{"id":233581,"date":"2025-06-13T08:32:44","date_gmt":"2025-06-13T08:32:44","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=233581"},"modified":"2025-06-13T08:32:47","modified_gmt":"2025-06-13T08:32:47","slug":"na-h20-naoh-h2-balance-the-equation-in-algebric-method","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/13\/na-h20-naoh-h2-balance-the-equation-in-algebric-method\/","title":{"rendered":"Na + H20 -> NaOH+ H2 ( balance the equation in algebric method"},"content":{"rendered":"\n<p>Na + H20 -> NaOH+ H2 ( balance the equation in algebric method<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-0-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p><strong>Balanced Chemical Equation (Using Algebraic Method):<\/strong><\/p>\n\n\n\n<p>Unbalanced equation:<br>Na + H\u2082O \u2192 NaOH + H\u2082<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step-by-Step Algebraic Balancing Method<\/strong><\/h3>\n\n\n\n<p>We assign algebraic variables to each compound:<\/p>\n\n\n\n<p>Let:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>aaa = number of Na atoms<\/li>\n\n\n\n<li>bbb = number of H\u2082O molecules<\/li>\n\n\n\n<li>ccc = number of NaOH molecules<\/li>\n\n\n\n<li>ddd = number of H\u2082 molecules<\/li>\n<\/ul>\n\n\n\n<p>So the equation becomes:<br>aNa+bH2O\u2192cNaOH+dH2a \\text{Na} + b \\text{H}_2\\text{O} \\rightarrow c \\text{NaOH} + d \\text{H}_2aNa+bH2\u200bO\u2192cNaOH+dH2\u200b<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p>Now write equations based on atom conservation:<\/p>\n\n\n\n<p><strong>1. Sodium (Na):<\/strong><br>Each Na atom appears once on both sides:<br>a=ca = ca=c<\/p>\n\n\n\n<p><strong>2. Hydrogen (H):<\/strong><br>Left side: Each H\u2082O has 2 H atoms \u2192 total H atoms = 2b<br>Right side:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Each NaOH has 1 H \u2192 contributes ccc<\/li>\n\n\n\n<li>Each H\u2082 molecule has 2 H atoms \u2192 contributes 2d2d2d<br>So:<br>2b=c+2d2b = c + 2d2b=c+2d<\/li>\n<\/ul>\n\n\n\n<p><strong>3. Oxygen (O):<\/strong><br>Each H\u2082O has 1 O \u2192 total O = b<br>Each NaOH has 1 O \u2192 total O = c<br>So:<br>b=cb = cb=c<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p>Now solve the system of equations:<\/p>\n\n\n\n<p>From equation 1:<br>a=ca = ca=c<\/p>\n\n\n\n<p>From equation 3:<br>b=cb = cb=c<\/p>\n\n\n\n<p>So, substitute a=b=ca = b = ca=b=c into equation 2:<\/p>\n\n\n\n<p>2b=b+2d2b = b + 2d2b=b+2d<\/p>\n\n\n\n<p>Solve for ddd:<br>2b\u2212b=2d2b &#8211; b = 2d2b\u2212b=2d<br>b=2db = 2db=2d<br>\u21d2 d=b2d = \\frac{b}{2}d=2b\u200b<\/p>\n\n\n\n<p>Since the smallest whole number solution requires no fractions, let\u2019s choose b=2b = 2b=2:<\/p>\n\n\n\n<p>Then:<br>a=b=c=2a = b = c = 2a=b=c=2,<br>d=22=1d = \\frac{2}{2} = 1d=22\u200b=1<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Balanced Equation:<\/strong><\/h3>\n\n\n\n<p><strong>2Na + 2H\u2082O \u2192 2NaOH + H\u2082<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation (Like in Textbooks):<\/strong><\/h3>\n\n\n\n<p>The reaction between sodium metal (Na) and water (H\u2082O) produces sodium hydroxide (NaOH) and hydrogen gas (H\u2082). To ensure the law of conservation of mass is upheld, the equation must be balanced so that the number of atoms for each element is the same on both sides.<\/p>\n\n\n\n<p>Using algebraic variables, each substance is assigned a coefficient. Equations are formed by matching the total number of atoms of each element on both sides. Solving the system shows that two sodium atoms react with two water molecules to produce two sodium hydroxide molecules and one hydrogen molecule. This maintains the correct ratio of sodium, hydrogen, and oxygen atoms.<\/p>\n\n\n\n<p>The final balanced chemical equation is:<br><strong>2Na + 2H\u2082O \u2192 2NaOH + H\u2082<\/strong>.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-275.jpeg\" alt=\"\" class=\"wp-image-233582\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Na + H20 -> NaOH+ H2 ( balance the equation in algebric method The Correct Answer and Explanation is: Balanced Chemical Equation (Using Algebraic Method): Unbalanced equation:Na + H\u2082O \u2192 NaOH + H\u2082 Step-by-Step Algebraic Balancing Method We assign algebraic variables to each compound: Let: So the equation becomes:aNa+bH2O\u2192cNaOH+dH2a \\text{Na} + b \\text{H}_2\\text{O} \\rightarrow c [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-233581","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/233581","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=233581"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/233581\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=233581"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=233581"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=233581"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}