{"id":235743,"date":"2025-06-15T17:44:29","date_gmt":"2025-06-15T17:44:29","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=235743"},"modified":"2025-06-15T17:44:38","modified_gmt":"2025-06-15T17:44:38","slug":"for-acetaldehyde-ch3cho-write-the-lewis-structure","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/15\/for-acetaldehyde-ch3cho-write-the-lewis-structure\/","title":{"rendered":"For acetaldehyde (CH3CHO), write the Lewis structure."},"content":{"rendered":"\n<pre id=\"preorder-ask-header-text\" class=\"wp-block-preformatted\">For acetaldehyde (CH3CHO), write the Lewis structure. Write the hybridization and geometry of each carbon. Draw its 3D structure and write the bond angles (approximately).<\/pre>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p><strong>Correct Answer:<\/strong><\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Lewis Structure of Acetaldehyde (CH\u2083CHO):<\/strong><\/li>\n<\/ol>\n\n\n\n<pre class=\"wp-block-preformatted\">mathematicaCopyEdit<code>   H   H\n   |   |\nH\u2013C\u2013C=O\n       |\n       H\n<\/code><\/pre>\n\n\n\n<p>Expanded:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Carbon 1 (CH\u2083): forms 3 single bonds with hydrogen and 1 single bond with the adjacent carbon.<\/li>\n\n\n\n<li>Carbon 2 (C=O): forms 1 single bond with CH\u2083, 1 double bond with oxygen, and 1 single bond with hydrogen.<\/li>\n<\/ul>\n\n\n\n<ol start=\"2\" class=\"wp-block-list\">\n<li><strong>Hybridization and Geometry:<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Carbon 1 (CH\u2083 group)<\/strong>: sp\u00b3 hybridized; <strong>geometry<\/strong> is <strong>tetrahedral<\/strong>.<\/li>\n\n\n\n<li><strong>Carbon 2 (carbonyl carbon)<\/strong>: sp\u00b2 hybridized; <strong>geometry<\/strong> is <strong>trigonal planar<\/strong>.<\/li>\n<\/ul>\n\n\n\n<ol start=\"3\" class=\"wp-block-list\">\n<li><strong>Bond Angles:<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Around <strong>CH\u2083 carbon (sp\u00b3)<\/strong>: approximately <strong>109.5\u00b0<\/strong>.<\/li>\n\n\n\n<li>Around <strong>carbonyl carbon (sp\u00b2)<\/strong>: approximately <strong>120\u00b0<\/strong>.<\/li>\n<\/ul>\n\n\n\n<ol start=\"4\" class=\"wp-block-list\">\n<li><strong>3D Structure (Description):<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The <strong>methyl group (CH\u2083)<\/strong> is tetrahedral with hydrogens positioned to minimize repulsion.<\/li>\n\n\n\n<li>The <strong>carbonyl carbon (C=O)<\/strong> lies in a trigonal planar arrangement with the double bond to oxygen and single bonds to the methyl group and hydrogen, forming roughly 120\u00b0 angles.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong> Explanation:<\/strong><\/p>\n\n\n\n<p>Acetaldehyde (CH\u2083CHO) is a simple aldehyde composed of two carbon atoms, four hydrogen atoms, and one oxygen atom. The molecule features a carbonyl group (C=O) bonded to a methyl group (CH\u2083) and a hydrogen atom.<\/p>\n\n\n\n<p>The Lewis structure is constructed by placing the atoms in their typical bonding patterns. The methyl carbon forms three single bonds with hydrogen atoms and one single bond with the adjacent carbon, requiring a total of four sigma bonds. This carbon uses <strong>sp\u00b3 hybrid orbitals<\/strong>, resulting in a <strong>tetrahedral<\/strong> geometry with bond angles near <strong>109.5\u00b0<\/strong>.<\/p>\n\n\n\n<p>The carbon of the carbonyl group forms a double bond with oxygen, a single bond with the methyl carbon, and a single bond with a hydrogen atom. This atom uses <strong>sp\u00b2 hybridization<\/strong>, generating three electron domains arranged in a <strong>trigonal planar<\/strong> geometry. Bond angles around this carbon are approximately <strong>120\u00b0<\/strong>.<\/p>\n\n\n\n<p>The oxygen atom in the carbonyl group holds two lone pairs and forms a double bond with carbon. This results in a bent electron arrangement but a linear bonding shape relative to the carbon.<\/p>\n\n\n\n<p>The 3D shape shows the CH\u2083 group with a tetrahedral arrangement of hydrogen atoms, while the carbonyl group lies flat in a plane. These geometries are dictated by electron repulsion principles described in VSEPR theory.<\/p>\n\n\n\n<p>This configuration gives acetaldehyde its characteristic planar region around the carbonyl and a pyramidal CH\u2083 group, allowing it to participate in various chemical reactions, particularly as an electrophile due to the polarized carbonyl group.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner6-205.jpeg\" alt=\"\" class=\"wp-image-235745\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>For acetaldehyde (CH3CHO), write the Lewis structure. Write the hybridization and geometry of each carbon. Draw its 3D structure and write the bond angles (approximately). The Correct Answer and Explanation is: Correct Answer: mathematicaCopyEdit H H | | H\u2013C\u2013C=O | H Expanded: Explanation: Acetaldehyde (CH\u2083CHO) is a simple aldehyde composed of two carbon atoms, four [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-235743","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/235743","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=235743"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/235743\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=235743"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=235743"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=235743"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}