{"id":234329,"date":"2025-06-14T04:36:10","date_gmt":"2025-06-14T04:36:10","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=234329"},"modified":"2025-06-14T04:36:12","modified_gmt":"2025-06-14T04:36:12","slug":"25-c-meoh-br-draw-the-major-products-of-the-reaction","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/14\/25-c-meoh-br-draw-the-major-products-of-the-reaction\/","title":{"rendered":"25 \u00b0C MeOH Br Draw the major product(s) of the reaction"},"content":{"rendered":"\n

25 \u00b0C MeOH Br Draw the major product(s) of the reaction. CH
H
C CH
Edit Drawing Draw the minor product(s) of the reaction. Draw Your Solution The major product(s) is\/are formed by an SN1 mechanism, the other mechanism that gives minor product(s) is E1<\/p>\n\n\n\n

\"\"<\/figure>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

Based on the provided reaction, here is the complete and correct solution.<\/p>\n\n\n\n

Analysis of the Reaction:<\/strong><\/p>\n\n\n\n

    \n
  1. Substrate:<\/strong>\u00a0The starting material is (3R)-3-bromo-3-methylhexane. The bromine atom is attached to a tertiary carbon, which is sterically hindered for SN2 reactions but readily forms a stable tertiary carbocation.<\/li>\n\n\n\n
  2. Reagent\/Solvent:<\/strong>\u00a0Methanol (MeOH) is a weak nucleophile and a weak base. It is also a polar protic solvent, which stabilizes the carbocation intermediate necessary for SN1 and E1 reactions.<\/li>\n\n\n\n
  3. Conditions:<\/strong>\u00a0The reaction is run at 25 \u00b0C, which is a relatively low temperature. Elimination reactions (E1) are favored by heat, while substitution reactions (SN1) are favored at lower temperatures.<\/li>\n<\/ol>\n\n\n\n

    Conclusion on Mechanism:<\/strong>
    Given the tertiary substrate, weak nucleophile\/base, and low temperature, the reaction will proceed via a competition between SN1 and E1 mechanisms. The SN1 pathway will be favored, producing the major product(s)<\/strong>, while the E1 pathway will be the minor pathway<\/strong>.<\/p>\n\n\n\n

    \n\n\n\n

    Corrected Solution:<\/strong><\/h3>\n\n\n\n

    Draw the major product(s) of the reaction.<\/strong><\/p>\n\n\n\n

    The major product is formed via an SN1 mechanism. The reaction proceeds through a planar tertiary carbocation intermediate, which loses its original stereochemistry. The nucleophile, methanol, can then attack from either face of the carbocation, resulting in a racemic mixture of the substitution product.<\/p>\n\n\n\n

      \n
    • Major Product:<\/strong>\u00a03-methoxy-3-methylhexane (racemic mixture)<\/li>\n<\/ul>\n\n\n\n

      Draw the minor product(s) of the reaction.<\/strong><\/p>\n\n\n\n

      The minor products are formed via an E1 mechanism. The weak base (methanol) removes a proton from a carbon adjacent (\u03b2-carbon) to the carbocation. There are two different types of \u03b2-hydrogens (on C2 and C4), leading to two constitutional isomers. According to Zaitsev’s rule, the more substituted alkene is favored. In this case, both possible alkenes are trisubstituted, so a mixture of both is expected.<\/p>\n\n\n\n

        \n
      • Minor Products:<\/strong>\u00a03-methylhex-3-ene and 3-methylhex-2-ene<\/li>\n<\/ul>\n\n\n\n

        Complete the statement below:<\/strong><\/p>\n\n\n\n

        The major product(s) is\/are formed by an SN1<\/strong> mechanism, the other mechanism that gives minor product(s) is E1<\/strong>.thumb_upthumb_down<\/p>\n\n\n\n

        \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

        25 \u00b0C MeOH Br Draw the major product(s) of the reaction. CHHC CHEdit Drawing Draw the minor product(s) of the reaction. Draw Your Solution The major product(s) is\/are formed by an SN1 mechanism, the other mechanism that gives minor product(s) is E1 The Correct Answer and Explanation is: Based on the provided reaction, here is […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-234329","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/234329","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=234329"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/234329\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=234329"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=234329"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=234329"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}