Correct Answer:<\/strong> The conjugate base of H\u2082SO\u2083<\/strong> is HSO\u2083\u207b<\/strong><\/p>\n\n\n\n Explanation:<\/strong><\/p>\n\n\n\n In acid-base chemistry, a conjugate base<\/strong> is what remains after an acid donates a proton (H\u207a). The concept of conjugate acid-base pairs is central to the Br\u00f8nsted\u2013Lowry theory<\/strong>, where:<\/p>\n\n\n\n Acid<\/strong> \u2192 loses a proton (H\u207a) \u2192 becomes its conjugate base<\/strong><\/p>\n<\/blockquote>\n\n\n\n Now consider the given acid: This molecule has two hydrogen atoms<\/strong> that are ionizable (protons that can be donated). When H\u2082SO\u2083<\/strong> loses one proton (H\u207a)<\/strong>, it forms:H\u2082SO\u2083\u2192HSO\u2083\u207b+H\u207a\\text{H\u2082SO\u2083} \\rightarrow \\text{HSO\u2083\u207b} + \\text{H\u207a}H\u2082SO\u2083\u2192HSO\u2083\u207b+H\u207a<\/p>\n\n\n\n This resulting species HSO\u2083\u207b<\/strong> is the conjugate base<\/strong> of H\u2082SO\u2083<\/strong>, because it\u2019s the particle that forms when H\u2082SO\u2083<\/strong> acts as an acid by donating one hydrogen ion.<\/p>\n\n\n\n It is important to note that HSO\u2083\u207b<\/strong> can also act as an acid itself and lose another proton to form SO\u2083\u00b2\u207b<\/strong>, which would then be its own conjugate base:HSO\u2083\u207b\u2192SO\u2083\u00b2\u207b+H\u207a\\text{HSO\u2083\u207b} \\rightarrow \\text{SO\u2083\u00b2\u207b} + \\text{H\u207a}HSO\u2083\u207b\u2192SO\u2083\u00b2\u207b+H\u207a<\/p>\n\n\n\n However, since the question asks for the conjugate base of H\u2082SO\u2083<\/strong>, the answer is the species formed after it donates just one proton<\/strong>, which is HSO\u2083\u207b<\/strong>.<\/p>\n\n\n\n In summary:<\/p>\n\n\n\n Understanding conjugate pairs is essential in acid-base reactions, buffers, and pH calculations.<\/p>\n\n\n\n What is the conjugate base of H2SO3 ? Express your answer as a chemical formula The Correct Answer and Explanation is: Correct Answer: The conjugate base of H\u2082SO\u2083 is HSO\u2083\u207b Explanation: In acid-base chemistry, a conjugate base is what remains after an acid donates a proton (H\u207a). The concept of conjugate acid-base pairs is central […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-233813","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/233813","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=233813"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/233813\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=233813"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=233813"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=233813"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
\n\n\n\n\n
H\u2082SO\u2083<\/strong> (sulfurous acid)<\/p>\n\n\n\n\n
![\"\"](\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-336.jpeg\")
<\/figure>\n","protected":false},"excerpt":{"rendered":"