{"id":233328,"date":"2025-06-13T04:40:07","date_gmt":"2025-06-13T04:40:07","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=233328"},"modified":"2025-06-13T04:40:10","modified_gmt":"2025-06-13T04:40:10","slug":"8-ml-of-benzaldehyde-reacted-with-acetone-to-produce-dibenzalacetone","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/13\/8-ml-of-benzaldehyde-reacted-with-acetone-to-produce-dibenzalacetone\/","title":{"rendered":"8 mL of benzaldehyde reacted with acetone to produce dibenzalacetone"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">8 mL of benzaldehyde reacted with acetone to produce dibenzalacetone. What is the theoretical yield in grams? Answer should be rounded to one decimal place. Molar weight: benzaldehyde = 106.23 g\/mol, dibenzalacetone = 234.30 g\/mol.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step 1: Balanced Chemical Equation<\/strong><\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">The <strong>aldol condensation<\/strong> between <strong>benzaldehyde<\/strong> and <strong>acetone<\/strong> proceeds as:2\u2009C6H5CHO+CH3COCH3\u2192C6H5CH=CHCOCH=CHC6H5+H2O2 \\, \\text{C}_6\\text{H}_5\\text{CHO} + \\text{CH}_3\\text{COCH}_3 \\rightarrow \\text{C}_6\\text{H}_5\\text{CH}=\\text{CHCOCH}=\\text{CHC}_6\\text{H}_5 + \\text{H}_2\\text{O}2C6\u200bH5\u200bCHO+CH3\u200bCOCH3\u200b\u2192C6\u200bH5\u200bCH=CHCOCH=CHC6\u200bH5\u200b+H2\u200bO<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">This means <strong>2 moles of benzaldehyde<\/strong> react with <strong>1 mole of acetone<\/strong> to form <strong>1 mole of dibenzalacetone<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step 2: Convert Volume of Benzaldehyde to Moles<\/strong><\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">We are given:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Volume of benzaldehyde = <strong>8.0 mL<\/strong><\/li>\n\n\n\n<li>Density of benzaldehyde = <strong>1.044 g\/mL<\/strong> (standard value)<\/li>\n\n\n\n<li>Molar mass of benzaldehyde = <strong>106.23 g\/mol<\/strong><\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">Mass&nbsp;of&nbsp;benzaldehyde=8.0\u2009mL\u00d71.044\u2009g\/mL=8.352\u2009g\\text{Mass of benzaldehyde} = 8.0 \\, \\text{mL} \\times 1.044 \\, \\text{g\/mL} = 8.352 \\, \\text{g}Mass&nbsp;of&nbsp;benzaldehyde=8.0mL\u00d71.044g\/mL=8.352gMoles&nbsp;of&nbsp;benzaldehyde=8.352\u2009g106.23\u2009g\/mol\u22480.0786\u2009mol\\text{Moles of benzaldehyde} = \\frac{8.352 \\, \\text{g}}{106.23 \\, \\text{g\/mol}} \\approx 0.0786 \\, \\text{mol}Moles&nbsp;of&nbsp;benzaldehyde=106.23g\/mol8.352g\u200b\u22480.0786mol<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step 3: Use Stoichiometry to Find Moles of Product<\/strong><\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">From the balanced equation:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>2 mol benzaldehyde \u2192 1 mol dibenzalacetone<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">So:Moles&nbsp;of&nbsp;dibenzalacetone=0.07862=0.0393\u2009mol\\text{Moles of dibenzalacetone} = \\frac{0.0786}{2} = 0.0393 \\, \\text{mol}Moles&nbsp;of&nbsp;dibenzalacetone=20.0786\u200b=0.0393mol<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step 4: Convert Moles to Grams<\/strong><\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">Mass=0.0393\u2009mol\u00d7234.30\u2009g\/mol\u22489.2\u2009g\\text{Mass} = 0.0393 \\, \\text{mol} \\times 234.30 \\, \\text{g\/mol} \\approx 9.2 \\, \\text{g}Mass=0.0393mol\u00d7234.30g\/mol\u22489.2g<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">\u2705 <strong>Final Answer: 9.2 g<\/strong><\/h3>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Conclusion (Textbook-style Summary)<\/strong><\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">To calculate the theoretical yield of dibenzalacetone, we first determine the number of moles of benzaldehyde used by converting the given volume to mass using its density and then to moles using its molar mass. From the balanced chemical reaction, two moles of benzaldehyde are needed to produce one mole of dibenzalacetone. We apply stoichiometry to find the expected moles of product and finally convert it to grams using the molar mass of dibenzalacetone. The theoretical yield is therefore <strong>9.2 grams<\/strong>, assuming benzaldehyde is the limiting reagent and the reaction proceeds with 100% efficiency.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-209.jpeg\" alt=\"\" class=\"wp-image-233329\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>8 mL of benzaldehyde reacted with acetone to produce dibenzalacetone. What is the theoretical yield in grams? Answer should be rounded to one decimal place. Molar weight: benzaldehyde = 106.23 g\/mol, dibenzalacetone = 234.30 g\/mol. The Correct Answer and Explanation is: Step 1: Balanced Chemical Equation The aldol condensation between benzaldehyde and acetone proceeds as:2\u2009C6H5CHO+CH3COCH3\u2192C6H5CH=CHCOCH=CHC6H5+H2O2 [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-233328","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/233328","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=233328"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/233328\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=233328"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=233328"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=233328"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}