{"id":233472,"date":"2025-06-13T06:49:32","date_gmt":"2025-06-13T06:49:32","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=233472"},"modified":"2025-06-13T06:49:34","modified_gmt":"2025-06-13T06:49:34","slug":"complete-and-balance-the-following-acid-base-reactions-include-solubility-state-as-well","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/13\/complete-and-balance-the-following-acid-base-reactions-include-solubility-state-as-well\/","title":{"rendered":"Complete and balance the following acid\/base reactions. Include solubility state as well."},"content":{"rendered":"\n

Complete and balance the following acid\/base reactions. Include solubility state as well. Ba(OH)2(aq) + H3PO4(aq) ? NH3(aq) + H2SO4(aq)<\/p>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

\n\n\n\n

1. Ba(OH)\u2082(aq) + H\u2083PO\u2084(aq) \u2192 ?<\/strong><\/h3>\n\n\n\n

Step 1: Identify the acid and base<\/strong><\/p>\n\n\n\n

    \n
  • Ba(OH)\u2082<\/strong> is a strong base.<\/li>\n\n\n\n
  • H\u2083PO\u2084<\/strong> (phosphoric acid) is a weak triprotic acid.<\/li>\n<\/ul>\n\n\n\n

    Step 2: Write the products of neutralization<\/strong><\/p>\n\n\n\n

    Acid + Base \u2192 Salt + Water
    Ba(OH)\u2082 provides 2 OH\u207b<\/strong>, and H\u2083PO\u2084 provides 3 H\u207a<\/strong>, so the reaction ratio is 3 Ba(OH)\u2082 : 2 H\u2083PO\u2084<\/strong> to form Ba\u2083(PO\u2084)\u2082<\/strong>, a slightly soluble salt, and water<\/strong>.<\/p>\n\n\n\n

    Balanced Equation:<\/strong><\/p>\n\n\n\n

    \n

    3Ba(OH)\u2082(aq) + 2H\u2083PO\u2084(aq) \u2192 Ba\u2083(PO\u2084)\u2082(s) + 6H\u2082O(l)<\/p>\n<\/blockquote>\n\n\n\n

      \n
    • Ba\u2083(PO\u2084)\u2082<\/strong> is a precipitate<\/strong> (insoluble in water).<\/li>\n\n\n\n
    • Water<\/strong> is a liquid<\/strong> formed during neutralization.<\/li>\n<\/ul>\n\n\n\n
      \n\n\n\n

      2. NH\u2083(aq) + H\u2082SO\u2084(aq) \u2192 ?<\/strong><\/h3>\n\n\n\n

      Step 1: Identify the acid and base<\/strong><\/p>\n\n\n\n

        \n
      • NH\u2083 (ammonia)<\/strong> is a weak base<\/strong>.<\/li>\n\n\n\n
      • H\u2082SO\u2084<\/strong> (sulfuric acid) is a strong diprotic acid<\/strong>.<\/li>\n<\/ul>\n\n\n\n

        Step 2: Determine the salt formed<\/strong><\/p>\n\n\n\n

        Ammonia reacts with sulfuric acid to form ammonium sulfate, (NH\u2084)\u2082SO\u2084<\/strong>, and no water is directly formed in this neutralization (because ammonia is not hydroxide-based).<\/p>\n\n\n\n

        Balanced Equation:<\/strong><\/p>\n\n\n\n

        \n

        2NH\u2083(aq) + H\u2082SO\u2084(aq) \u2192 (NH\u2084)\u2082SO\u2084(aq)<\/p>\n<\/blockquote>\n\n\n\n

          \n
        • The product, (NH\u2084)\u2082SO\u2084<\/strong>, is soluble in water<\/strong>, hence aqueous.<\/li>\n<\/ul>\n\n\n\n
          \n\n\n\n

          Final Answers:<\/h3>\n\n\n\n

          1.<\/strong>
          3Ba(OH)\u2082(aq) + 2H\u2083PO\u2084(aq) \u2192 Ba\u2083(PO\u2084)\u2082(s) + 6H\u2082O(l)<\/strong><\/p>\n\n\n\n

          2.<\/strong>
          2NH\u2083(aq) + H\u2082SO\u2084(aq) \u2192 (NH\u2084)\u2082SO\u2084(aq)<\/strong><\/p>\n\n\n\n

          \n\n\n\n

          \ud83d\udcd8 Explanation (300 words):<\/h3>\n\n\n\n

          Acid-base reactions are fundamental in chemistry and often involve the transfer of hydrogen ions (H\u207a) from acids to bases. In a neutralization reaction, an acid reacts with a base to produce a salt and usually water.<\/p>\n\n\n\n

          In the first reaction, barium hydroxide (Ba(OH)\u2082)<\/strong>, a strong base, reacts with phosphoric acid (H\u2083PO\u2084)<\/strong>, a weak triprotic acid. Each Ba(OH)\u2082 unit supplies 2 hydroxide ions (OH\u207b), and each H\u2083PO\u2084 molecule supplies 3 hydrogen ions (H\u207a). To balance the number of H\u207a and OH\u207b ions, we need 3 Ba(OH)\u2082 molecules and 2 H\u2083PO\u2084 molecules. This forms the salt barium phosphate (Ba\u2083(PO\u2084)\u2082)<\/strong> and 6 molecules of water. Barium phosphate is insoluble<\/strong> in water, so it forms a precipitate<\/strong>, indicated as (s).<\/p>\n\n\n\n

          In the second reaction, ammonia (NH\u2083)<\/strong>, a weak base, reacts with sulfuric acid (H\u2082SO\u2084)<\/strong>. Ammonia doesn\u2019t contain OH\u207b ions like traditional bases, but it accepts protons (H\u207a) to form ammonium ions (NH\u2084\u207a)<\/strong>. Each H\u2082SO\u2084 molecule provides 2 H\u207a ions, which can protonate 2 NH\u2083 molecules. The result is the salt ammonium sulfate ((NH\u2084)\u2082SO\u2084)<\/strong>, which is soluble in water<\/strong> and remains aqueous.<\/p>\n\n\n\n

          These reactions demonstrate key principles of acid-base chemistry, solubility rules, and the importance of balancing chemical equations to reflect conservation of mass and charge.<\/p>\n\n\n\n

          \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

          Complete and balance the following acid\/base reactions. Include solubility state as well. Ba(OH)2(aq) + H3PO4(aq) ? NH3(aq) + H2SO4(aq) The Correct Answer and Explanation is: 1. Ba(OH)\u2082(aq) + H\u2083PO\u2084(aq) \u2192 ? Step 1: Identify the acid and base Step 2: Write the products of neutralization Acid + Base \u2192 Salt + WaterBa(OH)\u2082 provides 2 OH\u207b, […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-233472","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/233472","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=233472"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/233472\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=233472"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=233472"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=233472"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}