{"id":239471,"date":"2025-07-02T20:50:16","date_gmt":"2025-07-02T20:50:16","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=239471"},"modified":"2025-07-02T20:50:18","modified_gmt":"2025-07-02T20:50:18","slug":"green-plants-use-light-from-the-sun-to-drive-photosynthesis","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/02\/green-plants-use-light-from-the-sun-to-drive-photosynthesis\/","title":{"rendered":"Green plants use light from the Sun to drive photosynthesis."},"content":{"rendered":"\n<p>Green plants use light from the Sun to drive photosynthesis. Photosynthesis is a chemical reaction in which water (<br>) and carbon dioxide (<br>) chemically react to form the simple sugar glucose (<br>) and oxygen gas (<br>). What mass of carbon dioxide is consumed by the reaction of 2.85 g of water? Round your answer to 3 significant digits.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/image-9.png\" alt=\"\" class=\"wp-image-239473\"\/><\/figure>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>Here is a step-by-step solution to the problem:<\/p>\n\n\n\n<p><strong>Step 1: Write and balance the chemical equation for photosynthesis.<\/strong><\/p>\n\n\n\n<p>The problem states that water (H\u2082O) and carbon dioxide (CO\u2082) react to form glucose (C\u2086H\u2081\u2082O\u2086) and oxygen (O\u2082).<\/p>\n\n\n\n<p>The unbalanced equation is:<br>H\u2082O + CO\u2082 \u2192 C\u2086H\u2081\u2082O\u2086 + O\u2082<\/p>\n\n\n\n<p>To balance the equation, we need to ensure there are equal numbers of each type of atom on both sides of the reaction.<\/p>\n\n\n\n<p>The balanced chemical equation is:<br><strong>6H\u2082O + 6CO\u2082 \u2192 C\u2086H\u2081\u2082O\u2086 + 6O\u2082<\/strong><\/p>\n\n\n\n<p>This equation tells us that 6 moles of water react with 6 moles of carbon dioxide to produce 1 mole of glucose and 6 moles of oxygen.<\/p>\n\n\n\n<p><strong>Step 2: Calculate the molar masses of water (H\u2082O) and carbon dioxide (CO\u2082).<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Molar mass of H\u2082O:<\/strong>\n<ul class=\"wp-block-list\">\n<li>Hydrogen (H): 2 \u00d7 1.01\u00a0g\/mol\u00a0= 2.02\u00a0g\/mol<\/li>\n\n\n\n<li>Oxygen (O): 1 \u00d7 16.00\u00a0g\/mol\u00a0= 16.00\u00a0g\/mol<\/li>\n\n\n\n<li>Total = 2.02 + 16.00 =\u00a0<strong>18.02\u00a0g\/mol<\/strong><\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Molar mass of CO\u2082:<\/strong>\n<ul class=\"wp-block-list\">\n<li>Carbon (C): 1 \u00d7 12.01\u00a0g\/mol\u00a0= 12.01\u00a0g\/mol<\/li>\n\n\n\n<li>Oxygen (O): 2 \u00d7 16.00\u00a0g\/mol\u00a0= 32.00\u00a0g\/mol<\/li>\n\n\n\n<li>Total = 12.01 + 32.00 =\u00a0<strong>44.01\u00a0g\/mol<\/strong><\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<p><strong>Step 3: Convert the mass of water to moles.<\/strong><\/p>\n\n\n\n<p>We are given 2.85 g of water. We use its molar mass to find the number of moles.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Moles of H\u2082O = Mass \/ Molar Mass<\/li>\n\n\n\n<li>Moles of H\u2082O = 2.85 g \/ 18.02\u00a0g\/mol\u00a0= 0.158157&#8230; mol<\/li>\n<\/ul>\n\n\n\n<p><strong>Step 4: Use the mole ratio to find the moles of carbon dioxide.<\/strong><\/p>\n\n\n\n<p>From the balanced equation (6H\u2082O + 6CO\u2082 \u2192 &#8230;), the ratio of moles of water to moles of carbon dioxide is 6:6, which simplifies to 1:1. This means for every mole of water that reacts, one mole of carbon dioxide also reacts.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Moles of CO\u2082 = Moles of H\u2082O \u00d7 (6 mol CO\u2082 \/ 6 mol H\u2082O)<\/li>\n\n\n\n<li>Moles of CO\u2082 = 0.158157&#8230; mol H\u2082O \u00d7 1 = 0.158157&#8230; mol CO\u2082<\/li>\n<\/ul>\n\n\n\n<p><strong>Step 5: Convert the moles of carbon dioxide to mass.<\/strong><\/p>\n\n\n\n<p>Now, we convert the moles of CO\u2082 back to mass using its molar mass.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Mass of CO\u2082 = Moles \u00d7 Molar Mass<\/li>\n\n\n\n<li>Mass of CO\u2082 = 0.158157&#8230; mol \u00d7 44.01\u00a0g\/mol\u00a0= 6.96049&#8230; g<\/li>\n<\/ul>\n\n\n\n<p><strong>Step 6: Round to the correct number of significant digits.<\/strong><\/p>\n\n\n\n<p>The initial measurement (2.85 g) has 3 significant digits. Therefore, our final answer must also be rounded to 3 significant digits.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>6.96049&#8230; g rounded to 3 significant digits is\u00a0<strong>6.96 g<\/strong>.<\/li>\n<\/ul>\n\n\n\n<p><strong>Answer:<\/strong><br>The mass of carbon dioxide consumed is\u00a0<strong>6.96 g<\/strong><\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner5-29.jpeg\" alt=\"\" class=\"wp-image-239474\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Green plants use light from the Sun to drive photosynthesis. Photosynthesis is a chemical reaction in which water () and carbon dioxide () chemically react to form the simple sugar glucose () and oxygen gas (). What mass of carbon dioxide is consumed by the reaction of 2.85 g of water? Round your answer to [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-239471","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/239471","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=239471"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/239471\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=239471"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=239471"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=239471"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}