{"id":237685,"date":"2025-06-17T12:10:15","date_gmt":"2025-06-17T12:10:15","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=237685"},"modified":"2025-06-17T12:10:17","modified_gmt":"2025-06-17T12:10:17","slug":"suppose-that-the-central-diffraction-maximum-for-two-slits-contains-17-interference-fringes-for-some-wavelength-of-light","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/17\/suppose-that-the-central-diffraction-maximum-for-two-slits-contains-17-interference-fringes-for-some-wavelength-of-light\/","title":{"rendered":"&#8216;Suppose that the central diffraction maximum for two slits contains 17 interference fringes for some wavelength of light"},"content":{"rendered":"\n<p>&#8216;Suppose that the central diffraction maximum for two slits contains 17 interference fringes for some wavelength of light: How many interference fringes would you expect in the first secondary diffraction maximum?&#8217;<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p><strong>Correct Answer: 16 interference fringes<\/strong><\/p>\n\n\n\n<p><strong>Explanation:<\/strong><\/p>\n\n\n\n<p>To solve this, we need to understand the interaction between <strong>diffraction<\/strong> and <strong>interference<\/strong> in a <strong>double-slit experiment<\/strong>.<\/p>\n\n\n\n<p>In a typical double-slit setup, the light passes through two slits and spreads out, creating two overlapping patterns:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Diffraction pattern<\/strong> due to each slit acting like a single aperture<\/li>\n\n\n\n<li><strong>Interference pattern<\/strong> due to the interaction between light waves from the two slits<\/li>\n<\/ol>\n\n\n\n<p>The central diffraction maximum is the broad central band formed due to the diffraction of light through the slits. Within this broad envelope, several <strong>interference fringes<\/strong> are observed as a result of constructive and destructive interference.<\/p>\n\n\n\n<p>We are told that <strong>17 interference fringes<\/strong> fit <strong>within the central diffraction maximum<\/strong>. This number includes the central bright fringe and 8 fringes on each side (symmetrically located). These interference fringes occur within the <strong>first diffraction minimum<\/strong> on either side of the central maximum.<\/p>\n\n\n\n<p>Now, we are asked to determine how many interference fringes fall within the <strong>first secondary diffraction maximum<\/strong>, which is the region between the <strong>first and second diffraction minima<\/strong>.<\/p>\n\n\n\n<p>The number of interference fringes between two successive diffraction minima is generally <strong>one less<\/strong> than the number in the central diffraction maximum. This is because the width of the diffraction envelope determines how many bright interference bands are allowed in each region.<\/p>\n\n\n\n<p>Since <strong>17 fringes<\/strong> are observed within the central diffraction maximum, <strong>each side of the central maximum<\/strong> has 8 fringes. In the next diffraction region (the first secondary maximum), the intensity is lower and narrower, and it allows <strong>only 16 fringes<\/strong> (8 on each side minus the central one, which only exists in the central maximum).<\/p>\n\n\n\n<p>Therefore, we expect <strong>16 interference fringes<\/strong> in the <strong>first secondary diffraction maximum<\/strong> \u2014 8 on each side of the new central point within that region.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-899.jpeg\" alt=\"\" class=\"wp-image-237686\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>&#8216;Suppose that the central diffraction maximum for two slits contains 17 interference fringes for some wavelength of light: How many interference fringes would you expect in the first secondary diffraction maximum?&#8217; The Correct Answer and Explanation is: Correct Answer: 16 interference fringes Explanation: To solve this, we need to understand the interaction between diffraction and [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center 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