{"id":239041,"date":"2025-06-18T15:06:37","date_gmt":"2025-06-18T15:06:37","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=239041"},"modified":"2025-06-18T15:06:40","modified_gmt":"2025-06-18T15:06:40","slug":"what-is-the-expected-product-for-the-following-reaction","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/18\/what-is-the-expected-product-for-the-following-reaction\/","title":{"rendered":"What is the expected product for the following reaction"},"content":{"rendered":"\n<p>What is the expected product for the following reaction? t-BuOK H3C\\nCH3 H3C Br t-BuOH heat The following compound: H3C CH3 CH3 The following compound: H3C CH3 H3C O The following compound: ? H3C CH3 CH3 The following compound: H3C CH3 H3C OH The following compound: H3C CH3<\/p>\n\n\n\n<figure class=\"wp-block-image size-full is-resized\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/image-727.png\" alt=\"\" class=\"wp-image-239042\" style=\"width:959px;height:auto\"\/><\/figure>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The given reaction involves potassium tert-butoxide (t-BuOK), which is a strong and bulky base, along with heat. This setup suggests an elimination reaction, specifically an E2 mechanism.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Expected Product<\/strong><\/h3>\n\n\n\n<p>The correct product for this reaction is <strong>2-methylpropene (isobutene)<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation<\/strong><\/h3>\n\n\n\n<p>This reaction follows an E2 elimination mechanism, which occurs in a single concerted step where the base abstracts a proton from the \u03b2-carbon (carbon adjacent to the carbon bonded to bromine), leading to the formation of a double bond and the departure of bromine as a leaving group.<\/p>\n\n\n\n<ol start=\"1\" class=\"wp-block-list\">\n<li><strong>Base Strength and Bulky Nature<\/strong>\n<ul class=\"wp-block-list\">\n<li>Potassium tert-butoxide is a strong and bulky base, which favors elimination over substitution. It preferentially removes the proton from the most accessible \u03b2-carbon, favoring the formation of a double bond.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Formation of the Alkene<\/strong>\n<ul class=\"wp-block-list\">\n<li>The substrate contains a <strong>tert-butyl bromide functional group<\/strong>. The bulky base abstracts a proton from the carbon adjacent to the bromine. As a result, the bromine leaves, and a <strong>double bond is formed between the two carbons<\/strong>, generating <strong>2-methylpropene<\/strong>.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Regioselectivity and Stability<\/strong>\n<ul class=\"wp-block-list\">\n<li>The most substituted alkene forms preferentially due to <strong>Zaitsev\u2019s Rule<\/strong>, which states that elimination favors the production of the more stable, highly substituted alkene. Since the product contains a <strong>tertiary alkene<\/strong>, it is the most thermodynamically stable configuration.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Reaction Conditions and Favorability<\/strong>\n<ul class=\"wp-block-list\">\n<li>The presence of heat reinforces elimination as the dominant pathway. <strong>E2 reactions occur best under high-temperature conditions, leading to rapid and irreversible formation of the alkene.<\/strong><\/li>\n<\/ul>\n<\/li>\n<\/ol>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Final Product<\/strong><\/h3>\n\n\n\n<p>The resulting compound is <strong>2-methylpropene (H2C=C(CH3)2)<\/strong>, which is the expected product based on the provided reaction conditions.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-1142.jpeg\" alt=\"\" class=\"wp-image-239043\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>What is the expected product for the following reaction? t-BuOK H3C\\nCH3 H3C Br t-BuOH heat The following compound: H3C CH3 CH3 The following compound: H3C CH3 H3C O The following compound: ? H3C CH3 CH3 The following compound: H3C CH3 H3C OH The following compound: H3C CH3 The Correct Answer and Explanation is: The given [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-239041","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/239041","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=239041"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/239041\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=239041"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=239041"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=239041"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}