{"id":232880,"date":"2025-06-12T09:57:07","date_gmt":"2025-06-12T09:57:07","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=232880"},"modified":"2025-06-12T09:57:09","modified_gmt":"2025-06-12T09:57:09","slug":"what-is-the-bromine-highest-oxidation-state-here","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/12\/what-is-the-bromine-highest-oxidation-state-here\/","title":{"rendered":"What is the bromine highest oxidation state here"},"content":{"rendered":"\n<p>What is the bromine highest oxidation state here? Write it down: (a) Br2 _ _ _ (b) BrCl3 _ _ _ (C) NaOBr _ _ _ (<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>Here are the correct answers and a detailed explanation for each compound:<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Answers:<\/h3>\n\n\n\n<p>(a) <strong>Br\u2082<\/strong> \u2192 <strong>0<\/strong><br>(b) <strong>BrCl\u2083<\/strong> \u2192 <strong>+3<\/strong><br>(c) <strong>NaOBr<\/strong> \u2192 <strong>+1<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>Oxidation state (also called oxidation number) is a concept that helps chemists track electron transfer in compounds and reactions. It represents the hypothetical charge an atom would have if all bonds to atoms of different elements were 100% ionic.<\/p>\n\n\n\n<p>Let\u2019s examine each compound:<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>(a) Br\u2082 (Bromine molecule):<\/strong><\/p>\n\n\n\n<p>In Br\u2082, bromine exists as a <strong>diatomic element<\/strong>, meaning it is composed of two bromine atoms bonded together. Since the atoms are identical, the electrons are shared equally.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Therefore, each bromine atom has an oxidation state of <strong>0<\/strong>.<\/li>\n\n\n\n<li>This is because elements in their <strong>elemental form<\/strong> always have an oxidation state of zero.<\/li>\n<\/ul>\n\n\n\n<p><strong>Oxidation state of Br in Br\u2082 = 0<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>(b) BrCl\u2083 (Bromine trichloride):<\/strong><\/p>\n\n\n\n<p>In BrCl\u2083, bromine is bonded to three chlorine atoms. Chlorine is more electronegative than bromine, so each Cl &#8220;pulls&#8221; electrons away from Br.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Chlorine typically has an oxidation state of <strong>\u20131<\/strong>.<\/li>\n\n\n\n<li>There are 3 chlorine atoms, contributing a total of \u20133.<\/li>\n<\/ul>\n\n\n\n<p>To balance the overall neutral charge:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Let Br\u2019s oxidation state be <strong>x<\/strong><\/li>\n\n\n\n<li>x + 3(\u20131) = 0<\/li>\n\n\n\n<li>x \u2013 3 = 0<\/li>\n\n\n\n<li>x = <strong>+3<\/strong><\/li>\n<\/ul>\n\n\n\n<p><strong>Oxidation state of Br in BrCl\u2083 = +3<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>(c) NaOBr (Sodium hypobromite):<\/strong><\/p>\n\n\n\n<p>This is an <strong>ionic compound<\/strong> made of Na\u207a, O\u00b2\u207b, and Br in a polyatomic ion. The key part is the <strong>hypobromite ion (OBr\u207b)<\/strong>.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Na is a group 1 metal, so it has an oxidation state of <strong>+1<\/strong>.<\/li>\n\n\n\n<li>Oxygen (O) typically has an oxidation state of <strong>\u20132<\/strong>.<\/li>\n\n\n\n<li>The overall charge of the OBr\u207b ion is \u20131.<\/li>\n<\/ul>\n\n\n\n<p>Let Br\u2019s oxidation state be <strong>x<\/strong>:<br>x + (\u20132) = \u20131<br>x = <strong>+1<\/strong><\/p>\n\n\n\n<p><strong>Oxidation state of Br in NaOBr = +1<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Summary:<\/h3>\n\n\n\n<figure class=\"wp-block-table\"><table class=\"has-fixed-layout\"><thead><tr><th>Compound<\/th><th>Oxidation State of Br<\/th><\/tr><\/thead><tbody><tr><td>(a) Br\u2082<\/td><td>0<\/td><\/tr><tr><td>(b) BrCl\u2083<\/td><td>+3<\/td><\/tr><tr><td>(c) NaOBr<\/td><td>+1<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n<p>This demonstrates that the oxidation state of bromine varies depending on the chemical environment, ranging from 0 (elemental form) to positive values when bonded with more electronegative atoms like oxygen or chlorine.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner5-364.jpeg\" alt=\"\" class=\"wp-image-232881\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>What is the bromine highest oxidation state here? Write it down: (a) Br2 _ _ _ (b) BrCl3 _ _ _ (C) NaOBr _ _ _ ( The Correct Answer and Explanation is: Here are the correct answers and a detailed explanation for each compound: Answers: (a) Br\u2082 \u2192 0(b) BrCl\u2083 \u2192 +3(c) NaOBr \u2192 [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-232880","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/232880","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=232880"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/232880\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=232880"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=232880"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=232880"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}