{"id":234698,"date":"2025-06-14T11:40:46","date_gmt":"2025-06-14T11:40:46","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=234698"},"modified":"2025-06-14T11:40:48","modified_gmt":"2025-06-14T11:40:48","slug":"the-chemical-formula-for-calcium-hydroxide-is-caoh","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/14\/the-chemical-formula-for-calcium-hydroxide-is-caoh\/","title":{"rendered":"The chemical formula for calcium hydroxide is: Ca(OH)"},"content":{"rendered":"\n<p>The chemical formula for calcium hydroxide is: Ca(OH)<br>Calculate the molar mass of calcium hydroxide. Round your answer to 2 decimal places. g\\cdot mol<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/image-491.png\" alt=\"\" class=\"wp-image-234699\"\/><\/figure>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p><strong>74.09<\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>To determine the molar mass of a chemical compound, the process involves summing the atomic masses of all the atoms present in its chemical formula. The result is expressed in grams per mole (&nbsp;g\/mol&nbsp;or g\u00b7mol\u207b\u00b9).<\/p>\n\n\n\n<p><strong>1. Analyze the Chemical Formula<\/strong><\/p>\n\n\n\n<p>The given chemical formula for calcium hydroxide is Ca(OH)\u2082. A breakdown of this formula reveals the number of atoms for each element:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Ca (Calcium):<\/strong>\u00a0There is one atom of calcium.<\/li>\n\n\n\n<li><strong>O (Oxygen):<\/strong>\u00a0The hydroxide group (OH) is in parentheses with a subscript of 2. This means the number of oxygen atoms is multiplied by two, resulting in two oxygen atoms.<\/li>\n\n\n\n<li><strong>H (Hydrogen):<\/strong>\u00a0Similarly, the subscript 2 applies to hydrogen, meaning there are two hydrogen atoms.<\/li>\n<\/ul>\n\n\n\n<p>In summary, one formula unit of Ca(OH)\u2082 contains 1 calcium atom, 2 oxygen atoms, and 2 hydrogen atoms.<\/p>\n\n\n\n<p><strong>2. Find the Atomic Masses<\/strong><\/p>\n\n\n\n<p>The next step is to obtain the standard atomic mass for each element from the periodic table. For precision, it is best to use values with several decimal places.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Atomic mass of Calcium (Ca) is approximately 40.078\u00a0g\/mol\u00a0.<\/li>\n\n\n\n<li>Atomic mass of Oxygen (O) is approximately 15.999\u00a0g\/mol\u00a0.<\/li>\n\n\n\n<li>Atomic mass of Hydrogen (H) is approximately 1.008\u00a0g\/mol\u00a0.<\/li>\n<\/ul>\n\n\n\n<p><strong>3. Calculate the Total Mass<\/strong><\/p>\n\n\n\n<p>Multiply the number of atoms of each element by its respective atomic mass and then sum the results.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Mass from Calcium: 1 \u00d7 40.078\u00a0g\/mol\u00a0= 40.078\u00a0g\/mol<\/li>\n\n\n\n<li>Mass from Oxygen: 2 \u00d7 15.999\u00a0g\/mol\u00a0= 31.998\u00a0g\/mol<\/li>\n\n\n\n<li>Mass from Hydrogen: 2 \u00d7 1.008\u00a0g\/mol\u00a0= 2.016\u00a0g\/mol<\/li>\n<\/ul>\n\n\n\n<p>Adding these values together gives the total molar mass:<br>Molar Mass = 40.078 + 31.998 + 2.016 = 74.092&nbsp;g\/mol&nbsp;.<\/p>\n\n\n\n<p><strong>4. Round to the Correct Number of Decimal Places<\/strong><\/p>\n\n\n\n<p>The problem requires the final answer to be rounded to two decimal places.<br>Rounding 74.092&nbsp;g\/mol&nbsp;gives&nbsp;<strong>74.09&nbsp;g\/mol&nbsp;<\/strong>.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-473.jpeg\" alt=\"\" class=\"wp-image-234700\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>The chemical formula for calcium hydroxide is: Ca(OH)Calculate the molar mass of calcium hydroxide. Round your answer to 2 decimal places. g\\cdot mol The Correct Answer and Explanation is: 74.09 Explanation: To determine the molar mass of a chemical compound, the process involves summing the atomic masses of all the atoms present in its chemical [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-234698","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/234698","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=234698"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/234698\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=234698"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=234698"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=234698"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}