{"id":235944,"date":"2025-06-15T21:33:36","date_gmt":"2025-06-15T21:33:36","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=235944"},"modified":"2025-06-15T21:33:38","modified_gmt":"2025-06-15T21:33:38","slug":"write-the-balanced-molecular-equation-for-the-neutralization-reaction-between-hi-and-baoh2-in-aqueous-solution-2","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/15\/write-the-balanced-molecular-equation-for-the-neutralization-reaction-between-hi-and-baoh2-in-aqueous-solution-2\/","title":{"rendered":"Write the balanced molecular equation for the neutralization reaction between HI and Ba(OH)2 in aqueous solution."},"content":{"rendered":"\n<pre id=\"preorder-ask-header-text\" class=\"wp-block-preformatted\">Write the balanced molecular equation for the neutralization reaction between HI and Ba(OH)2 in aqueous solution. Include physical states.<\/pre>\n\n\n\n<p class=\"wp-block-paragraph\"><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Balanced Molecular Equation:<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">2HI(aq)+Ba(OH)2(aq)\u2192BaI2(aq)+2H2O(l)2HI(aq) + Ba(OH)_2(aq) \\rightarrow BaI_2(aq) + 2H_2O(l)2HI(aq)+Ba(OH)2\u200b(aq)\u2192BaI2\u200b(aq)+2H2\u200bO(l)<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Explanation (300 words, without using the word &#8220;we&#8221;):<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">The reaction between hydroiodic acid (HI) and barium hydroxide Ba(OH)2\\text{Ba(OH)}_2Ba(OH)2\u200b represents a typical acid-base neutralization. Hydroiodic acid is a strong acid that completely dissociates in aqueous solution into hydrogen ions (H\u207a) and iodide ions (I\u207b). Barium hydroxide is a strong base that also dissociates fully in water to release barium ions (Ba\u00b2\u207a) and hydroxide ions (OH\u207b).<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">In a neutralization process, hydrogen ions from the acid react with hydroxide ions from the base to form water, a neutral and stable product. The number of H\u207a ions must be balanced with the number of OH\u207b ions to ensure complete neutralization. Each molecule of barium hydroxide provides two hydroxide ions, while each molecule of hydroiodic acid provides one hydrogen ion. Therefore, two moles of HI are required to neutralize one mole of Ba(OH)\u2082.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">The reaction produces barium iodide (BaI\u2082) as a salt. Barium iodide is soluble in water and remains in the aqueous phase as dissociated Ba\u00b2\u207a and I\u207b ions. The reaction also forms two molecules of water as a result of the combination of two H\u207a and two OH\u207b ions.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">The physical states are included to show the nature of each substance during the reaction. Both HI and Ba(OH)\u2082 are aqueous, indicating they are dissolved in water. The product BaI\u2082 is also aqueous, confirming its solubility, and water is produced as a liquid.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Neutralization reactions such as this are fundamental in acid-base chemistry. They are commonly used in laboratory titrations to determine the concentration of unknown acid or base solutions. The predictable formation of water and a salt makes these reactions essential for various industrial and chemical applications.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner10-135.jpeg\" alt=\"\" class=\"wp-image-235945\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Write the balanced molecular equation for the neutralization reaction between HI and Ba(OH)2 in aqueous solution. Include physical states. The Correct Answer and Explanation is: Balanced Molecular Equation: 2HI(aq)+Ba(OH)2(aq)\u2192BaI2(aq)+2H2O(l)2HI(aq) + Ba(OH)_2(aq) \\rightarrow BaI_2(aq) + 2H_2O(l)2HI(aq)+Ba(OH)2\u200b(aq)\u2192BaI2\u200b(aq)+2H2\u200bO(l) Explanation (300 words, without using the word &#8220;we&#8221;): The reaction between hydroiodic acid (HI) and barium hydroxide Ba(OH)2\\text{Ba(OH)}_2Ba(OH)2\u200b represents a [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-235944","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/235944","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=235944"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/235944\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=235944"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=235944"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=235944"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}