{"id":233476,"date":"2025-06-13T06:51:52","date_gmt":"2025-06-13T06:51:52","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=233476"},"modified":"2025-06-13T06:51:54","modified_gmt":"2025-06-13T06:51:54","slug":"what-mass-of-sodium-hydroxide-has-the-same-number-of-oxygen-atoms-as-130g-of-barium-dihydrogen-phosphate","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/13\/what-mass-of-sodium-hydroxide-has-the-same-number-of-oxygen-atoms-as-130g-of-barium-dihydrogen-phosphate\/","title":{"rendered":"what mass of sodium hydroxide has the same number of oxygen atoms as 130g of barium dihydrogen phosphate"},"content":{"rendered":"\n<p>what mass of sodium hydroxide has the same number of oxygen atoms as 130g of barium dihydrogen phosphate<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-0-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step 1: Determine the number of oxygen atoms in 130 g of Ba(H\u2082PO\u2084)\u2082<\/strong><\/h3>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Molar mass of Ba(H\u2082PO\u2084)\u2082<\/strong>:\n<ul class=\"wp-block-list\">\n<li>Ba = 137.33 g\/mol<\/li>\n\n\n\n<li>H = 1.008 \u00d7 4 = 4.032 g\/mol<\/li>\n\n\n\n<li>P = 30.97 \u00d7 2 = 61.94 g\/mol<\/li>\n\n\n\n<li>O = 16.00 \u00d7 8 = 128.00 g\/mol<\/li>\n\n\n\n<li><strong>Total molar mass<\/strong> = 137.33 + 4.032 + 61.94 + 128.00 = <strong>331.30 g\/mol<\/strong><\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Moles of Ba(H\u2082PO\u2084)\u2082 in 130 g<\/strong>: Moles=130331.30\u22480.3924\u00a0mol\\text{Moles} = \\frac{130}{331.30} \\approx 0.3924 \\text{ mol}Moles=331.30130\u200b\u22480.3924\u00a0mol<\/li>\n\n\n\n<li><strong>Oxygen atoms per formula unit of Ba(H\u2082PO\u2084)\u2082<\/strong>:<br>Each H\u2082PO\u2084\u207b group has 4 oxygen atoms. There are 2 such groups, so: Total\u00a0O\u00a0atoms\u00a0per\u00a0molecule=4\u00d72=8\\text{Total O atoms per molecule} = 4 \u00d7 2 = 8Total\u00a0O\u00a0atoms\u00a0per\u00a0molecule=4\u00d72=8<\/li>\n\n\n\n<li><strong>Total moles of oxygen atoms<\/strong>: 0.3924\u00a0mol\u00d78=3.139\u00a0mol\u00a0O\u00a0atoms0.3924 \\text{ mol} \u00d7 8 = 3.139 \\text{ mol O atoms}0.3924\u00a0mol\u00d78=3.139\u00a0mol\u00a0O\u00a0atoms<\/li>\n<\/ol>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step 2: Determine the mass of NaOH that contains 3.139 mol of oxygen atoms<\/strong><\/h3>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Each NaOH contains 1 oxygen atom<\/strong><br>Therefore, 1 mol of NaOH provides 1 mol of oxygen atoms.<\/li>\n\n\n\n<li><strong>We need 3.139 mol of NaOH to get 3.139 mol of O atoms<\/strong><\/li>\n\n\n\n<li><strong>Molar mass of NaOH<\/strong>:<br>Na = 22.99 g\/mol<br>O = 16.00 g\/mol<br>H = 1.008 g\/mol<br>Total = 22.99 + 16.00 + 1.008 = <strong>39.998 g\/mol<\/strong><\/li>\n\n\n\n<li><strong>Mass of NaOH<\/strong>: Mass=3.139\u00a0mol\u00d739.998\u00a0g\/mol\u2248125.54\u00a0g\\text{Mass} = 3.139 \\text{ mol} \u00d7 39.998 \\text{ g\/mol} \\approx \\boxed{125.54 \\text{ g}}Mass=3.139\u00a0mol\u00d739.998\u00a0g\/mol\u2248125.54\u00a0g\u200b<\/li>\n<\/ol>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Final Answer:<\/strong><\/h3>\n\n\n\n<p><strong>125.54 grams<\/strong> of sodium hydroxide contain the same number of oxygen atoms as <strong>130 grams<\/strong> of barium dihydrogen phosphate.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Textbook-Style Explanation:<\/strong><\/h3>\n\n\n\n<p>To compare the number of oxygen atoms in two substances, one must consider both the chemical formulas and the quantities involved. Barium dihydrogen phosphate, Ba(H\u2082PO\u2084)\u2082, contains two dihydrogen phosphate groups, each contributing four oxygen atoms, for a total of eight per formula unit. By calculating the number of moles in the given mass and multiplying by the number of oxygen atoms per mole, we determine the total moles of oxygen atoms.<\/p>\n\n\n\n<p>Sodium hydroxide, NaOH, contains only one oxygen atom per molecule. Therefore, the number of moles of NaOH needed equals the number of moles of oxygen atoms required. By multiplying the required moles of NaOH by its molar mass, we find the mass necessary to match the oxygen content of the original compound.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-249.jpeg\" alt=\"\" class=\"wp-image-233477\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>what mass of sodium hydroxide has the same number of oxygen atoms as 130g of barium dihydrogen phosphate The Correct Answer and Explanation is: Step 1: Determine the number of oxygen atoms in 130 g of Ba(H\u2082PO\u2084)\u2082 Step 2: Determine the mass of NaOH that contains 3.139 mol of oxygen atoms Final Answer: 125.54 grams [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-233476","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/233476","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=233476"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/233476\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=233476"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=233476"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=233476"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}