{"id":236776,"date":"2025-06-16T13:51:49","date_gmt":"2025-06-16T13:51:49","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=236776"},"modified":"2025-06-16T13:51:52","modified_gmt":"2025-06-16T13:51:52","slug":"draw-the-remaining-product-of-the-reaction","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/16\/draw-the-remaining-product-of-the-reaction\/","title":{"rendered":"Draw the remaining product of the reaction"},"content":{"rendered":"\n<pre id=\"preorder-ask-header-text\" class=\"wp-block-preformatted\">Draw the remaining product of the reaction: Modify the molecule so that it represents the product. You may need to add or remove bonds, atoms, charges. Select Draw Rings More Erase + H2O = OH + H3O- H2C H2C OH 9<\/pre>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/image-587.png\" alt=\"\" class=\"wp-image-236777\"\/><\/figure>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-0-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>In this reaction, water (H\u2082O) acts as a reagent, interacting with the molecule to yield hydroxide (OH\u207b) and hydronium (H\u2083O\u207a). The molecular structure provided includes a benzene ring with a hydroxyl (-OH) and methyl (-CH\u2083) group attached. The task requires adjusting the bonds, atoms, or charges to reflect the final product.<\/p>\n\n\n\n<p><strong>Reaction Explanation:<\/strong> The presence of water implies a possible acid-base interaction. The hydroxyl (-OH) group on the benzene ring can undergo protonation or deprotonation depending on the reaction conditions. In aqueous environments, if a strong acid is present, the hydroxyl group may gain a proton, leading to the formation of hydronium ion (H\u2083O\u207a). Conversely, if a base is involved, deprotonation may occur, forming hydroxide (OH\u207b).<\/p>\n\n\n\n<p>Considering the reaction context, the product involves a modified version of the original molecule. Water molecules facilitate proton transfer, influencing the charge distribution on the oxygen atom. The hydroxyl group transitions into a positively charged oxonium (-OH\u207a), while the surrounding system balances the charge through H\u2083O\u207a formation.<\/p>\n\n\n\n<p><strong>Structural Adjustments:<\/strong><\/p>\n\n\n\n<ol start=\"1\" class=\"wp-block-list\">\n<li>Maintain the benzene ring backbone.<\/li>\n\n\n\n<li>Retain the methyl (-CH\u2083) group attachment.<\/li>\n\n\n\n<li>Modify the hydroxyl (-OH) group to represent the protonated state (-OH\u207a).<\/li>\n\n\n\n<li>Account for the formation of H\u2083O\u207a as the complementary species in solution.<\/li>\n<\/ol>\n\n\n\n<p>The overall transformation involves adjusting the charge on oxygen while ensuring the hydronium ion (H\u2083O\u207a) forms in equilibrium with the molecular system. This reflects the reaction&#8217;s proton transfer dynamics. The finalized molecule consists of a benzene ring with methyl (-CH\u2083) and a positively charged hydroxyl (-OH\u207a) group, balancing the charge distribution with H\u2083O\u207a in solution.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-727.jpeg\" alt=\"\" class=\"wp-image-236778\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Draw the remaining product of the reaction: Modify the molecule so that it represents the product. You may need to add or remove bonds, atoms, charges. Select Draw Rings More Erase + H2O = OH + H3O- H2C H2C OH 9 The Correct Answer and Explanation is: In this reaction, water (H\u2082O) acts as a [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-236776","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/236776","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=236776"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/236776\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=236776"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=236776"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=236776"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}