{"id":232988,"date":"2025-06-12T12:30:30","date_gmt":"2025-06-12T12:30:30","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=232988"},"modified":"2025-06-12T12:30:32","modified_gmt":"2025-06-12T12:30:32","slug":"what-is-the-bond-order-of-b2-and-b2","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/12\/what-is-the-bond-order-of-b2-and-b2\/","title":{"rendered":"What is the bond order of B2 and B2+"},"content":{"rendered":"\n<p>What is the bond order of B2 and B2+? Which of these species has a longer bond? Bond order of B2: Bond order of B2+: Which species has a longer bond<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-0-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p><strong>Bond order of B\u2082:<\/strong> 1<br><strong>Bond order of B\u2082\u207a:<\/strong> 0.5<br><strong>Which species has a longer bond?<\/strong> B\u2082\u207a<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>To determine the bond order and compare bond lengths of diatomic molecules such as B\u2082 and B\u2082\u207a, we refer to <strong>Molecular Orbital (MO) Theory<\/strong>, which describes bonding in terms of molecular orbitals formed from the combination of atomic orbitals. For second-period homonuclear diatomic molecules like boron (B), the molecular orbital energy level diagram is essential.<\/p>\n\n\n\n<p>For elements with atomic numbers less than or equal to 7 (i.e., B, C, N), the order of molecular orbitals is:<\/p>\n\n\n\n<p>\u03c3(1s) &lt; \u03c3*(1s) &lt; \u03c3(2s) &lt; \u03c3*(2s) &lt; <strong>\u03c0(2p)<\/strong> &lt; <strong>\u03c3(2p)<\/strong> &lt; \u03c0*(2p) &lt; \u03c3*(2p)<\/p>\n\n\n\n<h4 class=\"wp-block-heading\">Step 1: Electron configuration of B\u2082<\/h4>\n\n\n\n<p>Each boron atom has 5 electrons, so B\u2082 has 10 electrons total.<\/p>\n\n\n\n<p>Filling the molecular orbitals:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>\u03c3(1s) \u2192 2 electrons<\/li>\n\n\n\n<li>\u03c3*(1s) \u2192 2 electrons<\/li>\n\n\n\n<li>\u03c3(2s) \u2192 2 electrons<\/li>\n\n\n\n<li>\u03c3*(2s) \u2192 2 electrons<\/li>\n\n\n\n<li>\u03c0(2p_x) and \u03c0(2p_y) \u2192 2 electrons (one in each)<\/li>\n<\/ul>\n\n\n\n<p>Bond order = \u00bd [(bonding e\u207b) \u2212 (antibonding e\u207b)]<br>= \u00bd [(2 in \u03c0(2p) + 2 in \u03c3(2s) + 2 in \u03c3(1s)) \u2212 (2 in \u03c3*(2s) + 2 in \u03c3*(1s))]<br>= \u00bd [(6 bonding) \u2212 (4 antibonding)]<br>= \u00bd (6 \u2212 4) = <strong>1<\/strong><\/p>\n\n\n\n<h4 class=\"wp-block-heading\">Step 2: Electron configuration of B\u2082\u207a<\/h4>\n\n\n\n<p>B\u2082\u207a has 9 electrons (one less than B\u2082).<\/p>\n\n\n\n<p>Remove one electron from the highest energy occupied MO, which is one of the \u03c0(2p) orbitals.<\/p>\n\n\n\n<p>Now, \u03c0(2p) contains only 1 electron (unpaired), so:<\/p>\n\n\n\n<p>Bond order = \u00bd [(5 bonding) \u2212 (4 antibonding)] = \u00bd (1) = <strong>0.5<\/strong><\/p>\n\n\n\n<h4 class=\"wp-block-heading\">Step 3: Bond length comparison<\/h4>\n\n\n\n<p><strong>The greater the bond order, the stronger and shorter the bond.<\/strong><br>Since B\u2082 has a bond order of 1 and B\u2082\u207a has a bond order of 0.5, <strong>B\u2082\u207a has a longer bond<\/strong> due to its weaker bonding interaction.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>Summary:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>B\u2082 has a bond order of <strong>1<\/strong><\/li>\n\n\n\n<li>B\u2082\u207a has a bond order of <strong>0.5<\/strong><\/li>\n\n\n\n<li><strong>B\u2082\u207a has the longer bond<\/strong> because lower bond order implies a weaker, longer bond.<\/li>\n<\/ul>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner5-391.jpeg\" alt=\"\" class=\"wp-image-232989\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>What is the bond order of B2 and B2+? Which of these species has a longer bond? Bond order of B2: Bond order of B2+: Which species has a longer bond The Correct Answer and Explanation is: Bond order of B\u2082: 1Bond order of B\u2082\u207a: 0.5Which species has a longer bond? B\u2082\u207a Explanation: To determine [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-232988","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/232988","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=232988"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/232988\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=232988"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=232988"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=232988"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}