{"id":233571,"date":"2025-06-13T08:24:17","date_gmt":"2025-06-13T08:24:17","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=233571"},"modified":"2025-06-13T08:24:19","modified_gmt":"2025-06-13T08:24:19","slug":"oso4-nmo-2-nahso3-h2o-mg-thf-review-examples-vilika-reagents-select-a-reagent","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/13\/oso4-nmo-2-nahso3-h2o-mg-thf-review-examples-vilika-reagents-select-a-reagent\/","title":{"rendered":"OsO4, NMO 2. NaHSO3, H2O Mg, THF Review Examples Vilika Reagents Select a Reagent"},"content":{"rendered":"\n

OsO4, NMO 2. NaHSO3, H2O Mg, THF Review Examples Vilika Reagents Select a Reagent
OsO4, NMO 2. NaHSO3, H2O Mg, THF Review Examples Vilika Reagents Select a Reagent<\/p>\n\n\n\n

\"\"<\/figure>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

The correct answer identifies the central molecule and explains its function as a reagent in organic chemistry.<\/p>\n\n\n\n

Reagent Identification: meta<\/em>-Chloroperoxybenzoic Acid (m-CPBA)<\/strong><\/h3>\n\n\n\n

The chemical structure shown in the central box is meta<\/em>-chloroperoxybenzoic acid<\/strong>, a reagent commonly known by its abbreviation m-CPBA<\/strong>. It is a type of peroxy acid, characterized by the -C(=O)OOH functional group, which makes it a powerful and selective oxidizing agent.<\/p>\n\n\n\n

Primary Reaction: Epoxidation of Alkenes<\/strong><\/h3>\n\n\n\n

The principal application of m-CPBA in organic synthesis is the epoxidation<\/strong> of alkenes. This reaction involves the direct transfer of an oxygen atom from the peroxy acid to the carbon-carbon double bond of an alkene, forming a three-membered cyclic ether called an epoxide<\/strong> (or oxirane). The other product of the reaction is meta<\/em>-chlorobenzoic acid.<\/p>\n\n\n\n

Mechanism and Stereochemistry:<\/strong>
The epoxidation reaction with m-CPBA proceeds through a concerted mechanism<\/strong>, often referred to as the “butterfly mechanism.” In a single, simultaneous step, the alkene’s \u03c0 bond attacks the terminal, electrophilic oxygen of the peroxy acid, while the weak O-O bond breaks. This process occurs through a cyclic transition state, leading to the formation of the epoxide ring.<\/p>\n\n\n\n

A crucial feature of this mechanism is its stereospecificity<\/strong>. The stereochemistry of the starting alkene is preserved in the epoxide product. This means that a cis<\/em>-alkene will always yield a cis<\/em>-epoxide (where the substituents are on the same side of the epoxide ring), and a trans<\/em>-alkene will produce a trans<\/em>-epoxide. This high degree of stereochemical control makes m-CPBA an invaluable tool for synthetic chemists.<\/p>\n\n\n\n

Context with Other Displayed Reagents<\/strong><\/h3>\n\n\n\n

The image also displays other common reagent systems, each for a distinct transformation:<\/p>\n\n\n\n

    \n
  • 1. OsO4, NMO; 2. NaHSO3, H2O:<\/strong>\u00a0This is the reagent set for\u00a0syn<\/em>-dihydroxylation<\/strong>. It converts an alkene into a\u00a0cis<\/em>-1,2-diol by adding two hydroxyl (-OH) groups to the same face of the double bond.<\/li>\n\n\n\n
  • Mg, THF:<\/strong>\u00a0These reagents are used to form a\u00a0Grignard reagent<\/strong>\u00a0from an alkyl or aryl halide. This reaction creates a potent carbon nucleophile (R-MgX) essential for forming new carbon-carbon bonds.<\/li>\n<\/ul>\n\n\n\n
    \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

    OsO4, NMO 2. NaHSO3, H2O Mg, THF Review Examples Vilika Reagents Select a Reagent OsO4, NMO 2. NaHSO3, H2O Mg, THF Review Examples Vilika Reagents Select a Reagent The Correct Answer and Explanation is: The correct answer identifies the central molecule and explains its function as a reagent in organic chemistry. Reagent Identification: meta-Chloroperoxybenzoic Acid (m-CPBA) […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-233571","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/233571","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=233571"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/233571\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=233571"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=233571"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=233571"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}