{"id":234436,"date":"2025-06-14T06:19:36","date_gmt":"2025-06-14T06:19:36","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=234436"},"modified":"2025-06-14T06:19:38","modified_gmt":"2025-06-14T06:19:38","slug":"which-chemical-equation-below-is-balanced-to-correctly-represent-the-law-of-conservation-of-mass","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/14\/which-chemical-equation-below-is-balanced-to-correctly-represent-the-law-of-conservation-of-mass\/","title":{"rendered":"Which chemical equation below is balanced to correctly represent the Law of Conservation of Mass"},"content":{"rendered":"\n<p>Which chemical equation below is balanced to correctly represent the Law of Conservation of Mass? 04 Al + 3O2 + 2 Al2O3 O2 AL + O2 + 2 Al2O3 O AL + O2 + Al2O3<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p><strong>Correct Answer:<\/strong><br><strong>4 Al + 3 O\u2082 \u2192 2 Al\u2082O\u2083<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation (Like in Textbooks):<\/strong><\/h3>\n\n\n\n<p>To determine which chemical equation correctly represents the <strong>Law of Conservation of Mass<\/strong>, we must understand what this law means. The <strong>Law of Conservation of Mass<\/strong> states that <strong>matter cannot be created or destroyed in a chemical reaction<\/strong>. Therefore, the <strong>total number of atoms of each element must be the same on both sides of the equation<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step-by-Step Analysis:<\/h3>\n\n\n\n<p>Let\u2019s analyze the correct chemical reaction involving aluminum (Al) and oxygen gas (O\u2082) forming aluminum oxide (Al\u2082O\u2083):<\/p>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Unbalanced Reaction:<\/strong><\/h4>\n\n\n\n<p><strong>Al + O\u2082 \u2192 Al\u2082O\u2083<\/strong><\/p>\n\n\n\n<p>Now, let\u2019s count the atoms on each side:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Left Side:<\/strong>\n<ul class=\"wp-block-list\">\n<li>Al: 1 atom<\/li>\n\n\n\n<li>O: 2 atoms (since O\u2082 is diatomic)<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Right Side:<\/strong>\n<ul class=\"wp-block-list\">\n<li>Al: 2 atoms (in Al\u2082O\u2083)<\/li>\n\n\n\n<li>O: 3 atoms (in Al\u2082O\u2083)<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<p>This equation is <strong>not balanced<\/strong> because the number of aluminum and oxygen atoms are not equal on both sides.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Balancing the Equation:<\/strong><\/h3>\n\n\n\n<p>To balance the atoms:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Balance Aluminum (Al):<\/strong>\n<ul class=\"wp-block-list\">\n<li>On the right, Al\u2082O\u2083 has 2 aluminum atoms.<\/li>\n\n\n\n<li>Multiply Al on the left by 4 to balance with 2 Al\u2082O\u2083 molecules:<br><strong>4 Al + O\u2082 \u2192 2 Al\u2082O\u2083<\/strong><\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Balance Oxygen (O):<\/strong>\n<ul class=\"wp-block-list\">\n<li>2 Al\u2082O\u2083 contains 2 \u00d7 3 = <strong>6 oxygen atoms<\/strong>.<\/li>\n\n\n\n<li>To get 6 oxygen atoms from O\u2082, we need 3 O\u2082 molecules:<br><strong>4 Al + 3 O\u2082 \u2192 2 Al\u2082O\u2083<\/strong><\/li>\n<\/ul>\n<\/li>\n<\/ol>\n\n\n\n<p>Now both sides have:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Aluminum:<\/strong> 4 atoms<\/li>\n\n\n\n<li><strong>Oxygen:<\/strong> 6 atoms<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Final Balanced Equation:<\/strong><\/h3>\n\n\n\n<p><strong>4 Al + 3 O\u2082 \u2192 2 Al\u2082O\u2083<\/strong><\/p>\n\n\n\n<p>This balanced chemical equation correctly follows the <strong>Law of Conservation of Mass<\/strong>, ensuring that the <strong>number of atoms of each element is equal<\/strong> on both sides of the reaction.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-408.jpeg\" alt=\"\" class=\"wp-image-234437\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Which chemical equation below is balanced to correctly represent the Law of Conservation of Mass? 04 Al + 3O2 + 2 Al2O3 O2 AL + O2 + 2 Al2O3 O AL + O2 + Al2O3 The Correct Answer and Explanation is: Correct Answer:4 Al + 3 O\u2082 \u2192 2 Al\u2082O\u2083 Explanation (Like in Textbooks): To [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-234436","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/234436","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=234436"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/234436\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=234436"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=234436"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=234436"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}