{"id":239174,"date":"2025-07-02T18:44:14","date_gmt":"2025-07-02T18:44:14","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=239174"},"modified":"2025-07-02T18:44:16","modified_gmt":"2025-07-02T18:44:16","slug":"draw-the-molecular-orbital-diagram-for-the-molecules-of-ethene-ch2ch2-and-ethyne-ch%e2%89%a1ch","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/02\/draw-the-molecular-orbital-diagram-for-the-molecules-of-ethene-ch2ch2-and-ethyne-ch%e2%89%a1ch\/","title":{"rendered":"Draw the molecular orbital diagram for the molecules of ethene (CH2=CH2) and ethyne (CH\u2261CH)"},"content":{"rendered":"\n<p>Draw the molecular orbital diagram for the molecules of ethene (CH2=CH2) and ethyne (CH\u2261CH)<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Molecular Orbital Diagram for Ethene (C\u2082H\u2084) and Ethyne (C\u2082H\u2082)<\/h3>\n\n\n\n<p><strong>Ethene (C\u2082H\u2084)<\/strong>:<br>Ethene is a molecule with a double bond between two carbon atoms. Each carbon in ethene is sp\u00b2 hybridized, and the molecule has a trigonal planar geometry. For the molecular orbital diagram:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Bonding and Antibonding Orbitals<\/strong>: The bonding and antibonding molecular orbitals for ethene come from the overlap of the atomic orbitals from each carbon and hydrogen.\n<ul class=\"wp-block-list\">\n<li>The carbon-carbon sigma (\u03c3) bond arises from the head-on overlap of sp\u00b2 hybrid orbitals.<\/li>\n\n\n\n<li>The \u03c0 bond comes from the sideways overlap of unhybridized p orbitals from the two carbon atoms.<\/li>\n\n\n\n<li>The hydrogen atoms contribute to the bonding orbitals through the overlap of their 1s orbitals with the carbon sp\u00b2 hybrid orbitals.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Orbital Filling<\/strong>:\n<ul class=\"wp-block-list\">\n<li>The \u03c3 and \u03c3* orbitals (for the carbon-carbon bond) are filled first, followed by the \u03c0 bonding and \u03c0* antibonding orbitals.<\/li>\n\n\n\n<li>The electrons fill the molecular orbitals based on the Pauli Exclusion Principle and Hund&#8217;s Rule.<\/li>\n<\/ul>\n<\/li>\n<\/ol>\n\n\n\n<p>In total, the bonding in ethene involves one \u03c3 bond, one \u03c0 bond, and the interactions with the hydrogens contribute to the bonding network.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>Ethyne (C\u2082H\u2082)<\/strong>:<br>Ethyne has a triple bond between two carbon atoms. Each carbon in ethyne is sp hybridized, resulting in a linear geometry. In the molecular orbital diagram:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Bonding and Antibonding Orbitals<\/strong>:\n<ul class=\"wp-block-list\">\n<li>The carbon-carbon sigma (\u03c3) bond comes from the overlap of sp hybrid orbitals.<\/li>\n\n\n\n<li>Two \u03c0 bonds form from the sideways overlap of two p orbitals on each carbon atom.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Orbital Filling<\/strong>:\n<ul class=\"wp-block-list\">\n<li>The \u03c3 bonding and antibonding orbitals fill first, followed by the two \u03c0 bonding and \u03c0* antibonding orbitals.<\/li>\n\n\n\n<li>The two remaining electrons will be placed in the lowest energy \u03c0 molecular orbital.<\/li>\n<\/ul>\n<\/li>\n<\/ol>\n\n\n\n<p>For ethyne, the bonding consists of one \u03c3 bond and two \u03c0 bonds between the carbon atoms, with minimal interaction from the hydrogens.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Ethene (C\u2082H\u2084)<\/strong>: The key feature of ethene&#8217;s bonding is the presence of one \u03c3 bond and one \u03c0 bond between the two carbon atoms. This allows for some flexibility in the bond, as the \u03c0 bond is relatively weak compared to the \u03c3 bond.<\/li>\n\n\n\n<li><strong>Ethyne (C\u2082H\u2082)<\/strong>: In ethyne, the triple bond involves one \u03c3 bond and two \u03c0 bonds, making it much stronger and shorter than ethene. The sp hybridization of the carbon atoms in ethyne results in a more linear molecule compared to the planar geometry of ethene.<\/li>\n<\/ul>\n\n\n\n<p>These diagrams help visualize how the atomic orbitals combine to form molecular orbitals, influencing the properties and stability of the molecules.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner5-4.jpeg\" alt=\"\" class=\"wp-image-239175\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Draw the molecular orbital diagram for the molecules of ethene (CH2=CH2) and ethyne (CH\u2261CH) The Correct Answer and Explanation is: Molecular Orbital Diagram for Ethene (C\u2082H\u2084) and Ethyne (C\u2082H\u2082) Ethene (C\u2082H\u2084):Ethene is a molecule with a double bond between two carbon atoms. Each carbon in ethene is sp\u00b2 hybridized, and the molecule has a trigonal [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-239174","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/239174","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=239174"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/239174\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=239174"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=239174"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=239174"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}