{"id":237225,"date":"2025-06-17T05:02:20","date_gmt":"2025-06-17T05:02:20","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=237225"},"modified":"2025-06-17T05:02:22","modified_gmt":"2025-06-17T05:02:22","slug":"illud-u-what-is-the-mass-in-grams-of-13-2-amu","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/17\/illud-u-what-is-the-mass-in-grams-of-13-2-amu\/","title":{"rendered":"ILLUD U What is the mass in grams of 13.2 amu"},"content":{"rendered":"\n<p>ILLUD U What is the mass in grams of 13.2 amu<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-0-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>To determine the mass in grams of <strong>13.2 moles<\/strong> of <strong>illudium (symbol: U)<\/strong>, you need to use the <strong>molar mass<\/strong> of uranium.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step-by-step solution:<\/h3>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Know the molar mass of uranium (U):<\/strong><br>Uranium has a molar mass of approximately <strong>238.03 g\/mol<\/strong>.<\/li>\n\n\n\n<li><strong>Use the formula:<\/strong> Mass\u00a0(g)=Moles\u00d7Molar\u00a0Mass\u00a0(g\/mol)\\text{Mass (g)} = \\text{Moles} \\times \\text{Molar Mass (g\/mol)}Mass\u00a0(g)=Moles\u00d7Molar\u00a0Mass\u00a0(g\/mol)<\/li>\n\n\n\n<li><strong>Substitute the values:<\/strong> Mass=13.2\u2009mol\u00d7238.03\u2009g\/mol\\text{Mass} = 13.2 \\, \\text{mol} \\times 238.03 \\, \\text{g\/mol}Mass=13.2mol\u00d7238.03g\/mol<\/li>\n\n\n\n<li><strong>Calculate the mass:<\/strong> Mass=3149.996\u2009g\\text{Mass} = 3149.996 \\, \\text{g}Mass=3149.996g<\/li>\n\n\n\n<li><strong>Round appropriately:<\/strong> Mass\u22483150\u2009grams\\text{Mass} \\approx \\boxed{3150 \\, \\text{grams}}Mass\u22483150grams\u200b<\/li>\n<\/ol>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation<\/h3>\n\n\n\n<p>To calculate the mass in grams of a given number of moles, you must understand the relationship between <strong>moles<\/strong>, <strong>molar mass<\/strong>, and <strong>grams<\/strong>. This relationship is central to stoichiometry in chemistry and allows scientists to convert between the number of particles and measurable quantities like grams.<\/p>\n\n\n\n<p>The mole is a standard scientific unit used to measure large quantities of very small entities such as atoms or molecules. One mole of any element contains approximately 6.022\u00d710236.022 \\times 10^{23}6.022\u00d71023 particles, known as Avogadro\u2019s number. The molar mass is the mass of one mole of a substance and is numerically equal to the element\u2019s atomic mass in grams.<\/p>\n\n\n\n<p>Uranium (U) has a molar mass of about 238.03 grams per mole. This means one mole of uranium weighs 238.03 grams. If you have 13.2 moles of uranium, you simply multiply the number of moles by the molar mass to get the total mass.<\/p>\n\n\n\n<p>By multiplying 13.2 moles by 238.03 grams per mole, the result is approximately 3150 grams. This calculation allows chemists and technicians to measure out specific quantities of substances needed for reactions or other purposes. It ensures accuracy in experiments and in industrial applications where precise amounts of materials are essential. Understanding this concept is fundamental for anyone studying chemistry or working in any field that involves chemical processes.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner5-681.jpeg\" alt=\"\" class=\"wp-image-237226\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>ILLUD U What is the mass in grams of 13.2 amu The Correct Answer and Explanation is: To determine the mass in grams of 13.2 moles of illudium (symbol: U), you need to use the molar mass of uranium. Step-by-step solution: Explanation To calculate the mass in grams of a given number of moles, you [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-237225","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/237225","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=237225"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/237225\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=237225"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=237225"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=237225"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}