{"id":233393,"date":"2025-06-13T05:53:44","date_gmt":"2025-06-13T05:53:44","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=233393"},"modified":"2025-06-13T05:53:47","modified_gmt":"2025-06-13T05:53:47","slug":"what-is-the-normal-boiling-point-of-each-compound","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/13\/what-is-the-normal-boiling-point-of-each-compound\/","title":{"rendered":"What is the normal boiling point of each compound"},"content":{"rendered":"\n<p>What is the normal boiling point of each compound? 800 700 600 Vapor pressure (mm Hg) 500 CS<br>400 300 CH<br>NO<br>200 100 0 -30 -10 10 30 50 70 90 110 Temperature (\u00b0C) CS<br>: \u00b0C CH<br>NO<br>: \u00b0C<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-0-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>To determine the <strong>normal boiling point<\/strong> of each compound, we use the <strong>vapor pressure vs. temperature graph<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">\ud83d\udd0d <strong>Definition<\/strong><\/h3>\n\n\n\n<p><strong>Normal boiling point<\/strong> is the <strong>temperature at which a compound\u2019s vapor pressure equals standard atmospheric pressure (760 mm Hg).<\/strong><\/p>\n\n\n\n<p>So on a <strong>vapor pressure vs. temperature graph<\/strong>, find the <strong>temperature where the vapor pressure = 760 mm Hg<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">\ud83d\udcc9 <strong>From the Graph (Based on the Description)<\/strong><\/h3>\n\n\n\n<p>We are given vapor pressure data for two compounds:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>CS\u2082 (Carbon disulfide)<\/strong><\/li>\n\n\n\n<li><strong>CH\u2083NO\u2082 (Nitromethane)<\/strong><\/li>\n<\/ul>\n\n\n\n<p>We identify the <strong>temperature where each compound\u2019s vapor pressure curve crosses 760 mm Hg<\/strong>.<\/p>\n\n\n\n<h4 class=\"wp-block-heading\">\ud83d\udd38 For <strong>CS\u2082<\/strong>:<\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The vapor pressure reaches <strong>760 mm Hg around 46\u00b0C<\/strong>.<\/li>\n\n\n\n<li>So, <strong>normal boiling point of CS\u2082 = 46\u00b0C<\/strong>.<\/li>\n<\/ul>\n\n\n\n<h4 class=\"wp-block-heading\">\ud83d\udd38 For <strong>CH\u2083NO\u2082<\/strong>:<\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The vapor pressure reaches <strong>760 mm Hg around 101\u00b0C<\/strong>.<\/li>\n\n\n\n<li>So, <strong>normal boiling point of CH\u2083NO\u2082 = 101\u00b0C<\/strong>.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">\u2705 <strong>Final Answers<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>CS\u2082:<\/strong> <strong>46\u00b0C<\/strong><\/li>\n\n\n\n<li><strong>CH\u2083NO\u2082:<\/strong> <strong>101\u00b0C<\/strong><\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">\ud83d\udcd8 <strong>Explanation<\/strong><\/h3>\n\n\n\n<p>The <strong>boiling point<\/strong> of a liquid is the temperature at which its <strong>vapor pressure equals the external atmospheric pressure<\/strong>. Under <strong>standard atmospheric pressure (1 atm = 760 mm Hg)<\/strong>, this is called the <strong>normal boiling point<\/strong>.<\/p>\n\n\n\n<p>Vapor pressure increases with temperature because more molecules have enough energy to escape the liquid phase into the vapor phase. The relationship between temperature and vapor pressure is generally <strong>exponential<\/strong>, as described by the <strong>Clausius-Clapeyron equation<\/strong>.<\/p>\n\n\n\n<p>To determine the <strong>normal boiling point<\/strong> from a <strong>vapor pressure vs. temperature graph<\/strong>, we locate the <strong>temperature at which the compound\u2019s vapor pressure curve intersects 760 mm Hg<\/strong>.<\/p>\n\n\n\n<p>In this case, we analyze two substances:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>For <strong>carbon disulfide (CS\u2082)<\/strong>, the vapor pressure curve reaches <strong>760 mm Hg<\/strong> at approximately <strong>46\u00b0C<\/strong>, indicating its normal boiling point. This relatively low boiling point reflects CS\u2082\u2019s high volatility and weak intermolecular forces (London dispersion forces).<\/li>\n\n\n\n<li>For <strong>nitromethane (CH\u2083NO\u2082)<\/strong>, the vapor pressure reaches <strong>760 mm Hg<\/strong> at around <strong>101\u00b0C<\/strong>. This higher boiling point suggests stronger intermolecular forces, likely due to <strong>dipole-dipole interactions<\/strong> from the polar nitro group.<\/li>\n<\/ul>\n\n\n\n<p>In summary, the <strong>normal boiling point<\/strong> is determined by the temperature at which the liquid\u2019s vapor pressure equals 760 mm Hg. It provides important information about the <strong>volatility and intermolecular forces<\/strong> in the compound.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-227.jpeg\" alt=\"\" class=\"wp-image-233394\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>What is the normal boiling point of each compound? 800 700 600 Vapor pressure (mm Hg) 500 CS400 300 CHNO200 100 0 -30 -10 10 30 50 70 90 110 Temperature (\u00b0C) CS: \u00b0C CHNO: \u00b0C The Correct Answer and Explanation is: To determine the normal boiling point of each compound, we use the vapor [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-233393","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/233393","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=233393"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/233393\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=233393"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=233393"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=233393"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}