{"id":233454,"date":"2025-06-13T06:38:37","date_gmt":"2025-06-13T06:38:37","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=233454"},"modified":"2025-06-13T06:38:39","modified_gmt":"2025-06-13T06:38:39","slug":"set-up-an-expression-to-find-the-area-of-the-shaded-region-in-figure-below","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/13\/set-up-an-expression-to-find-the-area-of-the-shaded-region-in-figure-below\/","title":{"rendered":"Set up an expression to find the area of the shaded region in Figure below"},"content":{"rendered":"\n<p>Set up an expression to find the area of the shaded region in Figure below . Then uge your graphing calculator ta evaluate the expression <\/p>\n\n\n\n<p>The Correct Answer and Explanation is:<\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step-by-Step General Approach (Textbook Style)<\/strong><\/h3>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Concept: Area of a Shaded Region Between Curves<\/strong><\/h4>\n\n\n\n<p>To find the area of a shaded region between two curves or under a single curve, the <strong>definite integral<\/strong> is used. The area under a curve y=f(x)y = f(x)y=f(x) from x=ax = ax=a to x=bx = bx=b is given by: Area=\u222babf(x)\u2009dx\\text{Area} = \\int_a^b f(x)\\,dxArea=\u222bab\u200bf(x)dx<\/p>\n\n\n\n<p>If there are two curves, where f(x)f(x)f(x) is the <strong>upper function<\/strong> and g(x)g(x)g(x) is the <strong>lower function<\/strong>, then the area between the curves from x=ax = ax=a to x=bx = bx=b is: Area=\u222bab[f(x)\u2212g(x)]\u2009dx\\text{Area} = \\int_a^b [f(x) &#8211; g(x)]\\,dxArea=\u222bab\u200b[f(x)\u2212g(x)]dx<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Example Setup<\/strong><\/h3>\n\n\n\n<p>Suppose the shaded region lies between the curves y=3x\u2212x2y = 3x &#8211; x^2y=3x\u2212x2 (on top) and y=xy = xy=x (on the bottom) from x=0x = 0x=0 to x=2x = 2x=2.<\/p>\n\n\n\n<p>The expression for the area becomes: Area=\u222b02[(3x\u2212x2)\u2212x]\u2009dx=\u222b02(2x\u2212x2)\u2009dx\\text{Area} = \\int_0^2 [(3x &#8211; x^2) &#8211; x]\\,dx = \\int_0^2 (2x &#8211; x^2)\\,dxArea=\u222b02\u200b[(3x\u2212x2)\u2212x]dx=\u222b02\u200b(2x\u2212x2)dx<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Evaluating with a Graphing Calculator<\/strong><\/h3>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Enter the function<\/strong> into the <code>Y=<\/code> screen.\n<ul class=\"wp-block-list\">\n<li>In this case: Y1=2x\u2212x2Y_1 = 2x &#8211; x^2Y1\u200b=2x\u2212x2<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Use the <code>fnInt<\/code> or <code>\u222b(<\/code> function<\/strong> (depending on your calculator model).\n<ul class=\"wp-block-list\">\n<li>Example on TI-84:\n<ul class=\"wp-block-list\">\n<li>Press <code>MATH<\/code> \u2192 scroll to <code>fnInt(<\/code><\/li>\n\n\n\n<li>Enter: <code>fnInt(2x - x^2, x, 0, 2)<\/code><\/li>\n<\/ul>\n<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Hit <code>ENTER<\/code><\/strong>, and the calculator evaluates the integral.<\/li>\n<\/ol>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Answer to the Example<\/strong><\/h3>\n\n\n\n<p>\u222b02(2x\u2212x2)\u2009dx=[x2\u2212x33]02=(4\u221283)\u2212(0\u22120)=43\\int_0^2 (2x &#8211; x^2)\\,dx = \\left[ x^2 &#8211; \\frac{x^3}{3} \\right]_0^2 = (4 &#8211; \\frac{8}{3}) &#8211; (0 &#8211; 0) = \\frac{4}{3}\u222b02\u200b(2x\u2212x2)dx=[x2\u22123&#215;3\u200b]02\u200b=(4\u221238\u200b)\u2212(0\u22120)=34\u200b<\/p>\n\n\n\n<p>So, the area of the shaded region is <strong>43\\frac{4}{3}34\u200b square units.<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Conclusion<\/strong><\/h3>\n\n\n\n<p>Setting up and evaluating definite integrals allows us to find the exact area of shaded regions under or between curves. The upper and lower functions must be identified clearly from the graph. A graphing calculator simplifies evaluation by numerically computing the integral once the correct expression is input.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-243.jpeg\" alt=\"\" class=\"wp-image-233455\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Set up an expression to find the area of the shaded region in Figure below . Then uge your graphing calculator ta evaluate the expression The Correct Answer and Explanation is: Step-by-Step General Approach (Textbook Style) Concept: Area of a Shaded Region Between Curves To find the area of a shaded region between two curves [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-233454","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/233454","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=233454"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/233454\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=233454"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=233454"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=233454"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}