d2x=\u22125<\/p>\n\n\n\n<p><strong>\u00a1Atenci\u00f3n!<\/strong> Esto nos da una contradicci\u00f3n con la respuesta que indicamos inicialmente (x = 3), lo que sugiere que algo est\u00e1 mal.<\/p>\n\n\n\n<p><strong>Revisemos la ecuaci\u00f3n original otra vez:<\/strong><br>Tal vez hubo un error en copiarla.<br>\u00bfEs la ecuaci\u00f3n correcta? <strong>7 &#8211; 3(x &#8211; 2) = 4(-x + 2)<\/strong><\/p>\n\n\n\n<p>Si es as\u00ed, entonces vamos paso a paso con m\u00e1s cuidado:<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Resoluci\u00f3n detallada nuevamente:<\/strong><\/h3>\n\n\n\n<p><strong>1. Expande ambos lados:<\/strong> 7\u22123(x\u22122)=4(\u2212x+2)\u21d27\u22123x+6=\u22124x+8\u21d213\u22123x=\u22124x+87 &#8211; 3(x &#8211; 2) = 4(-x + 2) \\Rightarrow 7 &#8211; 3x + 6 = -4x + 8 \\Rightarrow 13 &#8211; 3x = -4x + 87\u22123(x\u22122)=4(\u2212x+2)\u21d27\u22123x+6=\u22124x+8\u21d213\u22123x=\u22124x+8<\/p>\n\n\n\n<p><strong>2. Mueve las variables al mismo lado:<\/strong> 13+x=8\u21d2x=8\u221213\u21d2x=\u2212513 + x = 8 \\Rightarrow x = 8 &#8211; 13 \\Rightarrow x = -513+x=8\u21d2x=8\u221213\u21d2x=\u22125<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Conclusi\u00f3n:<\/strong><\/h3>\n\n\n\n<p>La soluci\u00f3n correcta es: x=\u22125\\boxed{x = -5}x=\u22125\u200b<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explicaci\u00f3n tipo libro (300 palabras):<\/strong><\/h3>\n\n\n\n<p>Para resolver una ecuaci\u00f3n algebraica como <strong>7 &#8211; 3(x &#8211; 2) = 4(-x + 2)<\/strong>, seguimos un procedimiento ordenado que incluye la aplicaci\u00f3n de la propiedad distributiva, simplificaci\u00f3n de t\u00e9rminos semejantes, y el uso de operaciones inversas para despejar la variable.<\/p>\n\n\n\n<p>En primer lugar, usamos la <strong>propiedad distributiva<\/strong> para eliminar los par\u00e9ntesis. Esta propiedad establece que a(b+c)=ab+aca(b + c) = ab + aca(b+c)=ab+ac. Aplic\u00e1ndola al lado izquierdo: \u22123(x\u22122)=\u22123x+6-3(x &#8211; 2) = -3x + 6\u22123(x\u22122)=\u22123x+6<\/p>\n\n\n\n<p>y al lado derecho: 4(\u2212x+2)=\u22124x+84(-x + 2) = -4x + 84(\u2212x+2)=\u22124x+8<\/p>\n\n\n\n<p>La ecuaci\u00f3n resultante es: 7\u22123x+6=\u22124x+87 &#8211; 3x + 6 = -4x + 87\u22123x+6=\u22124x+8<\/p>\n\n\n\n<p>Despu\u00e9s, combinamos los t\u00e9rminos constantes del lado izquierdo: 13\u22123x=\u22124x+813 &#8211; 3x = -4x + 813\u22123x=\u22124x+8<\/p>\n\n\n\n<p>Luego, queremos que todas las variables est\u00e9n en un solo lado, as\u00ed que sumamos 4x a ambos lados: 13+x=813 + x = 813+x=8<\/p>\n\n\n\n<p>Para aislar xxx, restamos 13 de ambos lados: x=8\u221213=\u22125x = 8 &#8211; 13 = -5x=8\u221213=\u22125<\/p>\n\n\n\n<p>Por lo tanto, la soluci\u00f3n de la ecuaci\u00f3n es \u22125\\boxed{-5}\u22125\u200b. Este m\u00e9todo paso a paso garantiza que no cometamos errores comunes como olvidar signos negativos o distribuir incorrectamente. Dominar estas t\u00e9cnicas es esencial para resolver con precisi\u00f3n ecuaciones algebraicas lineales.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner9-265.jpeg\" alt=\"\" class=\"wp-image-232354\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>resolver la ecuaci\u00f3n: cual es el precedimiento correcto para resolver la ecuacion 3(x-2)=-4 (-x+2)? X = 2 X =-2 (-1)(-) = (-1)(-2) Z- = X- 3x &#8211; 4x = -8 + 6 3x &#8211; 6 = 4x &#8211; 8 3(x &#8211; 2) = -4(-x + 2) (-1)(-x) = (-1)(2) ~X = 2 3x &#8211; 4x [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-232353","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/232353","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=232353"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/232353\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=232353"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=232353"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=232353"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}