{"id":239036,"date":"2025-06-18T15:03:51","date_gmt":"2025-06-18T15:03:51","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=239036"},"modified":"2025-06-18T15:03:53","modified_gmt":"2025-06-18T15:03:53","slug":"which-of-the-following-structures-represents-4-methylcyclohexanol","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/18\/which-of-the-following-structures-represents-4-methylcyclohexanol\/","title":{"rendered":"Which of the following structures represents 4-methylcyclohexanol"},"content":{"rendered":"\n<p>Which of the following structures represents 4-methylcyclohexanol? H3C OH H3C CH3 H3C OH CH3<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p><strong>Correct Answer: The correct structure of 4-methylcyclohexanol is:<\/strong><\/p>\n\n\n\n<p>A <strong>cyclohexane ring<\/strong> with a <strong>hydroxyl group (OH)<\/strong> attached to <strong>carbon 1<\/strong> and a <strong>methyl group (CH\u2083)<\/strong> attached to <strong>carbon 4<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation:<\/strong><\/h3>\n\n\n\n<p>To determine the correct structure of <strong>4-methylcyclohexanol<\/strong>, you must understand both the <strong>numbering of the cyclohexane ring<\/strong> and the <strong>placement of substituents<\/strong> on that ring.<\/p>\n\n\n\n<h4 class=\"wp-block-heading\">1. <strong>Base structure: Cyclohexanol<\/strong><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Cyclohexanol is a six-carbon ring (cyclohexane) with one <strong>hydroxyl group (-OH)<\/strong> attached.<\/li>\n\n\n\n<li>When numbering the ring, the carbon attached to the OH group is always numbered as <strong>carbon 1<\/strong> because OH has higher priority in IUPAC naming rules.<\/li>\n<\/ul>\n\n\n\n<h4 class=\"wp-block-heading\">2. <strong>Methyl group placement<\/strong><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The \u201c4-methyl\u201d part means there is a <strong>methyl group (CH\u2083)<\/strong> attached to <strong>carbon 4<\/strong> of the ring.<\/li>\n\n\n\n<li>You must number the ring in the direction that gives the next substituent (the methyl group) the <strong>lowest possible number<\/strong> after assigning 1 to the OH group.<\/li>\n<\/ul>\n\n\n\n<h4 class=\"wp-block-heading\">3. <strong>Putting it together<\/strong><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Start with cyclohexane.<\/li>\n\n\n\n<li>Attach an OH group to carbon 1.<\/li>\n\n\n\n<li>Then, counting three carbons away (in either direction), attach a methyl group to carbon 4.<\/li>\n<\/ul>\n\n\n\n<p>So the structure will look like this:<\/p>\n\n\n\n<pre class=\"wp-block-preformatted\">yamlCopyEdit<code>      CH3\n       |\n  C6\u2014C1\u2014C2\n \/        \\\nC5        C3\n \\        \/\n  C4\u2014\u2014\u2014C\n    |\n   OH\n<\/code><\/pre>\n\n\n\n<p>Alternatively, in skeletal or line structure diagrams, the ring will appear as a hexagon. One carbon will have an OH sticking out, and the carbon directly across the ring (carbon 4) will have a CH\u2083 group.<\/p>\n\n\n\n<p>This structure satisfies the name <strong>4-methylcyclohexanol<\/strong>, because it has:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>A six-membered ring (cyclohexane)<\/li>\n\n\n\n<li>An OH on carbon 1<\/li>\n\n\n\n<li>A CH\u2083 on carbon 4<\/li>\n<\/ul>\n\n\n\n<p>None of the choices like \u201cH\u2083C OH H\u2083C CH\u2083\u201d or \u201cH\u2083C OH CH\u2083\u201d accurately depict this unless shown as part of a ring structure. The correct answer must include a ring with these proper attachments.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-1141.jpeg\" alt=\"\" class=\"wp-image-239037\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Which of the following structures represents 4-methylcyclohexanol? H3C OH H3C CH3 H3C OH CH3 The Correct Answer and Explanation is: Correct Answer: The correct structure of 4-methylcyclohexanol is: A cyclohexane ring with a hydroxyl group (OH) attached to carbon 1 and a methyl group (CH\u2083) attached to carbon 4. Explanation: To determine the correct structure [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-239036","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/239036","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=239036"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/239036\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=239036"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=239036"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=239036"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}