{"id":235100,"date":"2025-06-15T01:57:12","date_gmt":"2025-06-15T01:57:12","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=235100"},"modified":"2025-06-15T01:57:15","modified_gmt":"2025-06-15T01:57:15","slug":"name-the-following-ionic-compounds-2","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/15\/name-the-following-ionic-compounds-2\/","title":{"rendered":"Name the following ionic compounds."},"content":{"rendered":"\n<p>Name the following ionic compounds. 1. BaCrO4 2. Ca(OH)2 3. KNO2 4. (NH4)3PO4 5. CuC2H3O2 6. (NH4)2SO3 7. Sb(ClO3)3 8. CrF3 9. CuCO3 10. Ag2C2O4 Write the formula for the following ionic comp 11. vanadium (III) fluoride<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-0-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Names of the Ionic Compounds:<\/h3>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>BaCrO\u2084<\/strong> \u2013 Barium chromate<\/li>\n\n\n\n<li><strong>Ca(OH)\u2082<\/strong> \u2013 Calcium hydroxide<\/li>\n\n\n\n<li><strong>KNO\u2082<\/strong> \u2013 Potassium nitrite<\/li>\n\n\n\n<li><strong>(NH\u2084)\u2083PO\u2084<\/strong> \u2013 Ammonium phosphate<\/li>\n\n\n\n<li><strong>CuC\u2082H\u2083O\u2082<\/strong> \u2013 Copper(I) acetate<\/li>\n\n\n\n<li><strong>(NH\u2084)\u2082SO\u2083<\/strong> \u2013 Ammonium sulfite<\/li>\n\n\n\n<li><strong>Sb(ClO\u2083)\u2083<\/strong> \u2013 Antimony(III) chlorate<\/li>\n\n\n\n<li><strong>CrF\u2083<\/strong> \u2013 Chromium(III) fluoride<\/li>\n\n\n\n<li><strong>CuCO\u2083<\/strong> \u2013 Copper(II) carbonate<\/li>\n\n\n\n<li><strong>Ag\u2082C\u2082O\u2084<\/strong> \u2013 Silver oxalate<\/li>\n<\/ol>\n\n\n\n<h3 class=\"wp-block-heading\">Formula for the Given Ionic Compound:<\/h3>\n\n\n\n<ol start=\"11\" class=\"wp-block-list\">\n<li><strong>Vanadium(III) fluoride<\/strong> \u2013 <strong>VF\u2083<\/strong><\/li>\n<\/ol>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation <\/h3>\n\n\n\n<p>Ionic compounds consist of positive ions (cations) and negative ions (anions) held together by electrostatic forces. Their names are determined by identifying the ions involved and applying specific nomenclature rules.<\/p>\n\n\n\n<p>For compounds involving metals with a fixed charge, like <strong>barium<\/strong>, <strong>calcium<\/strong>, and <strong>potassium<\/strong>, naming is straightforward. For example, <strong>BaCrO\u2084<\/strong> is named <em>barium chromate<\/em> because barium forms only a +2 ion and chromate is a known polyatomic ion (CrO\u2084\u00b2\u207b).<\/p>\n\n\n\n<p>Transition metals like <strong>copper<\/strong>, <strong>chromium<\/strong>, <strong>antimony<\/strong>, and <strong>vanadium<\/strong> can exhibit multiple oxidation states. In such cases, Roman numerals indicate the metal\u2019s oxidation state. For instance, <strong>CuC\u2082H\u2083O\u2082<\/strong> involves copper in the +1 state, requiring the name <em>copper(I) acetate<\/em>. In <strong>CuCO\u2083<\/strong>, copper has a +2 charge, making it <em>copper(II) carbonate<\/em>.<\/p>\n\n\n\n<p>Polyatomic ions like <strong>hydroxide (OH\u207b)<\/strong>, <strong>nitrate\/nitrite (NO\u2083\u207b\/NO\u2082\u207b)<\/strong>, <strong>phosphate (PO\u2084\u00b3\u207b)<\/strong>, <strong>sulfite (SO\u2083\u00b2\u207b)<\/strong>, <strong>acetate (C\u2082H\u2083O\u2082\u207b)<\/strong>, <strong>chlorate (ClO\u2083\u207b)<\/strong>, and <strong>oxalate (C\u2082O\u2084\u00b2\u207b)<\/strong> retain their standard names when used in compounds. The ammonium ion (NH\u2084\u207a), a common polyatomic cation, appears in compounds like <strong>(NH\u2084)\u2083PO\u2084<\/strong> (<em>ammonium phosphate<\/em>).<\/p>\n\n\n\n<p>In naming compounds such as <strong>Sb(ClO\u2083)\u2083<\/strong>, antimony exhibits a +3 charge to balance three chlorate ions, resulting in the name <em>antimony(III) chlorate<\/em>.<\/p>\n\n\n\n<p>To write a formula like <strong>vanadium(III) fluoride<\/strong>, determine the ion charges: vanadium(III) is V\u00b3\u207a, and fluoride is F\u207b. Three fluoride ions are needed to balance one V\u00b3\u207a ion, producing the formula <strong>VF\u2083<\/strong>. Proper balancing ensures overall charge neutrality in the compound.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner5-536.jpeg\" alt=\"\" class=\"wp-image-235101\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Name the following ionic compounds. 1. BaCrO4 2. Ca(OH)2 3. KNO2 4. (NH4)3PO4 5. CuC2H3O2 6. (NH4)2SO3 7. Sb(ClO3)3 8. CrF3 9. CuCO3 10. Ag2C2O4 Write the formula for the following ionic comp 11. vanadium (III) fluoride The Correct Answer and Explanation is: Names of the Ionic Compounds: Formula for the Given Ionic Compound: Explanation [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-235100","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/235100","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=235100"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/235100\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=235100"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=235100"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=235100"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}