{"id":234900,"date":"2025-06-14T14:46:24","date_gmt":"2025-06-14T14:46:24","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=234900"},"modified":"2025-06-14T14:46:26","modified_gmt":"2025-06-14T14:46:26","slug":"complete-the-skeleton-below-to-show-the-following-structure","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/14\/complete-the-skeleton-below-to-show-the-following-structure\/","title":{"rendered":"Complete the skeleton below to show the following structure"},"content":{"rendered":"\n<p>Complete the skeleton below to show the following structure: (1R,2R,5S)-2-bromo-5-ethylcyclohexanol. (6 Marks)<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/image-506.png\" alt=\"\" class=\"wp-image-234901\"\/><\/figure>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>To complete the skeletal structure of <strong>(1R,2R,5S)-2-bromo-5-ethylcyclohexanol<\/strong>, start by identifying the base molecule: <strong>cyclohexane<\/strong>, which is already provided.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step-by-Step Completion:<\/h3>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Number the cyclohexane ring<\/strong>:<br>Assign carbon 1 to the carbon bearing the hydroxyl (-OH) group. Number the ring clockwise to give the lowest possible locants to the substituents at positions 2 and 5.<\/li>\n\n\n\n<li><strong>Add substituents<\/strong>:\n<ul class=\"wp-block-list\">\n<li><strong>At C1<\/strong>: Attach the <strong>hydroxyl group (-OH)<\/strong> with <strong>R configuration<\/strong>. In a chair conformation, the <strong>equatorial position<\/strong> is generally more stable, but stereochemistry determines orientation. The R configuration here will place the OH <strong>axial up<\/strong> if the viewer assigns priorities accordingly.<\/li>\n\n\n\n<li><strong>At C2<\/strong>: Attach a <strong>bromine atom (Br)<\/strong> with <strong>R configuration<\/strong>. Based on stereochemistry rules, this places the Br group <strong>equatorial down<\/strong>.<\/li>\n\n\n\n<li><strong>At C5<\/strong>: Attach an <strong>ethyl group (-CH\u2082CH\u2083)<\/strong> with <strong>S configuration<\/strong>, which typically goes <strong>axial down<\/strong>.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Maintain 3D stereochemistry<\/strong>:<br>Use solid wedges (coming out of the plane) and dashed wedges (going behind the plane) to indicate chiral centers:\n<ul class=\"wp-block-list\">\n<li>C1: OH on a <strong>solid wedge up<\/strong><\/li>\n\n\n\n<li>C2: Br on a <strong>solid wedge down<\/strong><\/li>\n\n\n\n<li>C5: Ethyl group on a <strong>dashed wedge down<\/strong><\/li>\n<\/ul>\n<\/li>\n<\/ol>\n\n\n\n<h3 class=\"wp-block-heading\">Final Answer Description:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The ring is cyclohexane.<\/li>\n\n\n\n<li>OH group is on carbon 1 with R configuration (solid wedge).<\/li>\n\n\n\n<li>Br is on carbon 2 with R configuration (solid wedge or placed to reflect spatial orientation).<\/li>\n\n\n\n<li>Ethyl group is on carbon 5 with S configuration (dashed wedge).<\/li>\n<\/ul>\n\n\n\n<p>This ensures the structure reflects the stereochemistry <strong>(1R,2R,5S)<\/strong> and matches the molecular name <strong>2-bromo-5-ethylcyclohexanol<\/strong>. The skeletal structure should be a proper 3D representation with appropriate wedges to reflect chirality.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-523.jpeg\" alt=\"\" class=\"wp-image-234902\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Complete the skeleton below to show the following structure: (1R,2R,5S)-2-bromo-5-ethylcyclohexanol. (6 Marks) The Correct Answer and Explanation is: To complete the skeletal structure of (1R,2R,5S)-2-bromo-5-ethylcyclohexanol, start by identifying the base molecule: cyclohexane, which is already provided. Step-by-Step Completion: Final Answer Description: This ensures the structure reflects the stereochemistry (1R,2R,5S) and matches the molecular name 2-bromo-5-ethylcyclohexanol. [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-234900","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/234900","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=234900"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/234900\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=234900"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=234900"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=234900"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}