{"id":234031,"date":"2025-06-13T17:04:36","date_gmt":"2025-06-13T17:04:36","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=234031"},"modified":"2025-06-13T17:04:38","modified_gmt":"2025-06-13T17:04:38","slug":"circle-in-the-aromatic-compound-nh-nh-which-one-of-the-following-compounds-is-more-reactive-towards-electrophilic-aromatic-substitution","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/13\/circle-in-the-aromatic-compound-nh-nh-which-one-of-the-following-compounds-is-more-reactive-towards-electrophilic-aromatic-substitution\/","title":{"rendered":"Circle In the aromatic compound NH NH Which one of the following compounds is more reactive towards Electrophilic Aromatic Substitution"},"content":{"rendered":"\n

Circle In the aromatic compound NH NH Which one of the following compounds is more reactive towards Electrophilic Aromatic Substitution? PhCO2H PhCCl3 PhCN PhCH3 PhCl<\/p>\n\n\n\n

\"\"<\/figure>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

Here are the correct answers and explanations for the two questions.<\/p>\n\n\n\n

\n\n\n\n

Question 1: Circle the aromatic compound<\/strong><\/h3>\n\n\n\n

Correct Answer: C<\/strong><\/p>\n\n\n\n

Explanation:<\/strong><\/p>\n\n\n\n

A compound is considered aromatic if it adheres to H\u00fcckel’s criteria for aromaticity:<\/p>\n\n\n\n

    \n
  1. It must be\u00a0cyclic<\/strong>.<\/li>\n\n\n\n
  2. It must be\u00a0planar<\/strong>.<\/li>\n\n\n\n
  3. It must be\u00a0fully conjugated<\/strong>, meaning every atom in the ring must have an available p-orbital.<\/li>\n\n\n\n
  4. It must satisfy\u00a0H\u00fcckel’s rule<\/strong>, containing\u00a0(4n + 2) \u03c0 electrons<\/strong>, where ‘n’ is a non-negative integer (0, 1, 2, etc.).<\/li>\n<\/ol>\n\n\n\n

    Let’s analyze the given options:<\/p>\n\n\n\n

      \n
    • A and B:<\/strong>\u00a0These six-membered rings are not fully conjugated. They contain sp\u00b3 hybridized carbon atoms that break the continuous overlap of p-orbitals around the ring. Therefore, they are not aromatic.<\/li>\n\n\n\n
    • C (Furan):<\/strong>\u00a0This compound is cyclic and planar. It is fully conjugated, as the oxygen atom has a lone pair of electrons in a p-orbital that participates in the ring’s \u03c0 system. It contains two double bonds (4 \u03c0 electrons) and one lone pair from the oxygen atom (2 \u03c0 electrons), for a total of\u00a06 \u03c0 electrons<\/strong>. This satisfies H\u00fcckel’s rule for n=1 (4(1) + 2 = 6). Thus, furan is an\u00a0aromatic compound<\/strong>.<\/li>\n\n\n\n
    • D (Azete):<\/strong>\u00a0This four-membered ring is cyclic, planar, and conjugated. However, it contains\u00a04 \u03c0 electrons<\/strong>. This follows the 4n rule (for n=1), making it antiaromatic and highly unstable.<\/li>\n\n\n\n
    • E (Cyclopentadienyl cation):<\/strong>\u00a0This five-membered ring is cyclic, planar, and conjugated but only has\u00a04 \u03c0 electrons<\/strong>. Like compound D, it is antiaromatic.<\/li>\n<\/ul>\n\n\n\n

      Therefore, compound C<\/strong> is the only aromatic compound among the choices.<\/p>\n\n\n\n

      \n\n\n\n

      Question 2: Which one of the following compounds is more reactive towards Electrophilic Aromatic Substitution?<\/strong><\/h3>\n\n\n\n

      Correct Answer: D (PhCH\u2083)<\/strong><\/p>\n\n\n\n

      Explanation:<\/strong><\/p>\n\n\n\n

      Electrophilic Aromatic Substitution (EAS) is a reaction in which an electrophile (an electron-seeking species) attacks an electron-rich aromatic ring. The reactivity of a substituted benzene ring in an EAS reaction depends on the nature of the substituent attached to it.<\/p>\n\n\n\n

        \n
      • Activating groups<\/strong>\u00a0are electron-donating groups (EDGs). They increase the electron density of the benzene ring, making it more nucleophilic and thus\u00a0more reactive<\/strong>\u00a0towards electrophiles than benzene itself.<\/li>\n\n\n\n
      • Deactivating groups<\/strong>\u00a0are electron-withdrawing groups (EWGs). They decrease the electron density of the ring, making it less nucleophilic and\u00a0less reactive<\/strong>\u00a0towards electrophiles.<\/li>\n<\/ul>\n\n\n\n

        Let’s classify the substituents for each compound:<\/p>\n\n\n\n

          \n
        • A (PhCO\u2082H):<\/strong>\u00a0The carboxylic acid group (-CO\u2082H) is a strong electron-withdrawing group and is\u00a0strongly deactivating<\/strong>.<\/li>\n\n\n\n
        • B (PhCCl\u2083):<\/strong>\u00a0The trichloromethyl group (-CCl\u2083) is strongly electron-withdrawing due to the powerful inductive effect of the three chlorine atoms, making it\u00a0strongly deactivating<\/strong>.<\/li>\n\n\n\n
        • C (PhCN):<\/strong>\u00a0The nitrile group (-CN) is a strong electron-withdrawing group and is\u00a0strongly deactivating<\/strong>.<\/li>\n\n\n\n
        • D (PhCH\u2083):<\/strong>\u00a0The methyl group (-CH\u2083) is an electron-donating group (via induction and hyperconjugation). It is an\u00a0activating group<\/strong>.<\/li>\n\n\n\n
        • E (PhCl):<\/strong>\u00a0The chloro group (-Cl) is a halogen. Halogens are electron-withdrawing via induction but electron-donating via resonance. The inductive effect dominates, making them net\u00a0deactivating<\/strong>\u00a0(though they are ortho-, para-directing).<\/li>\n<\/ul>\n\n\n\n

          Comparing the options, toluene (PhCH\u2083<\/strong>) is the only compound with an activating group. All other compounds possess deactivating groups, which make their rings less reactive than benzene. Since the methyl group in toluene increases the ring’s electron density, it is the most reactive compound towards electrophilic attack.<\/p>\n\n\n\n

          The general order of reactivity is:
          PhCH\u2083 (D) > PhCl (E) > PhCO\u2082H (A) \u2248 PhCN (C) \u2248 PhCCl\u2083 (B)<\/strong>thumb_upthumb_down<\/p>\n\n\n\n

          \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

          Circle In the aromatic compound NH NH Which one of the following compounds is more reactive towards Electrophilic Aromatic Substitution? PhCO2H PhCCl3 PhCN PhCH3 PhCl The Correct Answer and Explanation is: Here are the correct answers and explanations for the two questions. Question 1: Circle the aromatic compound Correct Answer: C Explanation: A compound is […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-234031","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/234031","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=234031"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/234031\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=234031"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=234031"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=234031"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}