{"id":236134,"date":"2025-06-16T05:12:55","date_gmt":"2025-06-16T05:12:55","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=236134"},"modified":"2025-06-16T05:12:57","modified_gmt":"2025-06-16T05:12:57","slug":"in-the-carbon-skeleton-structure-below-identify-the-carbon-atoms-with-sp2-hybridization-2","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/16\/in-the-carbon-skeleton-structure-below-identify-the-carbon-atoms-with-sp2-hybridization-2\/","title":{"rendered":"In the carbon skeleton structure below, identify the carbon atom(s) with sp2 hybridization."},"content":{"rendered":"\n<p>In the carbon skeleton structure below, identify the carbon atom(s) with sp2 hybridization. 4th attempt Jd See Periodic Table See Hint TIP: Select each sp2 hybridized carbon: Selected atoms will be highlighted in green<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>To determine which carbon atoms in a carbon skeleton are <strong>sp\u00b2 hybridized<\/strong>, focus on those that form <strong>double bonds<\/strong> or are part of <strong>planar trigonal arrangements<\/strong>, such as <strong>carbonyl groups<\/strong> or <strong>aromatic rings<\/strong>. An sp\u00b2 hybridized carbon forms <strong>three sigma bonds<\/strong> and <strong>one unhybridized p orbital<\/strong> that participates in <strong>pi bonding<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Correct Identification:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Carbon atoms involved in a double bond (C=C)<\/strong>.<\/li>\n\n\n\n<li><strong>Carbon atoms in benzene rings (aromatic)<\/strong>.<\/li>\n\n\n\n<li><strong>Carbon atoms bonded to oxygen in carbonyl groups (C=O)<\/strong>.<\/li>\n<\/ul>\n\n\n\n<p>These carbon atoms have <strong>trigonal planar geometry<\/strong>, with bond angles close to <strong>120 degrees<\/strong>. In contrast:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>sp\u00b3 hybridized carbon atoms<\/strong> form four sigma bonds and exhibit <strong>tetrahedral geometry<\/strong>.<\/li>\n\n\n\n<li><strong>sp hybridized carbon atoms<\/strong> form two sigma bonds and two pi bonds, usually found in <strong>triple bonds<\/strong> or <strong>linear arrangements<\/strong>.<\/li>\n<\/ul>\n\n\n\n<p>If the image provided a structure like <strong>ethene (C\u2082H\u2084)<\/strong>, the two central carbon atoms are <strong>sp\u00b2 hybridized<\/strong> due to the <strong>double bond<\/strong>. In <strong>benzene (C\u2086H\u2086)<\/strong>, all six carbon atoms are sp\u00b2 hybridized due to the delocalized pi system. In molecules with <strong>aldehyde or ketone groups<\/strong>, the carbonyl carbon is sp\u00b2 hybridized.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Example:<\/h3>\n\n\n\n<p>For a compound such as <strong>propene (CH\u2083\u2013CH=CH\u2082)<\/strong>:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The second carbon (C\u2082), which is double-bonded to another carbon, is <strong>sp\u00b2 hybridized<\/strong>.<\/li>\n\n\n\n<li>The third carbon (C\u2083), which is also part of the double bond, is <strong>sp\u00b2 hybridized<\/strong>.<\/li>\n\n\n\n<li>The first carbon (C\u2081), part of the methyl group (CH\u2083), is <strong>sp\u00b3 hybridized<\/strong>.<\/li>\n<\/ul>\n\n\n\n<p>Understanding electron domain geometry and recognizing bond types allows accurate identification of hybridization states. The sp\u00b2 hybridization enables the formation of planar structures, critical in determining molecular shape and reactivity.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner5-648.jpeg\" alt=\"\" class=\"wp-image-236135\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>In the carbon skeleton structure below, identify the carbon atom(s) with sp2 hybridization. 4th attempt Jd See Periodic Table See Hint TIP: Select each sp2 hybridized carbon: Selected atoms will be highlighted in green The Correct Answer and Explanation is: To determine which carbon atoms in a carbon skeleton are sp\u00b2 hybridized, focus on those [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-236134","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/236134","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=236134"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/236134\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=236134"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=236134"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=236134"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}