{"id":237907,"date":"2025-06-17T18:02:20","date_gmt":"2025-06-17T18:02:20","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=237907"},"modified":"2025-06-17T18:02:23","modified_gmt":"2025-06-17T18:02:23","slug":"find-the-sum-of-following-fraction-4-12-2017-25","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/17\/find-the-sum-of-following-fraction-4-12-2017-25\/","title":{"rendered":"find the sum of following fraction 4 12\/20+17\/25"},"content":{"rendered":"\n

find the sum of following fraction 4 12\/20+17\/25<\/p>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

To find the sum of the fractions 41220+17254\\frac{12}{20} + \\frac{17}{25}42012\u200b+2517\u200b, we first convert the mixed number to an improper fraction, then add the two fractions.<\/p>\n\n\n\n

Step 1: Convert the mixed number to an improper fraction<\/h3>\n\n\n\n

41220=4\u00d720+1220=80+1220=92204\\frac{12}{20} = \\frac{4 \\times 20 + 12}{20} = \\frac{80 + 12}{20} = \\frac{92}{20}42012\u200b=204\u00d720+12\u200b=2080+12\u200b=2092\u200b<\/p>\n\n\n\n

Step 2: Find a common denominator for the fractions<\/h3>\n\n\n\n

We are adding 9220+1725\\frac{92}{20} + \\frac{17}{25}2092\u200b+2517\u200b.
To add fractions, they must have a common denominator. The least common denominator (LCD) of 20 and 25 is 100.<\/p>\n\n\n\n

Convert both fractions to have the same denominator:<\/p>\n\n\n\n

    \n
  • 9220=92\u00d7520\u00d75=460100\\frac{92}{20} = \\frac{92 \\times 5}{20 \\times 5} = \\frac{460}{100}2092\u200b=20\u00d7592\u00d75\u200b=100460\u200b<\/li>\n\n\n\n
  • 1725=17\u00d7425\u00d74=68100\\frac{17}{25} = \\frac{17 \\times 4}{25 \\times 4} = \\frac{68}{100}2517\u200b=25\u00d7417\u00d74\u200b=10068\u200b<\/li>\n<\/ul>\n\n\n\n

    Step 3: Add the fractions<\/h3>\n\n\n\n

    460100+68100=460+68100=528100\\frac{460}{100} + \\frac{68}{100} = \\frac{460 + 68}{100} = \\frac{528}{100}100460\u200b+10068\u200b=100460+68\u200b=100528\u200b<\/p>\n\n\n\n

    Step 4: Simplify the result<\/h3>\n\n\n\n

    We simplify 528100\\frac{528}{100}100528\u200b by dividing both numerator and denominator by their greatest common divisor, which is 4:528\u00f74100\u00f74=13225\\frac{528 \\div 4}{100 \\div 4} = \\frac{132}{25}100\u00f74528\u00f74\u200b=25132\u200b<\/p>\n\n\n\n

    Now convert 13225\\frac{132}{25}25132\u200b back to a mixed number:132 \\div 25 = 5\\) remainder \\(7\\), so \\[ \\frac{132}{25} = 5\\frac{7}{25}<\/p>\n\n\n\n

    Final Answer:<\/h3>\n\n\n\n

    41220+1725=57254\\frac{12}{20} + \\frac{17}{25} = 5\\frac{7}{25}42012\u200b+2517\u200b=5257\u200b<\/p>\n\n\n\n

    \n\n\n\n

    Explanation (300 words):<\/h3>\n\n\n\n

    To add the mixed number 412204\\frac{12}{20}42012\u200b and the fraction 1725\\frac{17}{25}2517\u200b, we follow a clear sequence of steps. First, we convert the mixed number to an improper fraction. A mixed number combines a whole number and a fraction, so we rewrite it using a single fraction. The denominator of the fraction part is 20. Multiplying the whole number 4 by 20 gives 80. Adding the numerator 12 gives 92. So 412204\\frac{12}{20}42012\u200b becomes 9220\\frac{92}{20}2092\u200b.<\/p>\n\n\n\n

    Next, we must add 9220+1725\\frac{92}{20} + \\frac{17}{25}2092\u200b+2517\u200b. To do this, we need a common denominator. The lowest common denominator of 20 and 25 is 100. We convert both fractions to have 100 as the denominator. Multiply both numerator and denominator of 9220\\frac{92}{20}2092\u200b by 5 to get 460100\\frac{460}{100}100460\u200b. Multiply both numerator and denominator of 1725\\frac{17}{25}2517\u200b by 4 to get 68100\\frac{68}{100}10068\u200b. Now both fractions have the same denominator, so we can add the numerators directly.<\/p>\n\n\n\n

    Adding 460+68460 + 68460+68 gives 528, so the sum is 528100\\frac{528}{100}100528\u200b. To simplify, we divide the numerator and denominator by 4. This results in 13225\\frac{132}{25}25132\u200b. Finally, we convert this improper fraction to a mixed number. Since 25 fits into 132 five times with a remainder of 7, the final answer is 57255\\frac{7}{25}5257\u200b. This represents the exact sum of the original expression.<\/p>\n\n\n\n

    \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

    find the sum of following fraction 4 12\/20+17\/25 The Correct Answer and Explanation is: To find the sum of the fractions 41220+17254\\frac{12}{20} + \\frac{17}{25}42012\u200b+2517\u200b, we first convert the mixed number to an improper fraction, then add the two fractions. Step 1: Convert the mixed number to an improper fraction 41220=4\u00d720+1220=80+1220=92204\\frac{12}{20} = \\frac{4 \\times 20 + […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-237907","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/237907","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=237907"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/237907\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=237907"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=237907"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=237907"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}