{"id":233159,"date":"2025-06-12T17:41:06","date_gmt":"2025-06-12T17:41:06","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=233159"},"modified":"2025-06-12T17:41:08","modified_gmt":"2025-06-12T17:41:08","slug":"calculate-the-density-of-mercury-in-lbm-ft3-from-a-tabulated-specific-gravity-and-calculate-the-volume-in-ft3-occupied-by-215-kg-of-mercury","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/12\/calculate-the-density-of-mercury-in-lbm-ft3-from-a-tabulated-specific-gravity-and-calculate-the-volume-in-ft3-occupied-by-215-kg-of-mercury\/","title":{"rendered":"Calculate the density of mercury in lbm\/ft^3 from a tabulated specific gravity, and calculate the volume in ft^3 occupied by 215 kg of mercury."},"content":{"rendered":"\n<p>Calculate the density of mercury in lbm\/ft^3 from a tabulated specific gravity, and calculate the volume in ft^3 occupied by 215 kg of mercury.<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p><strong>Answer:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Density of mercury in lbm\/ft\u00b3<\/strong>:<br>Specific gravity of mercury \u2248 13.6<br>Density of water = 62.4 lbm\/ft\u00b3<br>\u21d2 Density of mercury = 13.6 \u00d7 62.4 = <strong>848.64 lbm\/ft\u00b3<\/strong><\/li>\n\n\n\n<li><strong>Volume occupied by 215 kg of mercury<\/strong>:<br>215 kg \u00d7 2.20462 lbm\/kg = <strong>473.993 lbm<\/strong><br>Volume = mass \/ density = 473.993 lbm \u00f7 848.64 lbm\/ft\u00b3 \u2248 <strong>0.5585 ft\u00b3<\/strong><\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>Textbook-Style Explanation<\/strong><\/p>\n\n\n\n<p>To calculate the density of mercury in imperial units (pounds mass per cubic foot, or lbm\/ft\u00b3), we start with its <strong>specific gravity (SG)<\/strong>. Specific gravity is defined as the ratio of the density of a substance to the density of water at a reference temperature, typically 4\u00b0C. Mercury has a specific gravity of approximately <strong>13.6<\/strong>, which means it is 13.6 times denser than water.<\/p>\n\n\n\n<p>In the imperial system, the <strong>density of water<\/strong> is approximately <strong>62.4 lbm\/ft\u00b3<\/strong>. Since specific gravity is a unitless ratio, we can calculate the density of mercury by simply multiplying this value by the specific gravity:Density&nbsp;of&nbsp;mercury=SG\u00d7Density&nbsp;of&nbsp;water=13.6\u00d762.4=848.64\u2009lbm\/ft3\\text{Density of mercury} = \\text{SG} \\times \\text{Density of water} = 13.6 \\times 62.4 = 848.64 \\, \\text{lbm\/ft}^3Density&nbsp;of&nbsp;mercury=SG\u00d7Density&nbsp;of&nbsp;water=13.6\u00d762.4=848.64lbm\/ft3<\/p>\n\n\n\n<p>Next, to determine the <strong>volume occupied by a given mass of mercury<\/strong>, we need to convert the mass from kilograms to pounds mass. Using the conversion factor:1\u2009kg=2.20462\u2009lbm1 \\, \\text{kg} = 2.20462 \\, \\text{lbm}1kg=2.20462lbm215\u2009kg\u00d72.20462=473.993\u2009lbm215 \\, \\text{kg} \\times 2.20462 = 473.993 \\, \\text{lbm}215kg\u00d72.20462=473.993lbm<\/p>\n\n\n\n<p>Now we apply the definition of density:Density=MassVolume\u21d2Volume=MassDensity=473.993848.64\u22480.5585\u2009ft3\\text{Density} = \\frac{\\text{Mass}}{\\text{Volume}} \\Rightarrow \\text{Volume} = \\frac{\\text{Mass}}{\\text{Density}} = \\frac{473.993}{848.64} \\approx 0.5585 \\, \\text{ft}^3Density=VolumeMass\u200b\u21d2Volume=DensityMass\u200b=848.64473.993\u200b\u22480.5585ft3<\/p>\n\n\n\n<p>Thus, <strong>215 kg of mercury occupies approximately 0.5585 ft\u00b3<\/strong>. This calculation is commonly seen in fluid mechanics and thermodynamics to convert between metric and imperial units or to determine how much space a given mass of a liquid will occupy based on its known properties.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-196.jpeg\" alt=\"\" class=\"wp-image-233160\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Calculate the density of mercury in lbm\/ft^3 from a tabulated specific gravity, and calculate the volume in ft^3 occupied by 215 kg of mercury. The Correct Answer and Explanation is: Answer: Textbook-Style Explanation To calculate the density of mercury in imperial units (pounds mass per cubic foot, or lbm\/ft\u00b3), we start with its specific gravity [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-233159","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/233159","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=233159"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/233159\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=233159"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=233159"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=233159"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}