{"id":237567,"date":"2025-06-17T10:22:03","date_gmt":"2025-06-17T10:22:03","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=237567"},"modified":"2025-06-17T10:22:05","modified_gmt":"2025-06-17T10:22:05","slug":"ir-spectrum-of-benzyl-alcohol-starting-material","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/17\/ir-spectrum-of-benzyl-alcohol-starting-material\/","title":{"rendered":"IR spectrum of benzyl alcohol (starting material)"},"content":{"rendered":"\n<p>IR spectrum of benzyl alcohol (starting material) HIT-NO-1125 SCORE- ( ) SDBS-NO-685 IR-NIDA-05226 : LIQUID FILM BENZYL ALCOHOL<br>TRANSHETTANCE 100 50 0 4000 3000 2000 1500 1000 500 WAVENUMBER(1-1) IR spectrum of benzoic acid (product material) HIT-NO-1101 SCORE- ( ) SDBS-NO-673 IR-NIDA-07134 : CCL4 SOLUTION BENZOIC ACID<br>TRANSHETTANCE 100 50 0 4000 3000 2000 1500 1000 500 WAVENUMBER(1-1) Because benzoic acid is a solid product, this IR spectrum has been made by dissolving some compound in a solvent (CCl<br>). The resulting spectrum shows a C-Cl signal. Make sure label this C-Cl signal.<br>SOC2211 Organic Chemistry Experiment 5: Preparation of Benzoic Acid IR spectrum of benzyl alcohol (starting material) HIT-NO-1125 SCORE- ( ) SDBS-NO-685 IR-NIDA-05226 : LIQUID FILM BENZYL ALCOHOL<br>TRANSHETTANCE 100 50 0 4000 3000 2000 1500 1000 500 WAVENUMBER(1-1) IR spectrum of benzoic acid (product material) HIT-NO-1101 SCORE- ( ) SDBS-NO-673 IR-NIDA-07134 : CCL4 SOLUTION BENZOIC ACID<br>TRANSHETTANCE 100 50 0 4000 3000 2000 1500 1000 500 WAVENUMBER(1-1) Because benzoic acid is a solid product, this IR spectrum has been made by dissolving some compound in a solvent (CCl<br>). The resulting spectrum shows a C-Cl signal. Make sure label this C-Cl signal.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/image-647.png\" alt=\"\" class=\"wp-image-237568\"\/><\/figure>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The infrared (IR) spectra provided show the transition from benzyl alcohol to benzoic acid. The spectral features of benzyl alcohol include a broad O-H stretching vibration between 3200 and 3600 cm\u207b\u00b9, which is characteristic of hydroxyl functional groups. Additionally, the C-H stretching vibrations in the range of 2800 to 3100 cm\u207b\u00b9 indicate the presence of alkyl and aromatic components. The C-O stretching signal appears near 1050 to 1250 cm\u207b\u00b9, which is typical for alcohols.<\/p>\n\n\n\n<p>In the IR spectrum of benzoic acid, the most significant change is the disappearance of the O-H signal associated with alcohols and the emergence of a strong and broad O-H stretching vibration due to carboxylic acid between 2500 and 3500 cm\u207b\u00b9. The presence of a sharp and intense C=O stretching vibration near 1700 cm\u207b\u00b9 confirms the formation of the carboxyl functional group. Additionally, the C-O stretching modes appear around 1250 cm\u207b\u00b9, contributing to the identification of carboxylic acid functionality. Since benzoic acid was dissolved in carbon tetrachloride (CCl\u2084) for this analysis, the resulting spectrum includes a C-Cl stretching band, typically found between 600 and 800 cm\u207b\u00b9.<\/p>\n\n\n\n<p>The transformation from benzyl alcohol to benzoic acid is an oxidation process where the primary alcohol is converted into a carboxylic acid. This conversion introduces a distinct shift in spectral features, particularly the disappearance of alcohol-related peaks and the appearance of strong carboxyl absorptions. The IR spectrum is a valuable tool in verifying this transformation, as the key differences indicate the successful oxidation of benzyl alcohol to benzoic acid. Correctly labeling the C-Cl signal is necessary to differentiate solvent contributions from the actual structural features of the product.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-870.jpeg\" alt=\"\" class=\"wp-image-237569\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>IR spectrum of benzyl alcohol (starting material) HIT-NO-1125 SCORE- ( ) SDBS-NO-685 IR-NIDA-05226 : LIQUID FILM BENZYL ALCOHOLTRANSHETTANCE 100 50 0 4000 3000 2000 1500 1000 500 WAVENUMBER(1-1) IR spectrum of benzoic acid (product material) HIT-NO-1101 SCORE- ( ) SDBS-NO-673 IR-NIDA-07134 : CCL4 SOLUTION BENZOIC ACIDTRANSHETTANCE 100 50 0 4000 3000 2000 1500 1000 500 [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-237567","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/237567","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=237567"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/237567\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=237567"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=237567"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=237567"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}