{"id":233563,"date":"2025-06-13T08:17:22","date_gmt":"2025-06-13T08:17:22","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=233563"},"modified":"2025-06-13T08:17:24","modified_gmt":"2025-06-13T08:17:24","slug":"how-many-atoms-of-oxygen-are-there-in-36-5-grams-of-potassium-nitrate-kno","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/13\/how-many-atoms-of-oxygen-are-there-in-36-5-grams-of-potassium-nitrate-kno\/","title":{"rendered":"How many atoms of oxygen are there in 36.5 grams of potassium nitrate, KNO"},"content":{"rendered":"\n

How many atoms of oxygen are there in 36.5 grams of potassium nitrate, KNO
? [FW(KNO
) = 101.10 amu; N
= 6.02×10
] 5.56×10
atoms 6.28×10
atoms 6.52×10
atoms 5.28×10
atoms 6.85×10
atoms<\/p>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

To determine how many oxygen atoms<\/strong> are in 36.5 grams of potassium nitrate (KNO\u2083)<\/strong>, follow this step-by-step method used in textbooks:<\/p>\n\n\n\n

\n\n\n\n

Step 1: Understand the compound KNO\u2083<\/strong><\/h3>\n\n\n\n

The chemical formula of potassium nitrate (KNO\u2083) shows that each molecule contains 3 oxygen atoms<\/strong>.<\/p>\n\n\n\n

\n\n\n\n

Step 2: Calculate the number of moles of KNO\u2083<\/strong><\/h3>\n\n\n\n

We are given:<\/p>\n\n\n\n

    \n
  • Mass of KNO\u2083 = 36.5 g<\/li>\n\n\n\n
  • Formula weight (FW) of KNO\u2083 = 101.10 g\/mol<\/li>\n<\/ul>\n\n\n\n

    Moles of KNO\u2083=massformula weight=36.5101.10\u22480.3611 mol\\text{Moles of KNO\u2083} = \\frac{\\text{mass}}{\\text{formula weight}} = \\frac{36.5}{101.10} \\approx 0.3611\\ \\text{mol}Moles of KNO\u2083=formula weightmass\u200b=101.1036.5\u200b\u22480.3611 mol<\/p>\n\n\n\n

    \n\n\n\n

    Step 3: Use Avogadro’s number to find number of molecules<\/strong><\/h3>\n\n\n\n

    Avogadro\u2019s number is: 6.022\u00d71023 molecules\/mol6.022 \\times 10^{23}\\ \\text{molecules\/mol}6.022\u00d71023 molecules\/mol Number of molecules=0.3611 mol\u00d76.022\u00d71023=2.175\u00d71023 molecules\\text{Number of molecules} = 0.3611\\ \\text{mol} \\times 6.022 \\times 10^{23} = 2.175 \\times 10^{23}\\ \\text{molecules}Number of molecules=0.3611 mol\u00d76.022\u00d71023=2.175\u00d71023 molecules<\/p>\n\n\n\n

    \n\n\n\n

    Step 4: Multiply by 3 (oxygen atoms per molecule)<\/strong><\/h3>\n\n\n\n

    Oxygen atoms=2.175\u00d71023\u00d73=6.525\u00d71023 atoms\\text{Oxygen atoms} = 2.175 \\times 10^{23} \\times 3 = 6.525 \\times 10^{23}\\ \\text{atoms}Oxygen atoms=2.175\u00d71023\u00d73=6.525\u00d71023 atoms<\/p>\n\n\n\n

    \n\n\n\n

    \u2705 Final Answer:<\/strong><\/h3>\n\n\n\n

    6.52\u00d71023 atoms of oxygen\\boxed{6.52 \\times 10^{23}\\ \\text{atoms of oxygen}}6.52\u00d71023 atoms of oxygen\u200b<\/p>\n\n\n\n

    \n\n\n\n

    \ud83d\udcd8 Explanation<\/strong><\/h3>\n\n\n\n

    To calculate the number of oxygen atoms in a given mass of a compound, you must consider both the chemical formula<\/strong> and the molar relationships<\/strong> involved. Potassium nitrate (KNO\u2083) is composed of one potassium atom (K), one nitrogen atom (N), and three oxygen atoms (O)<\/strong>. Thus, for every 1 mole of KNO\u2083, there are 3 moles of oxygen atoms.<\/p>\n\n\n\n

    We start by converting the mass of potassium nitrate<\/strong> into moles<\/strong>, using the molar mass (101.10 g\/mol). For 36.5 grams, this gives about 0.3611 moles of KNO\u2083.<\/p>\n\n\n\n

    Using Avogadro\u2019s number<\/strong> (6.022 \u00d7 10\u00b2\u00b3), we then convert moles into molecules:
    0.3611 moles \u00d7 6.022 \u00d7 10\u00b2\u00b3 molecules\/mole \u2248 2.175 \u00d7 10\u00b2\u00b3 molecules of KNO\u2083.<\/p>\n\n\n\n

    Since each molecule has 3 oxygen atoms<\/strong>, we multiply by 3 to find the total number of oxygen atoms<\/strong>:
    2.175 \u00d7 10\u00b2\u00b3 \u00d7 3 = 6.525 \u00d7 10\u00b2\u00b3 atoms.<\/p>\n\n\n\n

    Therefore, 36.5 grams of potassium nitrate contains approximately 6.52 \u00d7 10\u00b2\u00b3 oxygen atoms<\/strong>, which matches the correct choice in the options.<\/p>\n\n\n\n

    \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

    How many atoms of oxygen are there in 36.5 grams of potassium nitrate, KNO? [FW(KNO) = 101.10 amu; N= 6.02×10] 5.56×10atoms 6.28×10atoms 6.52×10atoms 5.28×10atoms 6.85×10atoms The Correct Answer and Explanation is: To determine how many oxygen atoms are in 36.5 grams of potassium nitrate (KNO\u2083), follow this step-by-step method used in textbooks: Step 1: Understand […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-233563","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/233563","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=233563"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/233563\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=233563"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=233563"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=233563"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}