{"id":232451,"date":"2025-06-12T01:06:05","date_gmt":"2025-06-12T01:06:05","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=232451"},"modified":"2025-06-12T01:06:07","modified_gmt":"2025-06-12T01:06:07","slug":"what-is-the-percent-composition-of-zinc-phosphate-zn3po42","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/12\/what-is-the-percent-composition-of-zinc-phosphate-zn3po42\/","title":{"rendered":"What is the percent composition of zinc phosphate (Zn3(PO4)2)"},"content":{"rendered":"\n
What is the percent composition of zinc phosphate (Zn3(PO4)2)? Find the percentage for each element and show work<\/pre>\n\n\n\n
The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n
To find the percent composition<\/strong> of zinc phosphate<\/strong>, Zn\u2083(PO\u2084)\u2082, we need to determine the molar mass<\/strong> of the compound and then calculate the mass percent<\/strong> of each element in it.<\/p>\n\n\n\n
\n\n\n\n
Step 1: Determine the molar mass of Zn\u2083(PO\u2084)\u2082<\/strong><\/h3>\n\n\n\n
First, break the formula into the number of atoms of each element:<\/p>\n\n\n\n
    \n
  • Zn<\/strong>: 3 atoms<\/li>\n\n\n\n
  • P<\/strong>: 2 atoms<\/li>\n\n\n\n
  • O<\/strong>: 8 atoms (since each PO\u2084 has 4 O, and there are 2 PO\u2084 groups)<\/li>\n<\/ul>\n\n\n\n
    Use the periodic table to get atomic masses (rounded to 2 decimal places):<\/p>\n\n\n\n
      \n
    • Zn (zinc) = 65.38 g\/mol<\/li>\n\n\n\n
    • P (phosphorus) = 30.97 g\/mol<\/li>\n\n\n\n
    • O (oxygen) = 16.00 g\/mol<\/li>\n<\/ul>\n\n\n\n
      Now calculate the molar mass:Zn3=3\u00d765.38=196.14 g\/molP2=2\u00d730.97=61.94 g\/molO8=8\u00d716.00=128.00 g\/mol\\text{Zn}_3 = 3 \\times 65.38 = 196.14 \\text{ g\/mol} \\\\ \\text{P}_2 = 2 \\times 30.97 = 61.94 \\text{ g\/mol} \\\\ \\text{O}_8 = 8 \\times 16.00 = 128.00 \\text{ g\/mol}Zn3\u200b=3\u00d765.38=196.14 g\/molP2\u200b=2\u00d730.97=61.94 g\/molO8\u200b=8\u00d716.00=128.00 g\/mol<\/p>\n\n\n\n
      Total molar mass of Zn\u2083(PO\u2084)\u2082<\/strong>:196.14+61.94+128.00=386.08 g\/mol196.14 + 61.94 + 128.00 = 386.08 \\text{ g\/mol}196.14+61.94+128.00=386.08 g\/mol<\/p>\n\n\n\n
      \n\n\n\n
      Step 2: Find percent composition<\/strong><\/h3>\n\n\n\n
      Now calculate each element\u2019s percent by dividing its total mass by the molar mass:<\/p>\n\n\n\n
        \n
      • Zinc<\/strong>:<\/li>\n<\/ul>\n\n\n\n
        196.14386.08\u00d7100\u224850.80%\\frac{196.14}{386.08} \\times 100 \\approx 50.80\\%386.08196.14\u200b\u00d7100\u224850.80%<\/p>\n\n\n\n
          \n
        • Phosphorus<\/strong>:<\/li>\n<\/ul>\n\n\n\n
          61.94386.08\u00d7100\u224816.04%\\frac{61.94}{386.08} \\times 100 \\approx 16.04\\%386.0861.94\u200b\u00d7100\u224816.04%<\/p>\n\n\n\n
            \n
          • Oxygen<\/strong>:<\/li>\n<\/ul>\n\n\n\n
            128.00386.08\u00d7100\u224833.16%\\frac{128.00}{386.08} \\times 100 \\approx 33.16\\%386.08128.00\u200b\u00d7100\u224833.16%<\/p>\n\n\n\n
            \n\n\n\n
            Final Answer:<\/strong><\/h3>\n\n\n\n
              \n
            • Zinc (Zn)<\/strong>: 50.80%<\/li>\n\n\n\n
            • Phosphorus (P)<\/strong>: 16.04%<\/li>\n\n\n\n
            • Oxygen (O)<\/strong>: 33.16%<\/li>\n<\/ul>\n\n\n\n
              \n\n\n\n
              Textbook-Style Explanation (\u2248300 words):<\/strong><\/h3>\n\n\n\n
              Percent composition is the percentage by mass of each element in a compound. It helps chemists understand how much of each element is present in a given compound. To determine the percent composition of zinc phosphate, Zn\u2083(PO\u2084)\u2082, we must first calculate its molar mass by summing the masses of all the atoms in the compound.<\/p>\n\n\n\n
              Zinc phosphate contains 3 atoms of zinc (Zn), 2 atoms of phosphorus (P), and 8 atoms of oxygen (O). Using the periodic table, we find the atomic masses: zinc is 65.38 g\/mol, phosphorus is 30.97 g\/mol, and oxygen is 16.00 g\/mol. Multiplying each atomic mass by the number of atoms in the formula gives us:<\/p>\n\n\n\n
                \n
              • Zinc: 3 \u00d7 65.38 = 196.14 g\/mol<\/li>\n\n\n\n
              • Phosphorus: 2 \u00d7 30.97 = 61.94 g\/mol<\/li>\n\n\n\n
              • Oxygen: 8 \u00d7 16.00 = 128.00 g\/mol<\/li>\n<\/ul>\n\n\n\n
                Adding these values gives the total molar mass of zinc phosphate:
                196.14 + 61.94 + 128.00 = 386.08 g\/mol.<\/p>\n\n\n\n
                To find the percent composition, divide the total mass of each element by the compound’s molar mass and multiply by 100:<\/p>\n\n\n\n
                  \n
                • %Zn = (196.14 \u00f7 386.08) \u00d7 100 \u2248 50.80%<\/li>\n\n\n\n
                • %P = (61.94 \u00f7 386.08) \u00d7 100 \u2248 16.04%<\/li>\n\n\n\n
                • %O = (128.00 \u00f7 386.08) \u00d7 100 \u2248 33.16%<\/li>\n<\/ul>\n\n\n\n
                  These values show the mass proportion of each element in zinc phosphate. This information is useful in chemical analysis, stoichiometry, and quality control in manufacturing.<\/p>\n\n\n\n
                  \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"
                  What is the percent composition of zinc phosphate (Zn3(PO4)2)? Find the percentage for each element and show work The Correct Answer and Explanation is: To find the percent composition of zinc phosphate, Zn\u2083(PO\u2084)\u2082, we need to determine the molar mass of the compound and then calculate the mass percent of each element in it. Step […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-232451","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/232451","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=232451"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/232451\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=232451"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=232451"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=232451"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}