{"id":234954,"date":"2025-06-14T17:25:36","date_gmt":"2025-06-14T17:25:36","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=234954"},"modified":"2025-06-14T17:25:38","modified_gmt":"2025-06-14T17:25:38","slug":"density-determinations-true-density-of-aluminum-2-70-g-cma%c2%b3-weight-of-your-aluminum-26-975-g-part-4-aluminum-displacement","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/14\/density-determinations-true-density-of-aluminum-2-70-g-cma%c2%b3-weight-of-your-aluminum-26-975-g-part-4-aluminum-displacement\/","title":{"rendered":"Density Determinations True Density of Aluminum: 2.70 g\/cm\u00c2\u00b3 Weight of Your Aluminum: 26.975 g PART 4: Aluminum Displacement"},"content":{"rendered":"\n<p>Density Determinations True Density of Aluminum: 2.70 g\/cm\u00c2\u00b3 Weight of Your Aluminum: 26.975 g PART 4: Aluminum Displacement Method Trial 1: 40.0 mL Trial 2: 42.5 mL Trial 3: 51.3 mL Initial water volume in cylinder: 51.5 mL Final water volume in cylinder: 54.2 mL Volume of rod: 62.5 mL Density of aluminum rod: 0.826 g\/mL Percent error in value (NOTE: mL cm\u00c2\u00b3)<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/image-511.png\" alt=\"\" class=\"wp-image-234955\"\/><\/figure>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-0-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>Let\u2019s calculate the missing values step by step using the given data:<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Volume of rod (by displacement method)<\/strong><\/h3>\n\n\n\n<p>The volume of the rod is calculated by subtracting the initial water volume from the final water volume: Volume&nbsp;of&nbsp;rod=Final&nbsp;volume\u2212Initial&nbsp;volume\\text{Volume of rod} = \\text{Final volume} &#8211; \\text{Initial volume}Volume&nbsp;of&nbsp;rod=Final&nbsp;volume\u2212Initial&nbsp;volume<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Trial 1<\/strong>: 51.5\u00a0mL\u221240.0\u00a0mL=11.5\u00a0mL51.5\\ \\text{mL} &#8211; 40.0\\ \\text{mL} = 11.5\\ \\text{mL}51.5\u00a0mL\u221240.0\u00a0mL=11.5\u00a0mL<\/li>\n\n\n\n<li><strong>Trial 2<\/strong>: 54.2\u00a0mL\u221242.5\u00a0mL=11.7\u00a0mL54.2\\ \\text{mL} &#8211; 42.5\\ \\text{mL} = 11.7\\ \\text{mL}54.2\u00a0mL\u221242.5\u00a0mL=11.7\u00a0mL<\/li>\n\n\n\n<li><strong>Trial 3<\/strong>: 62.5\u00a0mL\u221251.3\u00a0mL=11.2\u00a0mL62.5\\ \\text{mL} &#8211; 51.3\\ \\text{mL} = 11.2\\ \\text{mL}62.5\u00a0mL\u221251.3\u00a0mL=11.2\u00a0mL<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Density of aluminum rod<\/strong><\/h3>\n\n\n\n<p>Density is calculated using the formula: Density=MassVolume\\text{Density} = \\frac{\\text{Mass}}{\\text{Volume}}Density=VolumeMass\u200b<\/p>\n\n\n\n<p>Given mass = 26.975 g<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Trial 1<\/strong>: 26.97511.5=2.3457\u00a0g\/mL\\frac{26.975}{11.5} = 2.3457\\ \\text{g\/mL}11.526.975\u200b=2.3457\u00a0g\/mL<\/li>\n\n\n\n<li><strong>Trial 2<\/strong>: 26.97511.7=2.3056\u00a0g\/mL\\frac{26.975}{11.7} = 2.3056\\ \\text{g\/mL}11.726.975\u200b=2.3056\u00a0g\/mL<\/li>\n\n\n\n<li><strong>Trial 3<\/strong>: 26.97511.2=2.4085\u00a0g\/mL\\frac{26.975}{11.2} = 2.4085\\ \\text{g\/mL}11.226.975\u200b=2.4085\u00a0g\/mL<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Percent error calculation<\/strong><\/h3>\n\n\n\n<p>Percent error is determined by: Percent&nbsp;Error=\u2223Measured\u2212True\u2223True\u00d7100\\text{Percent Error} = \\frac{|\\text{Measured} &#8211; \\text{True}|}{\\text{True}} \\times 100Percent&nbsp;Error=True\u2223Measured\u2212True\u2223\u200b\u00d7100<\/p>\n\n\n\n<p>True density = 2.70 g\/mL<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Trial 1<\/strong>: \u22232.3457\u22122.70\u22232.70\u00d7100=13.11%\\frac{|2.3457 &#8211; 2.70|}{2.70} \\times 100 = 13.11\\%2.70\u22232.3457\u22122.70\u2223\u200b\u00d7100=13.11%<\/li>\n\n\n\n<li><strong>Trial 2<\/strong>: \u22232.3056\u22122.70\u22232.70\u00d7100=14.60%\\frac{|2.3056 &#8211; 2.70|}{2.70} \\times 100 = 14.60\\%2.70\u22232.3056\u22122.70\u2223\u200b\u00d7100=14.60%<\/li>\n\n\n\n<li><strong>Trial 3<\/strong>: \u22232.4085\u22122.70\u22232.70\u00d7100=10.81%\\frac{|2.4085 &#8211; 2.70|}{2.70} \\times 100 = 10.81\\%2.70\u22232.4085\u22122.70\u2223\u200b\u00d7100=10.81%<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Summary Table<\/strong><\/h3>\n\n\n\n<figure class=\"wp-block-table\"><table class=\"has-fixed-layout\"><thead><tr><th><\/th><th>Trial 1<\/th><th>Trial 2<\/th><th>Trial 3<\/th><\/tr><\/thead><tbody><tr><td>Volume of rod (mL)<\/td><td>11.5<\/td><td>11.7<\/td><td>11.2<\/td><\/tr><tr><td>Density (g\/mL)<\/td><td>2.3457<\/td><td>2.3056<\/td><td>2.4085<\/td><\/tr><tr><td>Percent error (%)<\/td><td>13.11<\/td><td>14.60<\/td><td>10.81<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation<\/strong><\/h3>\n\n\n\n<p>The density determination of aluminum through the displacement method depends on accurate measurements of water displacement and mass. The volume of the rod is calculated from the difference between the final and initial water levels. This value directly affects the density calculation, as density is the ratio of mass to volume. Small deviations in volume readings result in noticeable changes in calculated density. Percent error helps evaluate the accuracy of these results compared to the true density of aluminum. The percent error values show deviations, likely caused by experimental errors such as parallax in reading the meniscus, air bubbles clinging to the submerged sample, or incomplete immersion of the rod.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-536.jpeg\" alt=\"\" class=\"wp-image-234956\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Density Determinations True Density of Aluminum: 2.70 g\/cm\u00c2\u00b3 Weight of Your Aluminum: 26.975 g PART 4: Aluminum Displacement Method Trial 1: 40.0 mL Trial 2: 42.5 mL Trial 3: 51.3 mL Initial water volume in cylinder: 51.5 mL Final water volume in cylinder: 54.2 mL Volume of rod: 62.5 mL Density of aluminum rod: 0.826 [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-234954","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/234954","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=234954"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/234954\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=234954"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=234954"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=234954"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}