{"id":238044,"date":"2025-06-17T19:43:23","date_gmt":"2025-06-17T19:43:23","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=238044"},"modified":"2025-06-17T19:43:24","modified_gmt":"2025-06-17T19:43:24","slug":"a-pi-r2-3-14-times-6m-times-6m","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/17\/a-pi-r2-3-14-times-6m-times-6m\/","title":{"rendered":"A = \\pi r^2 = 3.14 \\times 6m \\times 6m"},"content":{"rendered":"\n

A = \\pi r^2 = 3.14 \\times 6m \\times 6m = 3.14 \\times 36m^2 = 113.04 m^2<\/p>\n\n\n\n

\"\"<\/figure>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

Correct Calculation:<\/h3>\n\n\n\n

The area of a circle is given by the formula:<\/p>\n\n\n\n

A=\u03c0r2A = \\pi r^2<\/p>\n\n\n\n

Substituting \u03c0=3.14\\pi = 3.14 and r=6mr = 6m:<\/p>\n\n\n\n

A=3.14\u00d7(6m\u00d76m)A = 3.14 \\times (6m \\times 6m)<\/p>\n\n\n\n

A=3.14\u00d736m2A = 3.14 \\times 36m^2<\/p>\n\n\n\n

A=113.04m2A = 113.04m^2<\/p>\n\n\n\n

Thus, the correct answer remains 113.04 square meters<\/strong>.<\/p>\n\n\n\n

Explanation:<\/h3>\n\n\n\n

The formula for the area of a circle, A=\u03c0r2A = \\pi r^2, is derived from the geometric properties of circles. The term \u03c0\\pi represents the mathematical constant approximated as 3.14, and r2r^2 denotes the square of the radius. Squaring the radius ensures that the measurement reflects the entire circular region rather than just a linear distance.<\/p>\n\n\n\n

In this case, the given radius is 6 meters. Applying the formula, we substitute the values accordingly. The first step involves squaring the radius, which means multiplying 6m6m by itself. This results in 36m236m^2. Next, multiplying 3.143.14 by 36m236m^2 yields 113.04m2113.04m^2. This final value represents the total area enclosed within the circle\u2019s boundary.<\/p>\n\n\n\n

The significance of this computation lies in practical applications such as land measurement, engineering design, and physics problems involving circular components. Understanding how to calculate the area of a circle aids in determining surface coverage for materials like flooring, painting, and pipe cross-sections. Additionally, circular area calculations play a role in optimizing space efficiency in manufacturing and architecture.<\/p>\n\n\n\n

\"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

A = \\pi r^2 = 3.14 \\times 6m \\times 6m = 3.14 \\times 36m^2 = 113.04 m^2 The Correct Answer and Explanation is: Correct Calculation: The area of a circle is given by the formula: A=\u03c0r2A = \\pi r^2 Substituting \u03c0=3.14\\pi = 3.14 and r=6mr = 6m: A=3.14\u00d7(6m\u00d76m)A = 3.14 \\times (6m \\times 6m) A=3.14\u00d736m2A […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-238044","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/238044","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=238044"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/238044\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=238044"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=238044"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=238044"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}