{"id":235505,"date":"2025-06-15T12:32:28","date_gmt":"2025-06-15T12:32:28","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=235505"},"modified":"2025-06-15T12:32:30","modified_gmt":"2025-06-15T12:32:30","slug":"entropy-and-free-energy-qualitatively-predicting-reaction-entropy-note-fo-nced-students","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/15\/entropy-and-free-energy-qualitatively-predicting-reaction-entropy-note-fo-nced-students\/","title":{"rendered":"ENTROPY AND FREE ENERGY Qualitatively predicting reaction entropy Note fo nced students"},"content":{"rendered":"\n<p>ENTROPY AND FREE ENERGY Qualitatively predicting reaction entropy Note fo nced students: Assume the temperature remains constant: Assume all g= reaction sign of reaction entropy As rxn colg) + 2Hz (g) CH,OH (g) not enough information_ ASrxn ASrn 250,(g) 250,( (g) + 02 (g) not enough information_ 4s rxn *4,so,() K,o() H,o&#8217; (a9) HSO4 (aq) 4s Txn not enough Information ASrxn<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Correct Answers:<\/h3>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>CO(g) + 2H\u2082(g) \u2192 CH\u2083OH(g)<\/strong><br>\u2714 <strong>\u0394S\u1d63\u2093\u2099 &lt; 0<\/strong><\/li>\n\n\n\n<li><strong>2SO\u2083(g) \u2192 2SO\u2082(g) + O\u2082(g)<\/strong><br>\u2714 <strong>\u0394S\u1d63\u2093\u2099 > 0<\/strong><\/li>\n\n\n\n<li><strong>H\u2082SO\u2084(l) + H\u2082O(l) \u2192 H\u2083O\u207a(aq) + HSO\u2084\u207b(aq)<\/strong><br>\u2714 <strong>\u0394S\u1d63\u2093\u2099 > 0<\/strong><\/li>\n<\/ol>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p><strong>Entropy (S)<\/strong> is a measure of disorder or randomness in a system. In chemical reactions, entropy changes (\u0394S\u1d63\u2093\u2099) can be predicted qualitatively based on the <strong>physical states<\/strong> and <strong>number of particles<\/strong> involved.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>1. CO(g) + 2H\u2082(g) \u2192 CH\u2083OH(g)<\/strong><br>This reaction goes from <strong>3 moles of gas<\/strong> (1 CO + 2 H\u2082) to <strong>1 mole of gas<\/strong> (CH\u2083OH). The number of gas particles decreases, resulting in a <strong>decrease in entropy<\/strong>. Gases have high entropy, and fewer gas particles mean lower disorder.<\/p>\n\n\n\n<p>\u2714 <strong>\u0394S\u1d63\u2093\u2099 &lt; 0<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>2. 2SO\u2083(g) \u2192 2SO\u2082(g) + O\u2082(g)<\/strong><br>This process results in <strong>more gas particles<\/strong>: 2 reactant gas molecules become <strong>3 product gas molecules<\/strong> (2 SO\u2082 + 1 O\u2082). The increase in gas molecules means greater randomness and <strong>increased entropy<\/strong>.<\/p>\n\n\n\n<p>\u2714 <strong>\u0394S\u1d63\u2093\u2099 &gt; 0<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>3. H\u2082SO\u2084(l) + H\u2082O(l) \u2192 H\u2083O\u207a(aq) + HSO\u2084\u207b(aq)<\/strong><br>This reaction occurs in the <strong>aqueous phase<\/strong>, producing <strong>ions<\/strong> in solution. The creation of <strong>charged, mobile particles<\/strong> increases disorder, as ions are more disordered than pure liquids. Hence, the entropy <strong>increases<\/strong>.<\/p>\n\n\n\n<p>\u2714 <strong>\u0394S\u1d63\u2093\u2099 &gt; 0<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p>In summary, changes in the number of gas molecules and the production of ions help predict whether entropy increases or decreases. More gas particles or dissolved ions typically signal an increase in entropy.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-586.jpeg\" alt=\"\" class=\"wp-image-235506\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>ENTROPY AND FREE ENERGY Qualitatively predicting reaction entropy Note fo nced students: Assume the temperature remains constant: Assume all g= reaction sign of reaction entropy As rxn colg) + 2Hz (g) CH,OH (g) not enough information_ ASrxn ASrn 250,(g) 250,( (g) + 02 (g) not enough information_ 4s rxn *4,so,() K,o() H,o&#8217; (a9) HSO4 (aq) [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-235505","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/235505","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=235505"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/235505\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=235505"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=235505"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=235505"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}