{"id":237799,"date":"2025-06-17T15:32:48","date_gmt":"2025-06-17T15:32:48","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=237799"},"modified":"2025-06-17T15:32:50","modified_gmt":"2025-06-17T15:32:50","slug":"what-ir-peaks-are-present-in-3-nitroacetophenone","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/17\/what-ir-peaks-are-present-in-3-nitroacetophenone\/","title":{"rendered":"What IR peaks are present in 3-nitroacetophenone"},"content":{"rendered":"\n<p>What IR peaks are present in 3-nitroacetophenone?<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p><strong>Answer:<\/strong><br>The infrared (IR) spectrum of <strong>3-nitroacetophenone<\/strong> shows the following characteristic absorption peaks:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>C=O (carbonyl stretch)<\/strong>: Around <strong>1680\u20131700 cm\u207b\u00b9<\/strong><\/li>\n\n\n\n<li><strong>NO\u2082 group asymmetric stretch<\/strong>: Around <strong>1520\u20131550 cm\u207b\u00b9<\/strong><\/li>\n\n\n\n<li><strong>NO\u2082 group symmetric stretch<\/strong>: Around <strong>1340\u20131370 cm\u207b\u00b9<\/strong><\/li>\n\n\n\n<li><strong>Aromatic C=C stretches<\/strong>: Around <strong>1450\u20131600 cm\u207b\u00b9<\/strong><\/li>\n\n\n\n<li><strong>Aromatic C\u2013H stretching<\/strong>: Around <strong>3000\u20133100 cm\u207b\u00b9<\/strong><\/li>\n\n\n\n<li><strong>C\u2013H bending (methyl)<\/strong>: Around <strong>1375 cm\u207b\u00b9 and 1450 cm\u207b\u00b9<\/strong><\/li>\n\n\n\n<li><strong>C\u2013C stretching (aromatic ring)<\/strong>: Around <strong>1100\u20131300 cm\u207b\u00b9<\/strong><\/li>\n<\/ol>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>Explanation<\/strong><br>Infrared (IR) spectroscopy is used to identify functional groups in molecules based on their vibrational transitions. In the case of <strong>3-nitroacetophenone<\/strong>, the structure consists of a benzene ring substituted with a nitro group (\u2013NO\u2082) at the meta position and an acetyl group (\u2013COCH\u2083) at the para position relative to hydrogen.<\/p>\n\n\n\n<p>One of the most prominent peaks is from the <strong>carbonyl (C=O)<\/strong> stretching of the acetyl group, typically appearing sharply between <strong>1680 and 1700 cm\u207b\u00b9<\/strong>. This peak is strong due to the highly polar nature of the C=O bond.<\/p>\n\n\n\n<p>The <strong>nitro group<\/strong> contributes two distinctive peaks:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The <strong>asymmetric stretch<\/strong> occurs around <strong>1520\u20131550 cm\u207b\u00b9<\/strong><\/li>\n\n\n\n<li>The <strong>symmetric stretch<\/strong> is observed near <strong>1340\u20131370 cm\u207b\u00b9<\/strong><br>These are useful markers for identifying nitro-substituted aromatic compounds.<\/li>\n<\/ul>\n\n\n\n<p>The <strong>aromatic ring<\/strong> shows <strong>C=C stretching vibrations<\/strong> in the region of <strong>1450\u20131600 cm\u207b\u00b9<\/strong>. These peaks vary slightly in position and intensity depending on the substitution pattern on the ring.<\/p>\n\n\n\n<p>The <strong>C\u2013H stretches<\/strong> of aromatic hydrogens appear above <strong>3000 cm\u207b\u00b9<\/strong>, typically between <strong>3000 and 3100 cm\u207b\u00b9<\/strong>. In contrast, the <strong>methyl (\u2013CH\u2083) group<\/strong> from the acetyl moiety shows <strong>C\u2013H bending<\/strong> around <strong>1375 and 1450 cm\u207b\u00b9<\/strong>.<\/p>\n\n\n\n<p>Finally, there may be some fingerprint region bands below <strong>1300 cm\u207b\u00b9<\/strong> due to <strong>C\u2013C<\/strong> and <strong>C\u2013H<\/strong> bending modes, especially from the substituted aromatic ring, contributing to a complex pattern in the IR spectrum.<\/p>\n\n\n\n<p>Together, these peaks confirm the presence of ketone, nitro, aromatic, and methyl groups in 3-nitroacetophenone.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner10-249.jpeg\" alt=\"\" class=\"wp-image-237800\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>What IR peaks are present in 3-nitroacetophenone? The Correct Answer and Explanation is: Answer:The infrared (IR) spectrum of 3-nitroacetophenone shows the following characteristic absorption peaks: ExplanationInfrared (IR) spectroscopy is used to identify functional groups in molecules based on their vibrational transitions. In the case of 3-nitroacetophenone, the structure consists of a benzene ring substituted with [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-237799","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/237799","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=237799"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/237799\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=237799"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=237799"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=237799"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}