{"id":238439,"date":"2025-06-18T05:56:24","date_gmt":"2025-06-18T05:56:24","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=238439"},"modified":"2025-06-18T05:56:26","modified_gmt":"2025-06-18T05:56:26","slug":"what-is-the-formula-mass-of-strontium-phosphate","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/18\/what-is-the-formula-mass-of-strontium-phosphate\/","title":{"rendered":"What is the formula mass of strontium phosphate"},"content":{"rendered":"\n<p>What is the formula mass of strontium phosphate? Show your calculation. 357.83 amu b_ 421.83 amu 182.59 amu d. 715.66 amu 452.80 amu<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>To find the <strong>formula mass of strontium phosphate, Sr\u2083(PO\u2084)\u2082<\/strong>, follow these steps:<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 1: Identify the elements and number of atoms<\/h3>\n\n\n\n<p>The chemical formula <strong>Sr\u2083(PO\u2084)\u2082<\/strong> means:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Sr (Strontium):<\/strong> 3 atoms<\/li>\n\n\n\n<li><strong>P (Phosphorus):<\/strong> 2 atoms (because (PO\u2084)\u2082 means 2 phosphate groups)<\/li>\n\n\n\n<li><strong>O (Oxygen):<\/strong> 8 atoms (4 from each phosphate group \u00d7 2 = 8)<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step 2: Use the atomic masses from the periodic table<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Sr (Strontium):<\/strong> 87.62 amu<\/li>\n\n\n\n<li><strong>P (Phosphorus):<\/strong> 30.97 amu<\/li>\n\n\n\n<li><strong>O (Oxygen):<\/strong> 16.00 amu<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step 3: Multiply and add<\/h3>\n\n\n\n<p><strong>Mass of 3 Sr atoms:<\/strong>3\u00d787.62=262.86&nbsp;amu3 \u00d7 87.62 = 262.86\\ \\text{amu}3\u00d787.62=262.86&nbsp;amu<\/p>\n\n\n\n<p><strong>Mass of 2 P atoms:<\/strong>2\u00d730.97=61.94&nbsp;amu2 \u00d7 30.97 = 61.94\\ \\text{amu}2\u00d730.97=61.94&nbsp;amu<\/p>\n\n\n\n<p><strong>Mass of 8 O atoms:<\/strong>8\u00d716.00=128.00&nbsp;amu8 \u00d7 16.00 = 128.00\\ \\text{amu}8\u00d716.00=128.00&nbsp;amu<\/p>\n\n\n\n<p><strong>Total formula mass:<\/strong>262.86+61.94+128.00=452.80&nbsp;amu262.86 + 61.94 + 128.00 = \\boxed{452.80\\ \\text{amu}}262.86+61.94+128.00=452.80&nbsp;amu\u200b<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Final Answer:<\/h3>\n\n\n\n<p><strong>Correct choice: e. 452.80 amu<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation <\/h3>\n\n\n\n<p>The formula mass of a compound is the sum of the atomic masses of all atoms in its formula unit. It represents the mass of one formula unit of an ionic compound in atomic mass units (amu). Strontium phosphate, <strong>Sr\u2083(PO\u2084)\u2082<\/strong>, is an ionic compound made of strontium ions and phosphate ions.<\/p>\n\n\n\n<p>We start by analyzing the chemical formula. The subscript <strong>3<\/strong> next to Sr shows there are three strontium atoms. The (PO\u2084)\u2082 tells us that there are two phosphate groups. Each phosphate group contains one phosphorus atom and four oxygen atoms, so two groups contribute <strong>2 phosphorus atoms<\/strong> and <strong>8 oxygen atoms<\/strong>.<\/p>\n\n\n\n<p>Next, we refer to the periodic table for the atomic masses: strontium is approximately 87.62 amu, phosphorus is 30.97 amu, and oxygen is 16.00 amu. We multiply the atomic mass of each element by the number of atoms in the compound. After calculating each contribution separately, we add them together to get the total formula mass.<\/p>\n\n\n\n<p>This calculation gives us:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Strontium: 262.86 amu<\/li>\n\n\n\n<li>Phosphorus: 61.94 amu<\/li>\n\n\n\n<li>Oxygen: 128.00 amu<\/li>\n<\/ul>\n\n\n\n<p>Adding these yields a total formula mass of <strong>452.80 amu<\/strong>.<\/p>\n\n\n\n<p>This value matches option <strong>e<\/strong>, making it the correct answer. This mass tells us how much one formula unit of Sr\u2083(PO\u2084)\u2082 weighs in atomic mass units and is essential for converting between moles and grams in chemistry calculations.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner5-737.jpeg\" alt=\"\" class=\"wp-image-238440\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>What is the formula mass of strontium phosphate? Show your calculation. 357.83 amu b_ 421.83 amu 182.59 amu d. 715.66 amu 452.80 amu The Correct Answer and Explanation is: To find the formula mass of strontium phosphate, Sr\u2083(PO\u2084)\u2082, follow these steps: Step 1: Identify the elements and number of atoms The chemical formula Sr\u2083(PO\u2084)\u2082 means: [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-238439","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/238439","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=238439"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/238439\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=238439"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=238439"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=238439"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}