{"id":238299,"date":"2025-06-18T04:14:37","date_gmt":"2025-06-18T04:14:37","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=238299"},"modified":"2025-06-18T04:14:39","modified_gmt":"2025-06-18T04:14:39","slug":"show-how-to-draw-lewis-dot-structures-for-the-balanced-reaction-of-the-combustion-of-methane-ch4","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/18\/show-how-to-draw-lewis-dot-structures-for-the-balanced-reaction-of-the-combustion-of-methane-ch4\/","title":{"rendered":"Show how to draw Lewis dot structures for the balanced reaction of the combustion of methane (CH4)."},"content":{"rendered":"\n<p>Show how to draw Lewis dot structures for the balanced reaction of the combustion of methane (CH4). Show how to draw the Lewis dot structures for the balanced reaction of the combustion of ethanol (C2H5OH). Show how to draw Lewis dot structures for the balanced reaction of the combustion of hydrogen (H2).<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Lewis Dot Structures for Combustion Reactions<\/h3>\n\n\n\n<p><strong>1. Combustion of Methane (CH\u2084)<\/strong><br><strong>Balanced equation:<\/strong><br>CH\u2084 + 2O\u2082 \u2192 CO\u2082 + 2H\u2082O<\/p>\n\n\n\n<p><strong>Lewis Structures:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>CH\u2084<\/strong> (Methane):<br>Carbon is in the center with 4 hydrogen atoms single bonded around it. markdownCopyEdit<code> H | H - C - H | H<\/code><\/li>\n\n\n\n<li><strong>O\u2082<\/strong> (Oxygen gas):<br>Each O shares two electrons (double bond) iniCopyEdit<code>O = O<\/code><\/li>\n\n\n\n<li><strong>CO\u2082<\/strong> (Carbon dioxide):<br>Carbon is double bonded to each oxygen atom mathematicaCopyEdit<code>O = C = O<\/code><\/li>\n\n\n\n<li><strong>H\u2082O<\/strong> (Water):<br>Oxygen in center with 2 single bonds to hydrogen, and two lone pairs on O markdownCopyEdit<code> H - O - H .. ..<\/code><\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>2. Combustion of Ethanol (C\u2082H\u2085OH)<\/strong><br><strong>Balanced equation:<\/strong><br>C\u2082H\u2085OH + 3O\u2082 \u2192 2CO\u2082 + 3H\u2082O<\/p>\n\n\n\n<p><strong>Lewis Structures:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>C\u2082H\u2085OH (Ethanol):<\/strong><br>CH\u2083\u2212CH\u2082\u2212OH, carbon atoms bonded to H and OH mathematicaCopyEdit<code>H H H H | | | | H - C - C - O - H | H<\/code><\/li>\n\n\n\n<li><strong>O\u2082:<\/strong> iniCopyEdit<code>O = O<\/code><\/li>\n\n\n\n<li><strong>CO\u2082:<\/strong> mathematicaCopyEdit<code>O = C = O<\/code><\/li>\n\n\n\n<li><strong>H\u2082O:<\/strong> markdownCopyEdit<code> H - O - H .. ..<\/code><\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>3. Combustion of Hydrogen (H\u2082)<\/strong><br><strong>Balanced equation:<\/strong><br>2H\u2082 + O\u2082 \u2192 2H\u2082O<\/p>\n\n\n\n<p><strong>Lewis Structures:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>H\u2082 (Hydrogen gas):<\/strong> nginxCopyEdit<code>H \u2212 H<\/code><\/li>\n\n\n\n<li><strong>O\u2082 (Oxygen gas):<\/strong> iniCopyEdit<code>O = O<\/code><\/li>\n\n\n\n<li><strong>H\u2082O (Water):<\/strong> markdownCopyEdit<code> H - O - H .. ..<\/code><\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation (300 words)<\/h3>\n\n\n\n<p>Lewis dot structures represent the valence electrons in molecules and help visualize how atoms bond during chemical reactions. In combustion reactions, a hydrocarbon (or hydrogen gas) reacts with oxygen gas to form carbon dioxide and water. Each atom must follow the octet rule (or duet for hydrogen), meaning it should achieve a full outer shell through bonding.<\/p>\n\n\n\n<p>In the combustion of methane (CH\u2084), the carbon atom forms four single bonds with hydrogen atoms. Oxygen gas (O\u2082) consists of two oxygen atoms sharing a double bond. In the reaction, CH\u2084 and O\u2082 rearrange to form CO\u2082 and H\u2082O. Carbon in CO\u2082 forms two double bonds with oxygen, fulfilling the octet rule. Water has two single bonds between oxygen and hydrogen, and oxygen retains two lone pairs.<\/p>\n\n\n\n<p>In ethanol (C\u2082H\u2085OH), the molecule includes a hydroxyl group (OH) bonded to a carbon chain. Each carbon obeys the octet rule, and each hydrogen has a single bond. During combustion, the ethanol reacts with three oxygen molecules to yield two carbon dioxide molecules and three water molecules. The electrons rearrange such that carbon atoms form double bonds with oxygen in CO\u2082, and oxygen in water maintains its two lone pairs.<\/p>\n\n\n\n<p>Hydrogen gas (H\u2082) is a simple diatomic molecule with a single bond between two hydrogen atoms. Oxygen again exists as a diatomic molecule with a double bond. When H\u2082 combusts, it reacts with O\u2082 to produce H\u2082O. Each water molecule contains two hydrogen atoms bonded to one oxygen atom, which also has two lone pairs.<\/p>\n\n\n\n<p>These Lewis structures help us visualize electron movement and confirm that each atom satisfies bonding rules. They provide essential insight into how atoms rearrange during chemical reactions.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner5-703.jpeg\" alt=\"\" class=\"wp-image-238300\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Show how to draw Lewis dot structures for the balanced reaction of the combustion of methane (CH4). Show how to draw the Lewis dot structures for the balanced reaction of the combustion of ethanol (C2H5OH). Show how to draw Lewis dot structures for the balanced reaction of the combustion of hydrogen (H2). The Correct Answer [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-238299","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/238299","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=238299"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/238299\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=238299"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=238299"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=238299"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}