{"id":239912,"date":"2025-07-03T06:04:01","date_gmt":"2025-07-03T06:04:01","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=239912"},"modified":"2025-07-03T06:04:03","modified_gmt":"2025-07-03T06:04:03","slug":"what-is-the-value-of-y-in-the-formula-shown-when-x-4-5","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/07\/03\/what-is-the-value-of-y-in-the-formula-shown-when-x-4-5\/","title":{"rendered":"What is the value of y in the formula shown when x = 4\/5"},"content":{"rendered":"\n

What is the value of y in the formula shown when x = 4\/5? y = 4x + \u221ax + 0.2 – 5x y =<\/p>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

The given formula is:<\/p>\n\n\n\n

y=4x+x+0.2\u22125xy = 4x + \\sqrt{x} + 0.2 – 5xy=4x+x\u200b+0.2\u22125x<\/p>\n\n\n\n

We are asked to find the value of yyy when x=45x = \\frac{4}{5}x=54\u200b.<\/p>\n\n\n\n

Step-by-Step Calculation:<\/h3>\n\n\n\n
    \n
  1. Substitute x=45x = \\frac{4}{5}x=54\u200b into the formula:<\/strong><\/li>\n<\/ol>\n\n\n\n

    y=4(45)+45+0.2\u22125(45)y = 4\\left(\\frac{4}{5}\\right) + \\sqrt{\\frac{4}{5}} + 0.2 – 5\\left(\\frac{4}{5}\\right)y=4(54\u200b)+54\u200b\u200b+0.2\u22125(54\u200b)<\/p>\n\n\n\n

      \n
    1. Simplify each term:<\/strong><\/li>\n<\/ol>\n\n\n\n
        \n
      • First, simplify 4\u00d7454 \\times \\frac{4}{5}4\u00d754\u200b: 4\u00d745=165=3.24 \\times \\frac{4}{5} = \\frac{16}{5} = 3.24\u00d754\u200b=516\u200b=3.2<\/li>\n\n\n\n
      • Next, simplify 45\\sqrt{\\frac{4}{5}}54\u200b\u200b. To calculate the square root, we can express 45\\frac{4}{5}54\u200b as a decimal: 45=0.8\\frac{4}{5} = 0.854\u200b=0.8 Therefore: 0.8\u22480.8944\\sqrt{0.8} \\approx 0.89440.8\u200b\u22480.8944<\/li>\n\n\n\n
      • Then, calculate 5\u00d7455 \\times \\frac{4}{5}5\u00d754\u200b: 5\u00d745=45 \\times \\frac{4}{5} = 45\u00d754\u200b=4<\/li>\n<\/ul>\n\n\n\n
          \n
        1. Substitute these values into the equation:<\/strong><\/li>\n<\/ol>\n\n\n\n

          y=3.2+0.8944+0.2\u22124y = 3.2 + 0.8944 + 0.2 – 4y=3.2+0.8944+0.2\u22124<\/p>\n\n\n\n

            \n
          1. Perform the addition and subtraction:<\/strong><\/li>\n<\/ol>\n\n\n\n
              \n
            • First, add 3.2+0.89443.2 + 0.89443.2+0.8944: 3.2+0.8944=4.09443.2 + 0.8944 = 4.09443.2+0.8944=4.0944<\/li>\n\n\n\n
            • Then, add 0.20.20.2 to the result: 4.0944+0.2=4.29444.0944 + 0.2 = 4.29444.0944+0.2=4.2944<\/li>\n\n\n\n
            • Finally, subtract 4 from the result: 4.2944\u22124=0.29444.2944 – 4 = 0.29444.2944\u22124=0.2944<\/li>\n<\/ul>\n\n\n\n

              Final Answer:<\/h3>\n\n\n\n

              Thus, when x=45x = \\frac{4}{5}x=54\u200b, the value of yyy is approximately 0.2944<\/strong>.<\/p>\n\n\n\n

              \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

              What is the value of y in the formula shown when x = 4\/5? y = 4x + \u221ax + 0.2 – 5x y = The Correct Answer and Explanation is: The given formula is: y=4x+x+0.2\u22125xy = 4x + \\sqrt{x} + 0.2 – 5xy=4x+x\u200b+0.2\u22125x We are asked to find the value of yyy when x=45x […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-239912","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/239912","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=239912"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/239912\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=239912"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=239912"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=239912"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}