{"id":235188,"date":"2025-06-15T03:04:44","date_gmt":"2025-06-15T03:04:44","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=235188"},"modified":"2025-06-15T03:04:46","modified_gmt":"2025-06-15T03:04:46","slug":"electronic-structure","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/15\/electronic-structure\/","title":{"rendered":"ELECTRONIC STRUCTURE"},"content":{"rendered":"\n

ELECTRONIC STRUCTURE: Drawing a box diagram of the electron configuration of an atom Draw the electron configuration for a neutral atom of phosphorus. Energy: Explore: Check<\/p>\n\n\n\n

\"\"<\/figure>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

To draw the box diagram (orbital diagram) for a neutral atom of phosphorus (P)<\/strong>, follow its atomic number<\/strong>, which is 15<\/strong>. This means phosphorus has 15 electrons<\/strong>.<\/p>\n\n\n\n

Electron Configuration:<\/h3>\n\n\n\n

The electron configuration for phosphorus is:<\/p>\n\n\n\n

1s\u00b2 2s\u00b2 2p\u2076 3s\u00b2 3p\u00b3<\/strong><\/p>\n\n\n\n

This shows how electrons are distributed among the orbitals.<\/p>\n\n\n\n

Box (Orbital) Diagram:<\/h3>\n\n\n\n

Each box represents an orbital<\/strong>, and each arrow represents an electron<\/strong>. Arrows pointing up and down indicate paired electrons<\/strong> with opposite spins. Orbitals fill in order of increasing energy:
1s \u2192 2s \u2192 2p \u2192 3s \u2192 3p<\/p>\n\n\n\n

Here\u2019s the correct orbital (box) diagram:<\/p>\n\n\n\n

CopyEdit1s    2s    2p        3s    3p\n\u2191\u2193    \u2191\u2193   \u2191\u2193\u2191\u2193\u2191\u2193     \u2191\u2193   \u2191 \u2191 \u2191\n<\/code><\/pre>\n\n\n\n
    \n
  • 1s<\/strong> and 2s<\/strong> each hold 2 electrons<\/strong> (\u2191\u2193)<\/li>\n\n\n\n
  • 2p<\/strong> has 6 electrons<\/strong> (\u2191\u2193 \u2191\u2193 \u2191\u2193)<\/li>\n\n\n\n
  • 3s<\/strong> holds 2 electrons<\/strong> (\u2191\u2193)<\/li>\n\n\n\n
  • 3p<\/strong> has 3 electrons<\/strong>, so one arrow goes in each of the three 3p orbitals (\u2191 \u2191 \u2191), unpaired<\/strong> and same spin<\/strong> due to Hund\u2019s Rule<\/strong><\/li>\n<\/ul>\n\n\n\n
    Explanation <\/h3>\n\n\n\n
    Phosphorus has an atomic number of 15, meaning it contains 15 protons and, in a neutral atom, 15 electrons. The arrangement of these electrons follows the principles of quantum mechanics: Aufbau Principle<\/strong>, Pauli Exclusion Principle<\/strong>, and Hund\u2019s Rule<\/strong>.<\/p>\n\n\n\n
    The Aufbau Principle states that electrons occupy the lowest energy orbitals first<\/strong>. Starting from 1s, orbitals are filled in a specific order based on energy levels. After 1s and 2s are filled, electrons go into the 2p orbitals, then 3s, and finally 3p.<\/p>\n\n\n\n
    The Pauli Exclusion Principle specifies that an orbital can hold a maximum of two electrons with opposite spins<\/strong>. This is represented in box diagrams as one up arrow (\u2191) and one down arrow (\u2193) per box when both electrons occupy the same orbital.<\/p>\n\n\n\n
    Hund\u2019s Rule plays a key role in orbitals like 2p and 3p that contain multiple degenerate (equal energy) orbitals. It states that electrons will fill empty orbitals singly before pairing up<\/strong>. Therefore, in the 3p sublevel of phosphorus, three electrons will each occupy separate orbitals, and all will have parallel spins (same direction arrows), which is more stable.<\/p>\n\n\n\n
    The result is a clearly structured diagram showing how electrons occupy orbitals based on energy, spin, and sublevel capacity. This diagram helps visualize how phosphorus achieves a stable ground-state electron configuration and plays a vital role in predicting its chemical behavior.<\/p>\n\n\n\n
    \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"
    ELECTRONIC STRUCTURE: Drawing a box diagram of the electron configuration of an atom Draw the electron configuration for a neutral atom of phosphorus. Energy: Explore: Check The Correct Answer and Explanation is: To draw the box diagram (orbital diagram) for a neutral atom of phosphorus (P), follow its atomic number, which is 15. This means […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-235188","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/235188","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=235188"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/235188\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=235188"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=235188"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=235188"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}